Explanation
$$\rho =\rho _{0}(1-\gamma \Delta T)$$
$$\therefore \displaystyle \gamma =\frac{\rho _{0}-\rho }{\rho _{0}\Delta T}=\frac{1000-958.4}{(100)(1000)}$$
$$=4.16\times 10^{-4}(^{\circ}C)^{-1}$$
The density is the mass per unit volume of a substance and that mass of a given quantity of a substance does not change. So when volume changes density changes. Since water contracts form 0°C to 4°C,its volume decreases and the density increases to reach the maximum value at 4°C. When water is cooled from 100°C it contracts till it reaches 4°C; then it expands.
Since water contracts on melting and on heating from 0°C to 4°C
So in both beaker water must rise.
Hint: Absolute temperature is defined as 0K.
Step 1: $$\textbf{Explanation:}$$
We know that absolute temperature is $$0K$$.
So now we will covert this temperature in Kelvin to degree Celsius, we know that $${{T}_{K}}=273+{{T}_{C}}$$ (Where $${{T}_{K}}$$ is temperature in Kelvin and $${{T}_{C}}$$ is temperature in Celsius.)
$$\Rightarrow 0=273+{{T}_{C}}$$
$$\Rightarrow {{T}_{C}}=-273{{C}^{\circ }}$$
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from $$4^0$$C to $$0^0$$C, and it becomes less dense. The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.
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