Explanation
The correct option is $$D.$$
Formula for Gravitational force is:
$$F= \dfrac{G M m}{r^{2}}$$
So, Formula for G will be,
$$G = \dfrac{F r^{2}}{M m}$$
Thus, the dimensional formula for G is,
$$M^{-1}L^{3}T^{-2}$$
$$Angular \ velocity,W=\dfrac{1}{Time}=T^{-1}M^{0}L^{0}$$
$$Impulse=force\timestime=ML^{1}T^{-2}\times T^{1}$$$$=MLT^{-1}$$
The correct option is A.
Every experimental observation value is having some amount of uncertainty associated with it. Significant figures are the number of meaningful digits having certainty. All non – zero digits are significant. Thus in $$6.023 \times 10^{23}$$, we can see $$4$$ significant figures.
$$672.9 \rightarrow 6, 7, 2, 9 \rightarrow$$ 4 significant digits since all non zero digits are significant.$$2.520\times 10^{7} \rightarrow 2, 5, 2, 0 \rightarrow 4$$ significant digits, since all the zero on the right side of last non zero digit in the decimal part are significant.
Work $$=100=M^{1}L^{2}T^{-2}$$
Work $$=power \times time$$
$$\displaystyle time=\frac{work}{power}=T^{1}=\frac{100}{1000}=\frac{1}{10}$$
$$\displaystyle Pressure=\frac{force}{Area}$$
$$=\dfrac{M^{1}L^{1}T^{-2}}{L^{2}}$$
$$=ML^{-1}T^{-2}$$
$$\displaystyle =\frac{1}{2}\times\frac{1}{2}\times \frac{1}{(1)^{2}}\frac{kg}{ms^{2}} $$
$$=\dfrac{1}{4}=0.25 \ pascal$$
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