Explanation
At t =0, the particle was at x = A sin (0 + /6) = A/2.
The particle reaches equilibrium at $$t= t_1$$. Thus $$0 = A sin (wt_1 + /6) or t_1 = -T/12$$. Since time taken cannot be negative, $$t_1 = T/12$$.
Similarly same time will be used to travel from mean position to +A/2. Thus, total time taken is $$2(T/12) = T/6 = \dfrac{\pi} {3w}$$
The correct option is (c)
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