Explanation
Let, Frequency of wave is, $$f = 400 Hz$$ Velocity of wave is, $$v = 320 ms^{-1}$$ The phase difference is, $$\phi = 90^\circ = \dfrac{\pi}{2}$$ The wavelength of wave is, $$\lambda$$ $$\lambda = \dfrac{v}{f}$$ $$\lambda = \dfrac{320}{400}$$ $$\lambda = 0.8 m$$ Now, the phase difference between two particles in a wave is $$\dfrac{\phi}{2\pi}= \dfrac{x}{\lambda}$$ where, x is the distance between two particles in a wave. $$x = \dfrac{\lambda \phi}{2 \pi}$$ $$x = \dfrac{0.8 (\dfrac{\pi}{2})}{2 \pi}$$ $$x = \dfrac{0.8}{4} = 0.2 m$$ $$x = 20 cm$$
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