Explanation
Conserving momentum in X - direction
$$m \times 2.2 = 1.1 \times m \times cos 60 + v\:cos\:\theta \times m$$
$$2.2 = \dfrac{1.1}{2} + v\:cos\:\theta$$
$$ \dfrac{3.3}{2} = v\:cos\:\theta$$........................(1)
Similarly in Y - direction
$$v\:sin\:\theta = 1.1 sin \;60$$
$$v\:sin\:\theta = \dfrac{1.1\sqrt{3}}{2} $$........................(2)
from (1) & (2)
$$v = \sqrt{3.9(1.1)}m/s$$
$$ \theta = 30^{0}$$
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