Explanation
Lets initial velocity of car is v, final velocity of this car will be 5 v
K.E=12 mv2
∴ K.E∝v2
Given that, speed of particle is becoming 3 times of its initial value while moving. ie v′=3v
As we know K.E=12 mv2 ..........(1)
After velocity tripled K.E′=12 m(3v)2=92mv2...........(2)
From equation 1 and 2
K.E′=9×K.E
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