Explanation
Force on particle along the cord = $$mg\cos { \theta }$$
Distance travelled by the particle =$$\quad \dfrac { d }{ \cos { \theta } }$$, where $$d$$ is the diameter or the vertical circle.
$$s = \dfrac { a{ t }^{ 2 } }{ 2 }$$
$$\Rightarrow\ t =\sqrt { \dfrac { 2s }{ a } }$$.
Hence,$$\ t$$ is independent of $$\theta$$.
$$a= g\cos{\theta}\\AB = 2R\cos{\theta}\Rightarrow v^2 =u^2 + 2as \\v^2 = 0 + 2 (g\cos{\theta}) 2R\cos{\theta}\Rightarrow v^2 = 4gR \cos ^{2 }{\theta}\\ \Rightarrow v = 2\sqrt{ gR} \cos{\theta}$$
Kinetic Energy, $$KE=\dfrac{1}{2}mv^{2}$$
(where, $$m=$$ mass of the body and $$v=$$ velocity)
$$KE\propto mv^{2}$$
Kinetic energy can be increased by either increasing mass or velocity.
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