Explanation
It is given that two springs A and B are there.
Work done on first spring $${{W}_{1}}=\dfrac{1}{2}{{K}_{A}}x_{1}^{2}.........(1)$$
Work done on second spring $${{W}_{2}}=\dfrac{1}{2}{{K}_{B}}x_{2}^{2}..........(1)$$
Since, force is same $$F={{K}_{A}}{{x}_{1}}={{K}_{B}}{{x}_{2}}.........(3)$$
Taking ratios of equation (1) and (2)
Coefficient of restitution, $$e$$
$$ e=-\dfrac{relative\,velocity\,of\,seperation}{relative\,velocity\,of\,appproach} $$
$$ e=-\dfrac{4(-\hat{i})-4(+\hat{i})}{4\hat{i}-4(-\hat{i})}=1 $$
Hence, coefficient of restitution is $$1$$
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