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CBSE Questions for Class 11 Medical Biology Photosynthesis In Higher Plants Quiz 13 - MCQExams.com
CBSE
Class 11 Medical Biology
Photosynthesis In Higher Plants
Quiz 13
Select the correct statement regarding the first stable product formed in Hatch and Slack pathway in $$C_4$$ plants.
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Oxalocetate is formed by carboxylation of phosphoenol pyruvate (PEP) in the bundle sheath cells.
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Oxaloacetate is formed by carboxylation of phosphoenol pyruvate (PEP) in the mesophyll cells.
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Phosphoglyceric acid is formed in the mesophyll cells.
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Phosphoglyceric acid is formed in the bundle sheath cells.
Explanation
In $$C_4$$ plants the first stable compound is formed in the mesophyll cells that form a ring around the bundle sheath.$$CO_2$$ here, is first accepted by PhosphoenolPyruvate to form the stable compound OxaloAcetate(OAA), which is then transported to the bundle sheath cells where it is decarboxylated and is fixed through the $$C_3$$ cycle.
So, the correct answer is '
Oxaloacetate is formed by carboxylation of phosphoenol pyruvate (PEP) in the mesophyll cells'
When wheat and sugarcane leaves are fed with radioactive $$^{14} CO_{2}$$ in which would the radioactivity appear first in these plants?
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Wheat-
3-phosphoglycerate;
Sugarcane-
Oxalocetate
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Wheat-
3-phosphoglycerate;
Sugarcane-
3-phosphoglycerate
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Wheat-
Oxaloacetate;
Sugarcane-
Oxalocetate
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Wheat-
Malate;
Sugarcane-
3-phosphoglycerate
Select the incorrect pair.
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2-carbon compound - Aspartic acid
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3-cabon compound- PGA
0%
4- cabon compound-malic acid
0%
5-carbon compound--RuBP
Explanation
Correct Option:
A
Explanation:
The Calvin cycle is additionally known as
dark reactions
or light-independent reactions as a result of it's the part that
doesn't need energy
from the sun to happen.
Both
malic acid
and amino alkanoic acid
(aspartic acid
) are 4- carbon compounds fashioned in the
mesophyll cell
throughout the C4 cycle. Hence, 2 carbon compounds - aspartic acid is incorrect pair.
Which of the following statement is/are correct for photorespiration?
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Glycerate diffuses out of peroxisome and enters chloroplast, here it is phosphorylated
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Glyoxylate is used in the synthesis of glycine in peroxisome
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In mitochondria when glycine is converted into serin at that time glycine first oxidized and later reduced
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Coordinated of chloroplast, peroxisome and mitochondrion is essential in photorespiration
Explanation
During photorespiration, after a series of reaction, synthesis of serine takes place in mitochondria. This serine is taken up by peroxisome and is converted into glycerate. The glycerate then moves from peroxisome to chloroplast, where phosphorylation takes place and it is converted into PGA.
So the correct option is 'Glycerate diffuses out of peroxisome and enters chloroplast, here it is phosphorylated'
Select the correct option:
When $$C_{2}$$ is added to PEP, the first stable product synthesised is
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pyruvate
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glyceraldehyde-3-phosphate
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phosphoglycerate
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oxaloacetate
Explanation
In $$C_{4}$$ plants, initial fixation of $$CO_{2} $$ or carboxylation occurs in mesophyll cells. The chloroplasts of mesophyll cells possess enzyme PEP carboxylase (or PEP case) for initial fixation of $$CO_{2} $$ .The primary acceptor of $$CO_{2} $$ is phosphoenol pyruvate or PEP. It combines with $$CO_{2} $$ in the presence of PEP carboxylase (or PEP case) to form oxaloacetic acid or oxallocetate (OAA). So, the correct answer is '
oxaloacetate'.
The correct sequence of flow of electrons in the light reaction is:
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PSII, plastoquinone, cytochromes, PSI, ferredoxin
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PSI, cytochromes, PSII, ferredoxin, plastoquinone
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PSI, ferredoxin, PSII
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PSI, plastoquinone, cytochromes, PSII, ferredoxin
Explanation
Light reactions occur inside thylakoids. It is dependent upon light. It involves photolysis of water (breaking of water into $$H_{2}$$ and $$O_{2}$$ and production of assimilation power (NADPH and ATP). An electron released during photolysis of water are picked up by $$P_{680}$$ photo center of photosystem II. From here electrons passes over series of carrier which includes PQ, cytochrome b-f complex, and PC. While passing over cytochrome complex, the electron loses sufficient energy for creation of proton gradient and ATP from ADP and inorganic phosphate. From PC electron loses sufficient energy for creation of proton gradient and ATP from ADP and inorganic phosphate. From PC electron is picked by the trap center $$P_{700} $$of photosystem I, which pushes out electron after absorbing light energy. Electron passes over carriers FeS, ferredoxin and NADP reductase which gives an electron to $$NADP^+$$ for combing with $$H^+$$ to produce NADPH.
$$NADP^+ 2e^- + H^{+} \xrightarrow[NADP \,\, reductase]{} NADPH $$
So, the correct answer is '
PSII, plastoquinone, cytochromes, PSI, ferredoxin'.
Which pair is incorrect related to C$$_4$$ pathway?
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Location for primary (first) carboxylation - Mesophyll cells
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First CO$$_2$$ acceptor - PEP
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C$$_4$$ plant - Sugarcane
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First product - PGA
Explanation
In the C$$_4$$ pathway, initial carbon fixation takes place in mesophyll cells and the Calvin cycle takes place in bundle-sheath cells. In this, carbon dioxide attaches to the to the three-carbon molecule PEP in presence of PEP carboxylase and produces the four-carbon molecule oxaloacetate. Examples of C$$_4$$ plants include corn, sugarcane.
Thus, the correct answer is 'First product - PGA.'
Net energy required for producing 1 sucrose in $${ C }_{ 3 }$$ plants
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18 ATP & 12 NADPH
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30 ATP & 12 NADPH
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60 ATP & 24 NADPH
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36 ATP & 24 NADPH
Explanation
For the formation of one glucose molecule, the assimilatory energy required is 18ATP and 12NADPH2. A sucrose molecule is composed with 2 glucose molecule, so the assimilatory energy required for the formation of one sucrose molecule is 36ATP, and 24NADPH2.
So, the correct option is '36ATP and 24NADPH'.
Which of the following is not required for chemiosmotic process?
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Proton gradient
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Spliting of water
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ATP synthase enzyme
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Closed membrane system
Explanation
A. Proton gradient is required because the breakdown of this gradient leads to release of energy.
B. Splitting of water is required which takes place on the inner side of the membrane and the protons that are produced, they accumulate within the lumen of the thyllakoids.
C. ATP synthase enzyme is required that allows diffusion of protons back across the membrane, this releases energy to activate ATPase enzyme which catalyses the formation of ATP.
D. Closed membrane system is not required. Only a membrane is required for the development of a proton gradient across the membrane of the thyllakoid and the proton accumulation is towards the inside of the membrane.
So, the correct answer is 'Closed membrane system'.
Which one of the following is a $${ C }_{ 4 }$$ plant?
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Papaya
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Potato
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Maize
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Pea
Explanation
C3 plants include most of the temperate crops and all the woody trees. Example: beans, rice, wheat, potatoes
C4 plants constitute crops growing in a hot and dry climate. These are mostly grasses and some shrubs. Example: maize, sugarcane, amaranth
So, the correct option is 'Maize'.
To develop proton gradient in respiration the required energy come from the oxidation of
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NADH
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NADH and $${ H }_{ 2 }O$$
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$${ O }_{ 2 }$$ and NADH
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$${ O }_{ 2 }$$
Explanation
The electron transport chain is a series of proteins and organic molecules found in the inner membrane of the mitochondria. Electrons are passed from one member of the transport chain to another in a series of redox reactions. Energy released in these reactions is captured as a proton gradient, which is then used to make ATP in a process called chemiosmosis. Together, the electron transport chain and chemiosmosis make up oxidative phosphorylation.
All of the electrons that enter the transport chain come from NADH and FADH_2
molecules produced during earlier stages of cellular respiration.
NADH is very good at donating electrons in redox reactions so it can transfer its electrons directly to complex I, turning back into $$NAD^+ $$.
FADH_2
is not as good at donating electrons as NADH
so it cannot transfer its electrons to complex I. It feeds them into the transport chain through complex II, which does not pump protons across the membrane.
So the answer is 'NADH'.
Which option is not correct for chemiosmotic theory?
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ATP synthesis is linked with proton gradient
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Break down of proton gradient releases energy
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ATPase enzyme act as pump to break proton gradient
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It is applicable for photo phosphorylation and oxidative phosphorylation
Explanation
There is a proton gradient created across the thylakoid membrane. The breakdown of this gradient is important because it leads to the release of energy. The gradient is broken down due to the movement of protons across the membrane to the stroma through the transmembrane channel ADP ATP of the F0 of the ATPase.
The ATPase enzyme consists of two parts: F0 and F1. This breakdown provides enough energy to cause a conformational change in the F1 particle of the ATPase, which makes the enzyme synthesize ATP.
So, the correct option is 'ATPase enzyme act as a pump to break proton gradient'.
Energy required to develop proton gradient during respiration comes from
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Oxidation process of $$NADH$$
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Oxidation-reduction process of $$CO_2$$ and $$NADH$$ respectively
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From heat energy developed during respiration
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Oxidation-reduction process of $$NADPH$$ and $$O_2$$ respectively
Explanation
When inside the mitochondria, pyruvate and fatty acids are broken down to acetyl CoA, which is then metabolized by the citric acid cycle. During the reaction, NAD$$^{+}$$ is reduced to NADH. In the process of oxidative phosphorylation, high-energy electrons from NADH are passed along the ETC in the inner membrane to O$$_{2}$$. This transport of electrons generates a proton gradient across the mitochondrial inner membrane, which drives the production of ATP by ATP synthase.
So, the correct option is 'Oxidation process of NADH'.
Which cell organelle is not related with photorespiration?
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Mitochondria
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Chloroplast
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Glyoxysome
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Peroxysome
Explanation
Photorespiration is a metabolic pathway involving a complex network of enzyme reactions that exchange metabolites between chloroplasts, leaf peroxisomes, and mitochondria.
So the correct option is 'Glyoxysome'.
The reaction that is responsible for the fixation of $$CO_2$$ is catalyzed by which of the following enzymes in $$C_4$$ plants?
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RuBP carboxylase
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PEP carboxylase
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RuBP carboxylase and PEP carboxylase
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PGA synthase
Explanation
During $$C_4$$ cycle, instead of RuBP carboxylase, a different enzyme, PEP carboxylase, is used to fix CO$$_{2}$$. Carbon is taken up in the mesophyll cells of the leaf (by PEP carboxylase), added to other carbons to form a 4-C chemical called
oxaloacetate
, and the oxaloacetate is pumped into adjacent bundle sheath cells where the rest of the calvin cycle takes place.
So, the correct option is 'PEP carboxylase'.
Which of the following was used in the study of dark reaction of photosynthesis?
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Hydrilla
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Chlorella
and
Scenedesmus
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Chlamydomonas
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Chlorella
and
Spirogyra
Explanation
$$\textbf{Correct Option D}$$
$$\textbf{Solution}$$
$$\bullet$$ The dark reaction of photosynthesis is not dependent on the sunlight and can occur both in the presence as well as absence of Sunlight.
$$\bullet$$
The dark reaction generally occurs in the stroma of the which are the kitchen of the cell.
$$\bullet$$
The reaction is done in three major steps and it is collectively known as the Calvin cycle. The steps are carbon fixation, reduction and regeneration.
$$\bullet$$
Chlorella and spirogyra are used to study the dark reaction of photosynthesis because we are the micro algae and green algae and have photosynthetic pigments present in them.
$$\bullet$$
So, the correct option is D.
In the two light reactions of photosynthesis
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PS-1 produces a strong oxidant but PS-2 a strong reductant
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PS-1 produces a strong reductant like NADPH but PS-2 a strong oxidant
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PS-1 emits electrons for PS-2
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PS-1 produces ATP which is not formed by PS-2
Explanation
PS I forms a strong reductant (for CO$$_{2}$$ reduction) and PS II is responsible for the production of a strong oxidant (for oxidation of H$$_{2}$$O to O$$_{2}$$). The transfer of electrons from the weak reductant (produced by PS-II) to the weak oxidant (produced by PS-I) is coupled to ATP production.
So, the correct option is 'PS-1 produces a strong reductant like NADPH but PS-2 a strong oxidant'
Photosynthetic yield is reduced due to
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Plasmolysis of cell
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Glycolysis of glucose
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Photolysis of water
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Photorespiration
Explanation
During high temperature and increase in the concentration of the oxygen, the photosynthetic yield declines due to the increase in the affinity of the enzyme ribulose bisphosphate carboxylase oxygenase (RuBPCO) for the oxygen and decrease in the affinity for the carbon dioxide. Due to this change in affinity, it binds with oxygen instead of carbon dioxide and then the process of photorespiration begins rather than the dark reaction. It is a wasteful process in which plants have to spend ATPs to regenerate the enzyme and the carbon.
Hence, the correct answer is 'Photorespiration'.
$$C_4$$ plant are less efficient at low temperature due to
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Low $$O_2$$ affinity of PEP case
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Cold sensitivity of PEP carboxylase enzyme
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Reduced rate of decarboxylation of organic acids
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High energy requirement for $$CO_2$$ fixation.
Explanation
C$$_{4}$$ plants are widespread in tropical regions as they have ability to use the maximum carbon dioxide even with the high temperature and high light intensity. However, their photosynthetic efficiency declines at low temperature due to inactivation of the PEP carboxylase enzyme and high amount of energy required due to photoprotection effect.
Hence, the correct answer is 'Cold Sensitivity of PEP carboxylase enzyme'
The product of oxygenation of RUBP is
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Phosphoglycerate
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Phosphoglycolate
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Oxaloacetate
0%
Both A and B
Explanation
RuBP + O$$_{2}$$ → Phosphoglycolate + 3-Phosphoglycerate + 2H$$^{+}$$
Addition of O$$_{2}$$ to ribulose-1,5-bisphosphate produces 3-phosphoglycerate and 2-phosphoglycolate. Phosphoglycerate refers to 2-phosphoglycerate and 3-phosphoglycerate (but only 3-PGA is produced in this reaction).
So, the correct option is 'Phosphoglycolate'
Due to photo respiration approximately ......... of photosynthetically fixed CO2 is lost
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0%
25%
0%
50%
0%
60%
0%
80%
Explanation
While photorespiration, the oxygenation reaction of RuBisCO is a wasteful process because 3-phosphoglycerate is created at a reduced rate and higher metabolic cost compared with RuBP carboxylase activity. While photorespiratory carbon cycling results in the formation of G3P eventually, there is also a net loss of carbon i.e., 25% of carbon fixed by photosynthesis is re-released as CO$$_{2}$$.
So, the correct option is '25%'.
In $$C_4$$ plants, the final fixation of $$CO_2$$ takes place at
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Mesophyll cell's chloroplast
0%
Bundle sheath cell's cytoplasm
0%
Mesophyll cell's cytoplasm
0%
Bundle sheath cell's chloroplast
Explanation
After carbon fixation, the OAA produced is transported from the cytosol of mesophyll cells to chloroplasts of bundle-sheath cells. Here, decarboxylation of OAA takes place and it releases pyruvic acid and fixed CO$$_{2}$$. The pyruvic acid is transported back to mesophyll whereas the CO$$_{2}$$ enters the Calvin cycle.
So, the correct option is 'Bundle sheath cell's chloroplast'.
Which of the following cell organelles in concerned with photophosphorylation?
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Mitochondria
0%
Plastochondria
0%
Chloroplast
0%
More than one option is concerned
Explanation
The synthesis of ATP is called phosphorylation. If it occurs in the presence of light, it is called photophosphorylation, that occurs during photosynthesis in the chloroplast. Mitochondria perform oxidative and substrate level phosphorylation.
Hence, the correct answer is 'Chloroplast'
The $$CO_2$$ fixation during $$C_4$$ pathway occurs in the chloroplast of
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Guard cells
0%
Bundle sheath cells
0%
Mesophyll cells
0%
Spongy parenchyma
Explanation
The Carbon fixation pathway in C$$_4$$ plants begins in mesophyll cells, where the CO$$_2$$ gets converted to bicarbonate, which is then added to the three-carbon acid phosphoenolpyruvate (PEP) by the action of enzyme phosphoenolpyruvate carboxylase.
So, the correct answer is 'Mesophyll cells'.
Formation of NADPH occurs during
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Cyclic photophosphorylation
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Non - cyclic photophosphorylation
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Oxidative photophosphorylation
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Substrate level phosphorylation
Explanation
Cyclic photophosphorylation exists to provide energy for the calvin cycle and involves only p680 in photosystem ll and its product is ATP. Non-cyclic photophosphorylation is carried out using p700 in photosystem l and p680 in photosystem ll and it produces NADPH and ATP.
So, the correct option is 'Non - cyclic photophosphorylation'.
Four carbon acid Aspartate is transported from mesophyll cells to bundle sheath cell in which of the following $$C_4$$ plant.
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Sugarcane
0%
Panicum
0%
A triplex
0%
Paddy
Explanation
Four carbon Aspartate is transported from mesophyll cells to bundle sheath cell in sugarcane and maize.
This Carbon fixation method with 4 carbon acid is to reduce the chances of photorespiration. This pathway builds up high concentration of carbon dioxide in the Chloroplast of the bundle sheath cells.
So the correct answer is ' Sugarcane and maize'.
In $$C_4$$plants, mesophyll cells and bundle sheath cells are specialised to perform respectively.
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Light reaction and dark reaction
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Dark reaction and light reaction
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Light reaction and photorespiration
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Photorespiration and dark reaction.
Explanation
The mesophyll cells in C4 plants are highly specialized to do the light-dependent reaction of photosynthesis whereas the bundle sheath cells are specialised to perform light-independent reactions.
So, the correct option is, 'Light reaction and dark reaction'.
The sequence of cell organelles during photorespiration is
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Chloroplast - Golgi bodies - Mitochondria
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Chloroplast - Rough endoplasmic reticulum - Dictyosomes
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Chloroplast -Peroxisomes- Mitochondria
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Chloroplast - Vacuole - Peroxisome
Explanation
Photorespiration is a process which takes place in C3 plants. It is a wasteful pathway in which ATP produced by photosynthesis is used in oxygenation of RuBisCO into RuBP. The process begins at chloroplast under light conditions followed to peroxisomes and then to mitochondria.
So, the correct answer is 'Chloroplast -Peroxisomes- Mitochondria'.
Petiole of Australian Acacia helps in?
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Respiration
0%
Photosynthesis
0%
Transpiration
0%
Secretion
Explanation
A petiole joins the leaf to the stem and contains vascular tissue that gives an association from the stem to allow sap to enter the leaf and the results of photosynthesis (starches) to be transported from the leaf to whatever remains of the plant.
So, the correct option is 'Photosynthesis'.
Plants which show both calvin and Hatch slack pathways are :
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$$C_3$$ plants
0%
$$C_4$$ plants
0%
Both $$C_3$$ and $$C_4$$
0%
Both $$C_3$$ and $$CAM$$ plants
Explanation
C$$_4$$ pathway is the alternate pathway of C$$_4$$ cycle to fix CO$$_2$$. In this cycle, the first formed stable compound is a 4 carbon compound ( oxaloacetic acid ). Hence it is called C$$_4$$ cycle. The path way is also called as Hatch and Slack as they worked out the pathway in 1966 and it is also called as C$$_4$$ dicarboxylic acid pathway.
In C$$_4$$ plants
, the light-dependent reactions and the Calvin cycle are physically separated, with the light-dependent reactions occurring in the mesophyll cells (spongy tissue in the middle of the leaf) and the Calvin cycle occurring in special cells around the leaf veins. These cells are called bundle-sheath cells.
So, the correct option is 'C$$_4$$ plants'.
Pigment system is concerned with:
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Photolysis of water
0%
Reduction of $$ C{ O }_{ 2 } $$
0%
Flowering
0%
Seed germination
Explanation
Water splitting (Photolysis of water) occurs in the inner side (lumen side) of the thylakoid membrane.
PIgments and complexes are formed helping in the photosystem II.
So, the correct option is 'Photolysis of water'.
The key compound of Calvin cycle is?
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PGA
0%
PGAL
0%
DHAP
0%
DPGA
Explanation
Calvin cycle is a biochemical reaction in which CO$$_2$$ is fixed with the help of ATP and NADPH$$_2$$ formed in light reaction, to form carbohydrates. The path of carbon during the reaction was studied by Melvin Calvin. Three molecules of additive 6C compound immediately split up by hydrolysis into six molecules of 3C compound called 3-phosphoglyceric acid (3-PGA). Six molecules of 3_PGA are further phosphorylated by ATP and converted into six molecules of 1,3-diphosphoglyceric acid (1,3-DPGA). By using ATP and NADPH$$_2$$ formed in the light reaction, CO$$_2$$ is reduced to form organic food in the form of 3-phosphoglyceraldehyde 3C (PGAL) and further get converted into glucose (6C) which can be utilized directly in plant metabolism or can be stored in the form of starch.
So the correct option is 'PGAL'.
In $$C_4$$ plant PEPcase enzyme involve in :-
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Carboxylation
0%
Decarboxylation
0%
Oxidation
0%
Oxidative decarboxylation
Explanation
Primary carboxylating enzyme, PEPcase in C4 plants is found in cytoplasm of mesophyll cells.
Phosphoenolpyruvate carboxylase (PEPcase) catalyzes the fixation of carbon dioxide with phosphoenolpyruvate to produce oxaloacetate and inorganic phosphate.
So, the correct option is 'Carboxylation'.
Which of the following is a Hydrogen carrier?
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UQ
0%
Cyt b
0%
Cyt C
0%
Cyt $$C_1$$
Explanation
A hydrogen carrier is an organic macromolecule that transports atoms of hydrogen from one place to another inside a cell or from cell to cell. Ubiquinone (UQ) is an organic molecule involved in the electron transfer chain that transfers electrons from NADH reductase to cytochrome reductase (cytochrome b-c1 complex). During this process, it pumps out hydrogen ions from the matrix to the intermembrane space. Cytochrome b, cytochrome c and cytochrome c1 are also involved in the electron transport chain but they do not carry out proton translocation and hence do not act as hydrogen carriers. So, the correct option is 'UQ'.
Consider following statements A & B
A - The enzyme acts on 'N' terminal of polypeptide chain
B - The enzyme acts on 'C' terminal of a polypeptide chain
Choose the correct option w.r.t the digestive juices which contain these enzymes
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A- Succus entericus B - Pancreatic juice
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A - Intestinal juice B - Bile juice in duodenum
0%
A - Pancreatic juice B - Intestinal juice
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A - Intestinal juice B - Gastric juice
In $$C_4$$ plant $$RuBisCO$$ activate during:-
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Day
0%
Night
0%
Midnight
0%
Remain activated all time
Explanation
RuBisCO
catalyzes the key reaction in which RUBP acts as an acceptor for CO2 forming two molecules of PGA. The competing reaction with O2 leads to the formation of phosphoglycolate, which is recycled through photorespiration. Thus, t
he activity of
Rubisco is majorly depended on light activation and dark inactivation. The light reactions of
photosynthesis
produce ATP and activation of
RuBisCO
is ATP-dependent, which furnishes a
mechanism regarding the light-dependent activation of the enzyme. However, a
ctivation of RuBisco activase and transformation of
RuBisCO in its
inactive form need transport of electron and that can only occur in presence of light or during the day.
So, the correct answer is option A.
In the pathway of dark reaction,which occur in all photosynthetic plants,primary $$CO_2$$ acceptor contains how many carbon(s)?
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0%
3
0%
4
0%
1
0%
5
Explanation
Carbon dioxide is captured by the chemical ribulose biphosphate (RuBP). RuBP is a 5-C chemical. Six molecules of carbon dioxide enter the Calvin Cycle, eventually producing one molecule of glucose.
So, the correct option is '5'.
Thylakoids removed from chloroplasts were kept in illuminated culture having $$CO_2$$ and water, it did not produce sugar because of
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absence of enzymes
0%
non linking of PS I and PS II
0%
absence of light trapping molecules
0%
non formation of assimilatory power
Explanation
Thylakoids are the site of light-dependent reaction of photosynthesis. Hence they cannot produce hexose as end product because of the absence of $$CO_2$$ assimilating enzyme.
Therefore the right answer is option "A, absence of enzymes".
During photorespiration oxygen consuming reaction(s) occur in
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Stroma of chloroplasts $$\&$$ peroxisomes
0%
Stroma of Chloroplasts
0%
Grana of chloroplast and peroxisomes
0%
Stroma of chloroplasts and mitochondria
Explanation
The original oxygenation reaction by RUBISCO occurs in the chloroplast. In the peroxisome, glycolate from the chloroplast is converted to glyoxylate. This reaction consumes O2 and generates hydrogen peroxide. The O2 is released again, however, as the hydrogen peroxide is converted to water by the enzyme catalase.
So, the correct option is Stroma of chloroplasts & peroxisomes.
How many Calvin cycle (with some modification) are required to produce 12 molecules of Fructose?
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12
0%
72
0%
36
0%
96
Explanation
Calvin cycle fixes one molecule of carbon which can be used to make sugar. It takes three turns of the Calvin cycle to create one molecule of glyceraldehyde-3 phosphate. After six turns of the Calvin cycle, two molecules of glyceraldehyde-3 phosphate can be combined to make a fructose molecule. So, total 12 calvin cycle are required to produce 12 molecules of fructose.
Thus, the correct answer is '12.'
How many components listed are part of cyclic ETS?
$$P_{700}$$, $$P_{680}$$, NADP reductase, Hydrogen carrier, PS I, Water Splitting Complex, PS II.
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Two
0%
Three
0%
Five
0%
Four
In $$C_4$$ plants, the bundle sheath cells?
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Have thin walls to facilitate gaseous exchange
0%
Have large intercellular spaces
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Are rich in PEP carboxylase
0%
Have a high density of chloroplasts
Centrioles, cilia, flagella, and basal bodies have remarkably similar structural elements and arrangements. This leads us to which of the following as a probable hypothesis ?
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Disruption of one of these types of structure should necessarily disrupt each of the others as well.
0%
Loss of basal bodies should lead to loss of all cilia, flagella and centrioles
0%
Motor proteins such as dynein must have evolved before any of these four kinds of structure.
0%
Natural selection for motility must select for microtubular arrays in circular patterns.
Which of these is incorrect for $$C_4$$-plants
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kranz anatomy
0%
$$CO_2$$ acceptor is PEP
0%
PEPcase in mesophyll
0%
RUBISCO in mesophyll
Which of the following statements about cyclic photophosphory is not correct?
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It does not involve NADPH formation
0%
It may uses electrons supplied by photosystem II
0%
It involves a substrate level phosphorylation
0%
It does not generate oxygen
$$Mg^{2+}$$ and $$Cl^{-}$$ are required during transfer of electron from
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0%
$$OH^{-}$$ to $$Chlorophyll-a_{683}$$
0%
$$OH^{-}$$ to $$P_{700}$$
0%
$$FD$$ to $$FRS$$
0%
$$Cytochrome - b$$ to $$cytochrome - f$$
Explanation
Magnesium and chlorine form an ionic bond. Covalent bonds are formed when two or more atoms share electrons between them.
Ionic bonds are when atoms gain or lose an electron to become charged species that share an electrostatics interaction called an ionic bond.
So, the correct option is 'OH- to chlorophyll -a683'
Photosystem,which is directly responsible for reduction of $$NADP^+$$ to $$NADPH+H^+$$,has an absorption peak at:-
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$$700nm$$
0%
$$680nm$$
0%
$$430nm$$
0%
$$550nm$$
Explanation
Photosystems are the structural and functional unit of photosynthetic light harvesting complexes. These photosystems are of two types: photosystem 1 (680 nm) and photosystem 2(700 nm). Photosystem 2 has an absorption peak of 700 nm. In this process, after the absorption of light, electron get excited and is then transferred through different electron carriers to produce ATP and NADPH.
So, the correct option is '700 nm'
Thylakoids are found in ____.
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0%
Bacteria
0%
Blue green algae
0%
Higher plants
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All of these
The evolutionary strategies developed by $$C_4$$ plants are to?
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0%
Maximize carbon-di-oxide availability and minimize water loss
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Minimize carbon-di-oxide availability and maximize water loss
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Maximize carbon-di-oxide availability and maximize water loss
0%
Minimize carbon-di-oxide availability and minimize water loss
How many ATP - synthesised during complete oxidation of 3 molecule acetyl co A :
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0%
12 ATP
0%
24 ATP
0%
36 ATP
0%
6 ATP
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Practice Class 11 Medical Biology Quiz Questions and Answers
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