Match the columns: Column I Column II (a) Hatch and Slack (i) Electron microscope (b) Theophratus (ii) Citric acid cycle (c) Knoll and Ruska (iii) Micrographia (d) Robert Hooke (iv) $${C}_{4}$$ Pathways (v) Historia Plantarum

(a)-(iv); (b)-(v); (c)-(i); (d)-(iii)

(a)-(iv); (b)-(v); (c)-(i); (d)-(ii)

(a)-(ii); (b)-(iv); (c)-(v); (d)-(iii)

(a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)

MCQ Questions for Class 11 Medical Biology Photosynthesis In Higher Plants Quiz 7

Chemiosmosis is a universal mechanism by which organisms harvest and store energy.

Which of the following best describes the process?

0%
It is the process of whereby a proton gradient drives an energy-requiring reaction.
0%
It is the process used to move protons up a concentration gradient for subsequent production of ATP
0%
It is the process that uses pumps to drive chemicals across the membrane.
0%
It is the movement of specific chemicals against its gradient coupled to the flow of protons down its concentration gradient.

Photorespiration is an alternative process that some plants undergo under stressful environmental conditions. Which of the following best describes conditions that would most likely lead to a plant undergoing photorespiration?

0%
High temperature and open stomata which leads to a build up of carbon dioxide in the leaf.
0%
High temperatures and closed stomata which leads to a build up of oxygen gas in the leaf.
0%
High temperature and closed stomata which leads to a build up of water and carbon dioxide in the leaf.
0%
Low temperature and closed stomata which leads to a build up of water and oxygen gas in the leaf.
0%
Low temperature and open stomata which leads to a build up of oxygen gas in the leaf.

NADP is the abbreviation of

0%
Nicotinamide adenosine dinucleostide phosphate.
0%
Nicotinamide adenine dinucleostide phosphate.
0%
Nicotinamide adenine dinucleous phosphate.
0%
Nicotinamide adenosine dinucleous phosphate.

In Kranz anatomy, the bundle sheath cells have:

0%
Thin walls, many intercellular spaces and no chloroplast
0%
Thick walls, no intercellular spaces and large number of chloroplasts
0%
Thin walls, no intercellular spaces and several chloroplasts
0%
Thick walls, many intercellular space and few chloroplasts

Explanation

Correct option: B

Explanation:

Kranz anatomy is a special structure in the leaves of plants that have a $C_4$ pathway of carbon dioxide fixation.
The leaves contain a ring of mesophyll cells, containing small dimorphic chloroplasts concerned with the initial fixing of carbon dioxide, surrounding a sheath of parenchyma cells (the bundle sheath) which has large chloroplasts involved in the Calvin cycle.
Bundle sheath cells surround the vascular bundles. The cells are thick-walled with no intercellular spaces.
For some plants, $C_4$ photosynthesis pathway has facilitated their adaptation to arid conditions, high temperatures, and marginal environments.
Understanding the basics of this pathway has applications for improvements in agricultural productivity and alternative fuel development.

Which of the following characteristics out of I, II and III are exhibited by

$C_4$ plants?
I. Kranz anatomy.
II. The first stable product of photosynthesis is oxalo acetic acid.
III. Both PEP carboxylase and ribulose-bis phosphate carboxylase act as carboxylating enzyme.
Choose the correct option.

0%
I and II, but not III
0%
II and Ill, but not I
0%
I and lII, but not II
0%
All of these

Explanation

Kranz anatomy is the structure found in the C

$_4$ plants. This is the arrangement of the mesophyll cells which have few and small chloroplasts. These cells are surrounded internally by the bundle sheath cells which have many large chloroplasts.

The CO

$_2$ is fixed by PEP carboxylase in the mesophyll cells and the first stable product of photosynthesis is the oxalo acetic acid. This is 4 carbon compound and hence, the name of the pathway is C

$_4$ pathway.

The PEP carboxylase is present in the mesophyll cells and the RuBisCo is present in the bundle sheath cells. Both of these enzymes acts as carboxylating enzyme which helps in CO

$_2$ fixation.

Thus, the correct answer is option D.

Photorespiratory reactions are operated in the

0%
Chloroplasts, ribosomes and peroxisomes.
0%
Chloroplasts, mitochondria and peroxisomes.
0%
Mitochondria, preoxisomes and lysosomes.
0%
Mitochondria, chloroplasts and ribosomes.

$C_4$ pathway is advantageous over

$C_3$ pathway in plants as it

0%
Occurs in relatively low $CO_2$ concentration
0%
Uses more amount of water
0%
Occurs in relatively low $O_2$ concentration
0%
Is less efficient in energy utilization

Explanation

The C

$_4$ pathway is certainly more efficient than the C

$_3$ pathway in the sense of carbon fixation. This is due to two reasons. The first one is that the system does not undergo photorespiration, a process that runs counter to photosynthesis. The second one is that plants can keep their pores shut longer periods of time, thus avoiding water loss. C

$_4$ is usually saturated at relatively low CO

$_2$ concentration. Thus, C

$_4$ has greater production yields than C

$_3$ species at low concentrations. So, the correct answer is option A.

The entire reaction of C

$_4$ pathway takes place in the

0%
Mesophyll and bundle sheath cells.
0%
Vascular bundle and palisade tissue.
0%
Mitochondria and peroxisome.
0%
Bundle sheath cells and endoplasmic reticulum.

Explanation

The first carbon fixation in C

$_4$ pathway occurs in mesophyll cells. The thin walled mesophyll cells of C

$_4$ have grana in the chloroplast and carry on initial carbon dioxide fixation with the help of PEP carboxylase enzyme. The PEP carboxylase enzyme carboxylates phosphoenol pyruvic acid or PEP and converts it into four carbon atom containing organic acids like oxaloacetic acid and malic acid. These organic acids are transported to bundle sheath cells, where they are subsequently decarboxylated to release carbon dioxide.

Thus, the correct answer is option A.

The correct sequence of organelles in which glycolate and glyoxylate are produced sequentially in photorespiration is

0%
Chloroplast and mitochondria
0%
Chloroplast and peroxisome
0%
Peroxisome and mitochondria
0%
Peroxisome and chloroplast

The

${C}_{4}$ plants differ from

${C}_{3}$ plants with respect to the

0%
Substance that accepts $C{O}_{2}$ in carbon assimilation.
0%
Type of end product.
0%
Type of pigment involved in photosynthesis.
0%
Number of ATP that is consumed in preparing sugar.

Explanation

The C

$_4$ plants differ from C

$_3$ plants with reference to the substrate that accepts CO

$_2$ in carbon assimilation. In the C

$_3$ plants, CO

$_2$ is assimilated by condensing with RuBP by the help of RuBisCO enzyme to yield the first stable product, three carbon compund PGA. In C

$_4$ plants, CO

$_2$ is assimilated by condensing with PEP, by the help of PEPCase enzyme to yield the first stable product, four carbon compound OAA.

Kranz anatomy is found in case of

0%
Flower
0%
Root
0%
Leaf
0%
Stem

The two enzymatic activities associated with RUBISCO are

0%
Oxidase and oxygenase
0%
Oxygenase and carboxylase
0%
Oxidase and carboxylase
0%
Oxygenase and carbamylation

Phosphoenol pyruvate (PEP) is the primary

CO2CO2 acceptor in:

0%
$C_3$ and $C_4$ plants
0%
$C_3$ plants
0%
$C_4$ plants
0%
$C_2$ plants

Explanation

PEP stands for phosphoenol pyruvate. It acts as a primary acceptor in the case of C

$_4$ plants and gets converted to oxaloacetate. In C

$_3$ plants, ribulose biphosphate acts as a primary acceptor and gets converted into phosphoglycerate (PGA). C

$_2$ cycle is a photorespiratory cycle where due to the excessive oxygen concentration major site of RuBisCo is occupied by it which leads to decreased efficiency of RuBisCo to combine with carbon dioxide.

So, the correct answer is option C.

$Na^+, K^+$ pump is found in membranes of many cells, like nerve cells. It work against electro chemical gradient and involve an integral protein ATP. For each molecule of ATP used

0%
3 ions of $Na^+$ pumped out and 2 $K^+$ are taken in.
0%
3 ions of $Na^+$ are taken in and 2 $K^+$ are pumped out.
0%
2 ions of $Na^+$ are thrown out and 3 $K^+$ are absorbed.
0%
3 ions of $K^+$ are absorbed and 3 $Na^+$ are pumped out.

Explanation

The sodium-potassium pump is involved in the movement of the sodium and potassium ions across the cell membrane. In this process, ATP is hydrolyzed to liberate energy required for the transport. Hence the process is active that takes place with the help of

$Na^+$ /

$K^+$ -ATPase enzyme. In this, three sodium ions are expelled outside the cell and two potassium ions are moved into the cell. Thus the correct answer is option A.

The mechanism of ATP formation both in mitochondria and chloroplast is best explained by

0%
Relay pump theory of Godlewski
0%
Cholondy - Wents model
0%
Cheimoosmotic theory
0%
Munch's mass flow hypothesis

Match the columns:

Column I	Column II
(a) Hatch and Slack	(i) Electron microscope
(b) Theophratus	(ii) Citric acid cycle
(c) Knoll and Ruska	(iii) Micrographia
(d) Robert Hooke	(iv) ${C}_{4}$ Pathways
	(v) Historia Plantarum

0%
(a)-(iv); (b)-(v); (c)-(i); (d)-(ii)
0%
(a)-(iv); (b)-(v); (c)-(i); (d)-(iii)
0%
(a)-(ii); (b)-(iv); (c)-(v); (d)-(iii)
0%
(a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)

$C_4$ -plants, Calvin cycle enzymes are absent in

0%
Mesophyll chloroplasts
0%
Bundle sheath chloroplasts
0%
Guard cell chloroplasts
0%
Epidermal chloroplasts.

Explanation

Most of the plants that are adapted to dry tropical regions have the

$C_{4}$ pathway. These plants are called

$C_{4}$ plants. Sugarcane, Maize, Sorghum, etc. are the examples of these plants. In these plants, double fixation of carbon dioxide occurs. In

$C_{4}$ plants, the Calvin cycle occurs in the bundle-sheath cells. Calvin cycle enzymes such as RubisCo is absent from the mesophyll cell of chloroplast of

$C_{4}$ plant. These enzymes are present in the bundle-sheath cells surrounding the vascular bundles, guard cells and epidermal cells of chloroplasts.

Chemiosmosis was first described by

0%
Boyer
0%
Walker
0%
Mitchell
0%
Meischer

Photophosphorylation consists of

0%
Cyclic and non-cyclic phosphorylation
0%
Oxidative phosphorylation
0%
Substrate phosphorylation
0%
None of the above.

Explanation

Photosynthesis is an anabolic process happening in green plants during which plant body synthesizes its own food material by taking carbon dioxide from atmosphere and water from the soil in presence of sunlight. It proceeds in a sequence of light phase and dark phase.

Light phase is also known as a photochemical phase because it is a light dependent phase. During this phase, the formation of high-energy chemical intermediates ATP and NADPH

$_{2}$ takes place. ATP and NADPH

$_{2}$ are the assimilatory power of photosynthesis. Light phase also includes light absorption, water splitting and release of oxygen. Two photosynthetic units called Photosystem I and Photosystem II are also involved in light phase.

Dark phase is the phase which is independent of light. But, it is dependent on the products of light reaction (ATP and NADPH

$_{2}$ ). In this phase, assimilation of carbon dioxide takes place during which carbon dioxide and water combine to form glucose.

Oxysomes were discovered by

0%
Palade
0%
Benda
0%
Fernandes-Moran
0%
Luch and Rich

Explanation

Oxysomes refers to small round structures present within the folds of the cristae of the inner mitochondrial membrane.
It is also known as F $_0$ -F $_1$ particles.
F $_0$ and F $_1$ particles are found in the inner mitochondrial region and are attached to the cristae and help in ATP production and oxidation.
It is also known as Fernandez Moran particles (named after its discoverers).
So, the correct answer is 'Fernandes-Moran'.

Match the following

a.	Bacteria	1.	Synthesis and storage of lipids
b.	Sphaerosomes	2.	Idiogram
c.	Chloroplasts	3.	Glycocalyx
d.	Karyotype	4.	Thylakoids

0%
a-3, b-1, c-4, d-2
0%
a-3, b-1, c-2, d-4
0%
a-4, b-3, c-2, d-1
0%
a-1, b-2, c-3, d-4
0%
a-3, b-2, c-4, d-1.

Glycolate metabolism occurs in

0%
Lysosome
0%
Ribosomes
0%
Glyoxysomes
0%
Peroxisome

$C_4$ -plants, photosystem II is absent in chloroplasts of

0%
Mesophyll cells
0%
Bundle sheath cells
0%
Palisade cells
0%
Spongy cells.

Explanation

$C_{ 4 }$ plants have two types of photosynthetic cells, mesophyll and bundle sheath cells. Mesophyll chloroplasts are randomly distributed along cell walls, whereas bundle sheath chloroplasts are located close to the vascular tissues or mesophyll cells depending on the plant species. The photosystem is absent in bundle sheath cells.

Cell organelle taking part in photorespiration is

0%
Glyoxisome
0%
Peroxisome
0%
Dictyosome
0%
E.R.

The excess energy of electron is used in the synthesis of

0%
Organic compounds
0%
ATP from ADP and iP
0%
$NADPH_2$ from $NADP$
0%
None of the above

Which cellular part is correctly described

0%
Thylakoids - Flattened membranous sacs forming grana
0%
Centrioles - Sites for active RNA synthesis
0%
Ribosomes - Those in chloroplasts are larger (80 S) while those in cytoplasm are smaller (70 S)
0%
Lysosomes - Opimally active at 8.5 pH.

Agranal chloroplasts are found in some ____________.

0%
Succulents
0%
Hydrophytes
0%
$C_4$ plants
0%
$C_3$ plants.

Energy required to synthesise ATP from ADP and inorganic phosphate is

0%
2500 cal
0%
7600 cal
0%
12000 cal
0%
20000 cal

Reduction means

0%
Loss of electrons
0%
Gain of electrons
0%
Gain of protons
0%
Loss of protons and electrons

$C_4$ plants are adapted to

0%
Temperate humid climate
0%
Tropical humid climate
0%
Temperate dry climate
0%
Tropical dry climate

Explanation

$C_{4}$ plants are adapted to dry tropical regions. Sugarcane, Maize, Sorghum, etc., are the examples of

$C_{4}$ plants. In these plants, the Calvin cycle occurs in the bundle-sheath cells.

$C_{4}$ plants have a special type of anatomy called Kranz anatomy. They can tolerate higher temperatures because of Kranz anatomy. 'Kranz' means wreath and is a reflection of the arrangement of cells. Kranz anatomy is characterized by having a large number of chloroplasts, grana are absent, thick walls impervious to gaseous exchange and no extracellular spaces.

Kranz anatomy is found in (A) (B) (C) (D)

0%
Stems of $C_4$ plants
0%
Stems of $C_3$ plants
0%
Leaves of $C_4$ plants
0%
Leaves of $C_3$ plants.

Explanation

Kranz anatomy is found in leaves of

$C_{4}$ plants. The

$C_{4}$ pathway requires the presence of two types of cells i.e. mesophyll cells and bundle sheath cells. The particularly large cells around the vascular bundles of

$C_{4}$ plants are called bundle sheath cells, these cells may form several layers around the vascular bundles, they are characterised by having large number of chloroplasts, grana are absent, thick walls impervious to gaseous exchange and no extracellular spaces. This special anatomy of leaves of the

$C_{4}$ plants is called Kranz anatomy. 'Kranz' means wreath and is a reflection of the arrangement of cells.

Excited pigment molecule shifts an electron in an outer orbit having

0%
Less energy
0%
More energy
0%
Lesser spin
0%
More spin

Energy required for ATP synthesis in PS II comes from

0%
Proton gradient
0%
Electron gradient
0%
Reduction of glucose
0%
Oxidation of glucose

Calvin cycle operates in chloroplasts. Where does Hatch-Slack pathway occur

0%
Mitochondria
0%
Golgi bodies
0%
Chloroplasts
0%
Cytoplasm.

Explanation

Hatch-Slack pathway is a cyclic process. It occurs in chloroplasts. It was discovered by two Australian scientists Hatch and Slack. It is also known as

$C_{4}$ pathway because it is found in

$C_{4}$ plants. Carbon dioxide fixation is done in this pathway. The primary

$CO_{2}$ acceptor is a three-carbon molecule phosphoenol pyruvate (PEP) and it is present in mesophyll cells. The enzyme that catalyses this

$CO_{2}$ fixation is PEP carboxylase or PEPcase. The mesophyll cells of

$C_{4}$ plants lack the enzyme RuBisCO. The 4-carbon oxaloacetic acid (OAA) is formed in the mesophyll cells which is further converted into malic acid or aspartic acid and then transported into bundle sheath cells. In the bundle sheath cells, these

$C_{4}$ acids are broken down to release

$CO_{2}$ and a three-carbon molecule.

The source of hydrogen for carbon assimilation during photosynthesis is

0%
$NADPH$
0%
$FADH_2$
0%
$H_2O$
0%
$RuBP$ .

ATP is injected in cyanide poisoning because it is

0%
Necessary for cellular functions
0%
Necessary for $Na^+$ - $K^+$ pump
0%
$Na^+$ - $K^+$ pump operates at the cell membranes
0%
ATP breaks down cyanide

In non-cyclic photophosphorylation the electron released by

$P_{680}$ is replaced by

0%
Plastoquinone
0%
Water
0%
$CO_2$
0%
$NADP^+$ .

Explanation

Non-cyclic phosphorylation involves both Photosystem I and Photsystem II. These two photosystems work in series, first PS II and then PS I. The two photosystems are connected through an electron transport chain.

$NADPH$ is synthesised by this kind of electron flow. Electrons are transferred from the PS II and then passed on to the pigments of PS I. Then, electrons get excited and transferred to another acceptor. These electrons are then moved downhill again to a molecule of

$NADP^{+}$ . The addition of these electrons results in formation of

$NADPH$ . The electron released from PS II by

$P_{680}$ must be replaced. This is achieved by electrons available due to splitting of water. The water splitting complex is associated with PS II, which itself is physically located on the inner side of the membrane of the thylakoid. Water is split into

$H^{+}$ ,

$[O]$ and electrons. The protons and oxygen formed by splitting of water is released within the lumen of the thylakoids. The oxygen produced is released as one of the net products of photosynthesis.

$2H_{2}O$

$\longrightarrow$

$4H^{+}$ +

$O_{2}$ +

$4e^{-}$

Dark reaction in photosynthesis is called so because

0%
It can occur in dark alone.
0%
It does not require direct light energy.
0%
It cannot occur during day time.
0%
It occurs more rapidly at night.

In case of

$C_4$ -pathway

0%
$CO_2$ combines with PGA
0%
$CO_2$ combines with PEP
0%
$CO_2$ first combines with RuBP
0%
$CO_2$ combines with RMP

Explanation

$C_{4}$ pathway is called so because it is found in

$C_{4}$ plants. It is a cyclic process. It is also known as a Hatch-Slack pathway. In this pathway,

$CO_{2}$ combine with PEP because it is primary

$CO_{2}$ acceptor. PEP (phosphoenolpyruvate) is a three-carbon molecule and it is present in mesophyll cells. The enzyme that catalyzes this

$CO_{2}$ fixation is PEP carboxylase or PEPcase. The mesophyll cells of

$C_{4}$ plants lack the enzyme RuBisCO. The 4-carbon oxaloacetic acid (OAA) is formed in the mesophyll cells which is further converted into the malic acid or aspartic acid and then transported into bundle sheath cells. In the bundle sheath cells, these

$C_{4}$ acids are broken down to release

$CO_{2}$ and a three-carbon molecule.

Which one is most efficient converter of sunlight?

0%
Sugarcane
0%
Rice
0%
Wheat
0%
Papaya.

Explanation

Plants such as sugarcane and sorghum fix atmospheric carbon dioxide into phosphoenol pyruvic acid to produce oxaloacetic acid (a

$C_4$ acid). Such plants are called

$C_4$ plants.

$C_4$ cycle is much more efficient in utilizing atmospheric

$CO_2$ (even when the stomata are nearly closed).

$C_3$ cycle is much less efficient in utilizing atmospheric

$CO_2$ .

Sugarcane performs

$C_4$ cycle.

Rice, Wheat, Papaya perform

$C_3$ .

So, the correct answer is 'Sugarcane'.

ATP synthesis proposed by Peter Mitchell is

0%
Phosphorylation
0%
Photophosphorylation
0%
Oxidative phosphorylation
0%
Chemiosmotic synthesis

Photophosphorylation is the process in which

0%
$CO_2$ and $O_2$ unite.
0%
Phosphoglyceric acid is produced.
0%
Aspartic acid is formed.
0%
Light energy is converted into chemical energy through production of ATP.

Explanation

Photophosphorylation is the process in which light energy is converted into chemical energy through production of ATP. The process of reduction of

$NADP$ into

$NADP + H^{+}$ may be denoted as electron transport system (ETS). It is the process of formation of ATP from ADP and inorganic phosphate (ip) utilising light energy. The flow of electrons through ETS is linked to photophosphorylation. Electron transport chain is a series of electron carriers over which electrons pass in a downhill journey releasing energy at every step that is used in generating an electrochemical proton gradient which helps in synthesising ATP. Based on path of electrons, associated photophosphorylation can be identified as non-cyclic and cyclic phosphorylation.

When cell converts light energy into chemical energy, which of the following reaction would take place?

0%
ADP + iP = ATP
0%
ATP - iP = ADP
0%
AMP + iP = ADP
0%
GDP + iP = GTP

Dark reaction of photosynthesis occurs in

0%
Grana
0%
Stroma
0%
Matrix
0%
Cytoplasm

Assimilatory power produced in Hill reaction and used in Blackman's reaction refers to

0%
Generation of ATP and NADPH $_2$
0%
Reduction of CO $_2$
0%
Splitting of water
0%
Disintegration of plastids

Explanation

Light reaction or light dependent reaction or Hill's reaction occurs in grana of chloroplast where the energy from sunlight is absorbed and converted to chemical energy which is stored in ATP and NADPH

$_2$
In light-independent reactions or Blackman's reaction, the carbohydrates are synthesized from carbon dioxide using the energy stored in the ATP and NADPH

$_2$ formed in the light-dependent reactions.

Assimilatory powers (ATP and NADPH

$_2$ ) are mainly produced in the light reaction.

So the answer is 'Generation of ATP and NADPH

$_2$ .

Chemiosmotic theory of ATP synthesis in chloroplasts and mitochondria is based on _______________.

0%
Membrane potential
0%
Accumulation of $Na^+$ ions
0%
Accumulation of $K^+$ ions
0%
Proton gradient

$C_4$ plants, synthesis of sugars/final

$CO_2$ fixation occurs in

0%
Palisade cells
0%
Spongy cells
0%
Undifferentiated mesophyll cells
0%
Bundle sheath cells

Explanation

In C

$_4$ plants

CO $_2$ is taken from the atmosphere is accepted by PEP present in the chloroplasts of mesophyll cells of the leaves.
It forms a first stable 4-carbon compound oxaloacetic acid.
This again converts into malic acid which enters into the chloroplasts of bundle sheath cells where oxidative decarboxylation occurs to form pyruvic acid.
CO $_2$ released in bundle sheath cells react with Ribulose-1,5-biphosphate (RuBP) and Calvin cycle starts which fix CO $_2$ and gives sugar.
Pyruvic acid again enters mesophyll cells to regenerates phosphoenol pyruvic acid.

So the correct option is 'Bundle sheath cells'.

Which is a 4-carbon compound?

0%
Oxaloacetic acid
0%
Citric acid
0%
Phosphoglyceric acid
0%
Phosphoenolpyruvate
0%
Ribulosebiphosphate

ATP does not provide phosphate in the reaction

0%
Glucose Glucose 6-P
0%
Fructose Fructose 6-P
0%
PGAL 1 : 3-diPGA
0%
PEPA Pyruvic acid

PEP is

$CO_2$ acceptor in

0%
$C_4$ plants
0%
$C_3$ plants
0%
$C_2$ plants
0%
Both A and B

Explanation

PEP (phosphoenolpyruvate) is a three-carbon molecule. It is first

$CO_{2}$ acceptor in

$C_{4}$ plants. Most of the plants that are adapted to dry tropical regions have the

$C_{4}$ pathway. These plants are called

$C_{4}$ plants. Sugarcane, Maize, Sorghum, Corn, etc. are the examples of these plants. In these plants, double fixation of carbon dioxide occurs by

$C_{4}$ pathway. The enzyme that catalyzes this

$CO_{2}$ fixation is PEP carboxylase or PEPcase. The mesophyll cells of

$C_{4}$ acids are broken down to release

$CO_{2}$ and a three-carbon molecule.

CBSE Questions for Class 11 Medical Biology Photosynthesis In Higher Plants Quiz 7 - MCQExams.com

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Practice Class 11 Medical Biology Quiz Questions and Answers

CBSE Questions for Class 11 Medical Biology Photosynthesis In Higher Plants Quiz 7 - MCQExams.com

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Practice Class 11 Medical Biology Quiz Questions and Answers

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