Explanation
In C4 plants:
For 1 CO2 molecule: 5 ATPs + 2 NADPH molecules are required
For 3 CO2 molecules (that is 1 triose phosphate): 15 ATPs + 6 NADPH molecules are required
For 6 CO2 molecules (that is 1 glucose): 30 ATPs + 12 NADPH molecules are required.
So, the correct option is '30'.
In C$$_3$$ plants first product is 3 carbon compound called phosphoglyceric acid (PGA) while in C$$_4$$ plants, the first product is 4 carbon compound called the oxaloacetic acid (OAA).
A. Potato- C$$_3$$ plant.
B. Mustard- C$$_3$$ plant.
C. Onion- C$$_4$$ plant.
D. Wheat- C$$_3$$ plant.
Hence, the correct answer is 'Onion'.
In electron transport process the excited electron from P$$_{680}$$ (PS II) is accepted by primary acceptor quinone, which sends them to an electron transport system consisting of plastoquinone, cytochrome complex and plastocyanin.
The excited electron absorbed by P$$_{700}$$ (PS I) reaction centre, then transfer to the ferredoxin (Fe), then the reduced Ferredoxin donates the electron to NADP$$^+$$.
The $${NADP}^+$$ take an electron from ferredoxin, protons from the medium and get reduced to NADPH in presence of enzyme ferredoxin- NADP- reductase.
Hence, the correct answer is 'PQ, cytochromes, PC and FeS'.
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