Match column I with column II and select the correct option from the codes given below. Column I Column II A. Krebs' cycle (i) Inspiration B. Lungs (ii) Hamburger's phenomenon C. Diaphragm (iii) Diffusion of $$CI^{-}$$ into RBCs D. Pons varolii (iv) Mitochondria E. Chloride shift (v) Crural and costal (vi) Pneumotaxic centre (vii) Expiration

A-(iv), B-(i), (vii), C-(v), D-(vi), E-(ii), (iii)

A-(v), B-(i), C-(iv), (vii), D-(vi), E-(ii), (iii)

A-(ii), (vi), B-(i), C-(iii), D-(v), (vii), E-(iv)

A-(iii), B-(i), C-(ii), (v), D-(vi), (vii), E-(iv)

MCQ Questions for Class 11 Medical Biology Respiration In Plants Quiz 14

The fate of pyruvic acid during aerobic respiration is

0%
Lactic acid fermentation
0%
Alcoholic fermentation
0%
Oxidative decarboxylation
0%
Oxidative phosphorylation

Explanation

During aerobic respiration, pyruvic acid which is formed during glycolysis enters the mitcohondrial matrix. It undergoes oxidative decarboxylation to produce

${CO}_{2}$ and NADH. The product combines with sulfur-containing co-enzyme A to form acetyl CoA. This reaction is catalyzed by an enzyme complex pyruvate dehydrogenase. This step is called link reaction or gateway step as it links glycolysis with Krebs' cycle.

$Pyruvic \,\,acid+COA+{NAD}^{+}\xrightarrow[Pyruvate \,\,dehydrogenase]{ Mg^{2+}}Acetyl \,CoA+{CO}_{2}+NADH+{H}^{+}$

So the correct answer is 'Oxidative decarboxylation'.

Krebs' cycle is also called metabolic sink as it is a common pathway for

0%
Carbohydrates, fats and proteins (amino acids)
0%
Carbohydrates and fats only
0%
Carbohydrates and organic acids only
0%
Proteins and fats only

Explanation

Krebs' cycle also known as TCA cycle or citric acid cycle, is a common pathway of oxidative breakdown of carbohydrates, fatty acids and amino acids. Amino acids enter the Krebs' cycle directly as glutamate (for

$\alpha$ -Ketoglutarate) and aspartate (for oxaloacetate) after their deamination. Fats produce fatty acids and glycerol. Glycerol is phosphorylated and oxidized to form glyceraldehyde 3-phosphate. Fatty acids undergo

$\beta$ -oxidation to produce acetyl CoA. Acetyl CoA enters Krebs' cycle.

So the correct answer is 'Carbohydrates, fats and proteins (amino acids)'.

Which of the following is a 4-carbon compound?

0%
Oxaloacetic acid
0%
Phosphoglyceric acid
0%
Ribulose bisphosphate
0%
Phosphoenol pyruvate

Pyruvate dehydrogenase is used in converting

0%
Glucose to Pyruvate
0%
Pyruvic acid to Lactic acid
0%
Pyruvate to Acetyl CoA
0%
Pyruvate to Glucose

Which step is called a gateway step/link reaction in aerobic respiration?

0%
Glycolysis
0%
Formation of acetyl coenzyme A
0%
Citric acid formation
0%
ETS terminal oxidation

Explanation

During aerobic respiration, pyruvic acid which is formed during glycolysis enters the mitochondrial matrix. It undergoes oxidative decarboxylation to produce

$Pyruvic \,\,acid+COA+{NAD}^{+}\xrightarrow[Pyruvate \,\,dehydrogenase]{ Mg^{2+}}Acetyl\,\, CoA+{CO}_{2}+NADH+{H}^{+}$

So the correct answer is 'Formation of acetyl coenzyme A'.

Site of Krebs' cycle in mitochondria is

0%
Outer membrane
0%
Matrix
0%
Oxysomes
0%
Inner membrane

The first 5C dicarboxylic acid in Krebs' cycle which is used in nitrogen metabolism is

0%
OAA
0%
Citric acid
0%
$\alpha$ -ketoglutaric acid
0%
Acetyl coenzyme A

Explanation

The first 5 carbon dicarboxylic acid in Krebs' cycle is

$\alpha$ -ketoglutaric acid. The

$\alpha$ -ketoglutarate that accumulates when

$\alpha$ -ketoglutarate dehydrogenase is inhibited can be used in nitrogen metabolism as a precursor for several amino acids and the purine bases.

$\alpha-ketoglutarate \rightarrow Glutamate\rightarrow Other \,\,amino \,\,acids\rightarrow Purines$

$\alpha$ -ketoglutarate of Krebs' cycle produces an important amino acid called glutamate on amination.

So the correct answer is '

$\alpha$ -ketoglutaric acid'.

Categories the given equations under respective phases and select the correct option.

0%
I-Glycolysis ; II-Fermentation ; III-Krebs' cycle
0%
I-Krebs' cycle ; II - Fermentation ; III -Glycolysis
0%
I-Krebs' cycle ;II- Glycolysis ; III- Fermentation
0%
I- Glycolysis ; II- Krebs' cycle ; III-Fermentation

Explanation

Glycolysis, also known as EMP (Embden, Meyerhof, Parnas) pathway, is the breakdown of glucose to pyruvic acid in the absence of oxygen. It occurs in the cytosol of the cell and completes in 10 steps. Net reaction of glycolysis is:

$Glucose+{2NAD}^{+}+2ADP+{2H}_{3}{PO}_{4}\xrightarrow{Glycolysis}2 Pyruvate+2 NADH+2 ATP+{2H}^{+}$

A molecule of pyruvic acid that enters a mitochondrion is completely oxidized to form 3 carbon dioxide in one pre-Krebs' cycle decarboxylation and two Krebs' cycle decarboxylations. Net reaction of Krebs' cycle is as:

$Pyruvic acid+{4NAD}^{+}+{FAD}^{+}+{2H}_{2}O+ADP+Pl\rightarrow{3CO}_{2}+4 NADH{4H}^{+}+{FADH}_{2}+ATP$

The given reaction represents alcoholic fermentation. In alcoholic fermentation, pyruvate is converted into ethanol in a two-step pathway. Ethyl alcohol fermentation. is quite common in fungi(e.g., Rhizopus, yeast) and bacteria. In yeast, pyruvate is decarboxylated to form acetaldehyde which is then reduced by NADH to form ethanol.

So the correct answer is 'I- Glycolysis; II- Krebs' cycle; III-Fermentation'.

1034972_887760_ans_b80451c14f2746c2b58f8b781a653536.jpg

Substrate level phosphorylation occurs during which step of Krebs' cycle?

0%
$Succinyl \,CoA\rightarrow Succinic \,acid$
0%
$Isocitric \,acid\rightarrow Oxalosuccinic \,acid$
0%
$Oxalosuccinic \,acid\rightarrow\alpha-ketoglutaric \,acid$
0%
$Malic \,acid\rightarrow OAA$

Explanation

During Krebs' or citric acid cycle, succinyl-CoA is acted upon by enzyme succinyl-CoA synthetase to form succinate (a 4C compound). The reaction releases sufficient energy to form ATP (in plants) or GTP (in animals) by substrate-level phosphorylation. GTP can form ATP through a coupled reaction.

$Succinyl \,\,CoA+GDP/ADP +{H}_{3}{PO}_{4}\overset{Succinyl CoA}{\underset{synthetase}{\rightleftharpoons}}Succinate+CoA+GTP/ATP$

So the correct answer is '

$Succinyl \,CoA\rightarrow Succinic \,acid$ '.

Refer the given figure showing citric acid cycle. What changes take place during the conversion of A to B?

0%
$CO_2$ is liberated
0%
$NAD^+$ is converted to $NADH$ + $H^+$
0%
GTP is formed from GDP
0%
All of these

Which of the following steps of respiration is amphibolic?

0%
Glycolysis
0%
Oxidative decarboxylation of pyruvate
0%
TCA cycle
0%
Oxidative phosphorylation

The intermediate product between

$\alpha$ -ketoglutaric acid and succinic acid in TCA cycle is

0%
Acetyl CoA
0%
Succinyl CoA
0%
Fumarate
0%
Oxalosuccinic acid

Select the correct statement -

0%
When ATP is synthesised directly from metabolites, it is substrate level phosphorylation.
0%
In Krebs' cycle, citrate undergoes 2 decarboxylations and 4 dehydrogenations.
0%
Krebs' cycle is an amphibolic process
0%
All of these

Explanation

The term substrate-level phosphorylation refers to the synthesis of ATP by reactions in which ADP is one of several substrates and ATP is one of several products of an enzyme-catalyzed reaction. In the example below, the substrates are phosphoenolpyruvate and ADP. Each acetyl coenzyme A proceeded once through the citric acid cycle. Therefore, in total, it created 6

$NADH$ +

$H^+$ molecules, two

$FADH_2$ molecules, four carbon dioxide molecules, and two ATP molecules. In Krebs' cycle, citrate undergoes 2 decarboxylations and 4 dehydrogenations. Kreb cycle is an amphibolic pathway. It serves in both catabolic and anabolic processes. The Kerbs cycle or citric acid cycle is a series of reactions that degrades acetyl CoA to yield carbon dioxide, and energy, which is used to produce

$NADH$ ,

$H^+$ and

$FADH$ .

Thus, the correct answers is 'All of the above'.

All enzymes of TCA cycle are located in the mitochondrial matrix except one which is located in inner-mitochondrial membranes in eukaryotes and in cytosol in prokaryotes. This enzyme is

0%
Isocitrate dehydrongenase
0%
Ketoglutarate dehydrogenase
0%
Succinate dehydrogenase
0%
Lactate dehydrogenase

Respiratory quotient is defined as

0%
$O_2$ evolved / $CO_2$ absorbed
0%
$CO_2$ evolved / $O_2$ absorbed
0%
$CO_2$ evolved
0%
$CO_2$ absorbed/ $O_2$ evolved.

Select the correct option:

Select the correct sequence of formation of given intermediates of Krebs' cycle.

0%
$Succinate\rightarrow Malate\rightarrow Fumarate\rightarrow OAA$
0%
$Fumarate\rightarrow Succinate\rightarrow Malate\rightarrow OAA$
0%
$Succinate\rightarrow Fumarate\rightarrow Malate\rightarrow OAA$
0%
$Malate\rightarrow Fumarate\rightarrow Succinate\rightarrow OAA$

Explanation

In Kreb's cycle:

1. Dehydrogenation: This process converts succinate into 4 carbon fumarate with the aid of enzyme, succinate dehydrogenase, and liberates a pair of hydrogen atoms.

2. Hydration. This process changes fumarate into 4- carbon maltate in the presence of water and an enzyme furmarase.

3. Dehydrogenation: This process restores oxaloacetate by removing a pair of hydrogen atoms from maltate with the help of an enzyme maltate dehydrogenase.

So, the correct answer is 'Succinate

$\rightarrow$ Fumarate

$\rightarrow$ Malate

$\rightarrow$ OAA'.

Select the wrong statement -

0%
When tripalmitin is used as a substrate in respiration, the RQ is 0.7.
0%
The intermediate compound which links glycolysis with Krebs' cycle is malic acid
0%
One glucose molecule yields a net gain of 36 ATP molecules during aerobic respiration.
0%
One glucose molecule yields a net gain of 2 ATP molecules during glycolysis.

If volume of

${CO}_{2}$ liberated during respiration is more than the volume of

${O}_{2}$ used, then the respiratory substrate will be

0%
Carbohydrate
0%
Fat
0%
Protein
0%
Organic acid

Explanation

RQ slightly more than unity is found when organic acids are broken down as respiratory substrates under aerobic conditions, e.g. for the breakdown of oxalic acid liberation of

$CO_2$ is more than

$O_2$ .

$RQ=\frac{4{CO}_{2}}{{O}_{2}}=4.0$ .

So the correct option is D.

Select the correct option:

Refer to the following flow chart representing the cellular respiration and its fuels. Blanks 1,2,3,4,5,6 and 7 are respectively

0%
amino acids, carbohydrate, glucose, fats, glycerol, fatty acid, acetyl Co-A.
0%
fats, acetyl Co-A, amino acid, fatty acid, carbohydrate, glycerol, glucose.
0%
fatty acid, glucose, acetyl Co-A, glycerol, fats carbohydrate, amino acid.
0%
carbohydrate, fats, glycerol, fatty acids, amino acid, glucose, acetyl Co-A.

Refer to the given figure and select the correct option for A,B,C and D.

0%
A-Fats ; B- Proteins;C-3-PGAL ; D- AcetylCoA
0%
A-Fats ; B- Proteins;C-3-PGAL ;D- $CO_2$
0%
A-Proteins ; B- Fats ; C- Acetyl CoA ; D- PEP
0%
A-Proteins ; B- Fats ; C - PEP ;D - Acetyl CoA

Match column I with column II and select the correct option from the codes given below.

Column I	Column II
A. Krebs' cycle	(i) Inspiration
B. Lungs	(ii) Hamburger's phenomenon
C. Diaphragm	(iii) Diffusion of $CI^{-}$ into RBCs
D. Pons varolii	(iv) Mitochondria
E. Chloride shift	(v) Crural and costal
	(vi) Pneumotaxic centre
	(vii) Expiration

0%
A-(iv), B-(i), (vii), C-(v), D-(vi), E-(ii), (iii)
0%
A-(v), B-(i), C-(iv), (vii), D-(vi), E-(ii), (iii)
0%
A-(ii), (vi), B-(i), C-(iii), D-(v), (vii), E-(iv)
0%
A-(iii), B-(i), C-(ii), (v), D-(vi), (vii), E-(iv)

Which of the following options contains the end products formed during anaerobic respiration in Yeast?

0%
$H_2O, CO_2$ and energy
0%
$H_2S, C_6H_{12}O_6$ and energy
0%
$CO_2, C_2H_5OH$ and energy
0%
$H_2O$ and $CO_2$

In some biochemical reaction, two redox equivalents in the form of hydrogen atoms come out from PGAL and transferred to NAD

$^+$ , site of this process is

0%
Stroma of chloroplast
0%
Cytoplasm
0%
Mitochondrial matrix
0%
Outer membrane of mitochondria

Explanation

The given reaction is one of the step of glycolysis. Glycolysis takes place in the cytoplasm of the cell. Two redox-equivalents in the form of two hydrogen atoms come out from PGAL (phosphoglyceraldehyde) and transferred to a molecule of NAD

$^+$ . In this, PGAL is oxidized with inorganic phosphate to get form BPGA (biphosphoglyceric acid) and NADH

$_2$ is formed.

Thus, the correct answer is 'Cytoplasm'.

971205_1049641_ans_faa774dd0c7b485198ce0624020363d4.jpg

When the Respiratory Quotient (R.Q.) is greater than 1, it indicates

0%
Only aerobic respiration is taking place
0%
Only anaerobic respiration is taking place
0%
Both aerobic and anaerobic respiration are taking place
0%
None of these

Before entering the TCA cycle, pyruvic acid converted into acetyl CoA. This process is known as

0%
Oxidative carboxylation
0%
Oxidative dehydration
0%
Oxidative decarboxylation
0%
Reductive phosphorylation

Explanation

Before entering the TCA cycle, pyruvic acid converted into acetyl CoA. This process is known as oxidative decarboxylation. During this step, pyruvic acid loses one carbon atom with the release of carbon dioxide. In this step, NAD

$^+$ is converted into NADH. This step is catalyzed by pyruate dehydrogenase complex. The acetyl CoA then is converted to oxaloacetate, which enters the TCA cycle.

Thus, the correct answer is 'Oxidative decarboxylation.'

971218_1049648_ans_1277f028f78c4b1c878b0a949617660d.jpg

A Krebs cycle intermediate, which act as a raw material for chlorophyll production is synthesized after

0%
Condensation
0%
Substrate level phosphorylation
0%
Hydration
0%
Dehydrogenation

Explanation

Succinyl coenzyme A is utilized in the synthesis of porphyrin rings, used in heme manufacture and chlorophyll biosynthesis. It is synthesized from α-ketoglutarate by α-ketoglutarate dehydrogenase through oxidative decarboxylation. During this process, coenzyme A is added, and H

$^{+}$ and CO

$_{2}$ are released along.

α-Ketoglutarate + NAD

$^{+}$ + CoA-SH → Succinyl-CoA + NADH + H

$^{+}$ + CO

$_{2}$

So, the correct option is 'Dehydrogenation'.

Respiratory quotient may be represented as

0%
$O_2$ taken in $/ CO_2$ evolved
0%
$CO_2$ evolved $/O_2$ taken in
0%
$O_2$ taken in $/H_2O$ evolved
0%
$CO_2$ taken in $H_2O$ evolved

Explanation

The respiratory quotient is used for measurement of basal metabolic rate when estimated from CO

$_{2}$ production. It is measured using a respirometer and is calculated as the the ratio of CO

$_{2}$ produced by the body to O

$_{2}$ consumed by the body.

So, the correct option is 'CO

$_{2}$ evolved /O

$_{2}$ taken in'

By the aerobic respiration of one molecule of glucose, how many

$CO_2$ molecules produced in the mitochondria but outside the TCA cycle?

0%
$2$
0%
$4$
0%
$6$
0%
$12$

Explanation

The four steps of aerobic respiration are glycolysis, formation of acetyl coA, TCA cycle and the electron transport chain. In this, glycolysis takes place in the cytoplasm and TCA cycle takes place in the mitochondria. Before entering the TCA cycle, pyruvic acid is converted into acetyl CoA. This process is known as oxidative decarboxylation. During this step, 2 molecules of pyruvic acid lose one carbon atom each with the release of 2 molecules of carbon dioxide. In this step, 2 molecules of NAD

$^+$ are converted into 2 molecules of NADH. This step is catalyzed by pyruate dehydrogenase complex. The two molecules of acetyl CoA are then converted into 2 molecules of oxaloacetate, which enter the TCA cycle.

Thus, the correct answer is '2.'

971233_1049651_ans_82b8f02b5e8742c1a68e796cd774b942.gif

How many ATP are formed when 2 molecules of NADH + H+ formed in glycolysis enter the ETS via malate aspartate shuttle?

0%
Two
0%
Four
0%
Six
0%
Eight

Explanation

1 Molecules of NADH

$_2$ is equivalent 3 ATP molecules, since two NADH

$_2$ molecules are formed in the transition from glycolysis to malate aspartate shunt. Therefore, the number of ATP formed are

$2\times$ 3 =6

So, the correct answer is 'Six'

Match the number of carbon atoms given in column I with that of the compounds given in column II and select the correct option

	Column I		Column II
A	$4 C$ compound	1	Acetyl Co-A
B	$2 C$ compound	2	Pyruvate
C	$5 C$ compound	3	Citric acid
D	$3 C$ compound	4	$\alpha -$ ketoglutaic acid
		5	Malic acid

0%
A-2, B-5, C-3, D-1
0%
A-3, B-1, C-4, D-2
0%
A-5, B-1, C-4, D-2
0%
A-5, B-3, C-1, D-2

Explanation

A. Malic acid is a 4C compound and has the formula C

$_4$ H

$_6$ O

$_5$ .

B. Acetyl Co-A is a 2C compound and consists of two carbon units joined to Co-A.

C. α-ketoglutaric acid is a derivative of glutaric acid and is a 5C compound.

D. Pyruvate is a 3C compound and has the formula C

$_3$ H

$_4$ O

$_3$ .

So, the correct answer is 'A-5, B-1, C-4, D-2'.

Acetyl CoA connects

0%
EMP and Glycolysis
0%
Calvin cycle and EMP
0%
Glycolysis and Krebs cycle
0%
Krebs cycle and ETS

Explanation

The transition reaction connects glycolysis to Krebs cycle by a process called oxidative decarboxylation. Pyruvate (3-carbon molecule) from glycolysis is converted into acetyl-Coenzyme A (2-carbon molecule) and CO

$_{2}$ . When the two pyruvates undergo oxidative decarboxylation, two molecules of NAD

$^{+}$ become reduced to 2NADH + 2H

$^{+}$ which carry protons and electrons to the electron transport chain to generate additional ATP by oxidative phosphorylation. The two molecules of acetyl-CoA can now enter the citric acid cycle.

The overall reaction for the transition reaction is:

2 pyruvate + 2 NAD

$^{+}$ + 2 Coenzyme A → 2 acetyl-CoA + 2 NADH + 2 H

$^{+}$ + 2 CO

$_{2}$

So, the correct option is 'Glycolysis and Krebs cycle'.

Which one among the following is oxidative step of glycolysis?

0%
Phosphoglycerate $\rightarrow$ phosphoenol pyruvate
0%
Glyceraldehyde $3-$ phosphate $\rightarrow$ $1, 3-$ bis Phosphoglycerate
0%
Phospho enol pyruvate $\rightarrow$ pyruvate
0%
Fructose $1,6-$ bis phosphate $\rightarrow$ Triose phosphate

Number of oxygen atoms required for aerobic oxidation of pyruvate

0%
$5$
0%
$8$
0%
$10$
0%
$12$

Explanation

Two molecules of pyruvate are formed from the breakdown of glucose at the end of glycolysis. The pyruvate is then converted to acetyl CoA which is further oxidized in the mitochondria. Acetyl CoA enters Krebs cycle and is oxidized to

$CO_2$ ,

$H_2O$ ,

$ATP$ ,

$FADH_2$ and

$NADH^+$ . This complete oxidation of pyruvate requires 10 molecules of oxygen.

So, the correct answer is '10'

The number of ATP produced when one molecule of pyruvic acid is used as respiratory substrate in Kreb's cycle?

0%
$15$
0%
$12$
0%
$3$
0%
$36$

Metabolic fate of pyruvic acid depend on

0%
Cellular energy
0%
Availability of oxygen
0%
Type of respiration
0%
All of the above

What could be the reason for maida flour to increase in size?

0%
Fermentation
0%
Preservation
0%
Fumigation
0%
Both A and B

Pacemaker enzyme of EMP pathway is

0%
Hexokinase
0%
Pyruvate kinase
0%
Enolase
0%
Phosphofructokinase

Rearrange the sequential order as formed during the breakdown of glucose into pyruvate.

Glucose 6-phosphate, Fructose 6-phosphate, PGA, Pyruvate

0%
Glucose 6 phosphate $\rightarrow$ Fructose 6 phosphate $\rightarrow$ PGA $\rightarrow$ Pyruvate
0%
PyruvateGlucose 6 phosphate $\rightarrow$ Fructose 6 phosphate $\rightarrow$ PGA
0%
Pyruvate $\rightarrow$ Fructose 6 phosphate $\rightarrow$ Glucose 6 phosphate $\rightarrow$ PGA
0%
Glucose 6 phosphate $\rightarrow$ PGA $\rightarrow$ Fructose 6 phosphate $\rightarrow$ Pyruvate

In how many steps, glycolysis can be regulated?

0%
One
0%
Two
0%
Three
0%
Four

How many molecules of ATP are require in glycolysis to change one molecule of glucose to pyruvic acid?

0%
1
0%
4
0%
2
0%
3

In aerobic respiration the Kreb's cycle occurs inside the

0%
Chloroplast
0%
Cytoplasm
0%
Mitochondria
0%
Ribosome

In anaerobic respiration of yeast

0%
${ O }_{ 2 }$ is given out
0%
${ CO }_{ 2 }$ is given out
0%
${ CO }_{ 2 }$ is taken in
0%
${ O }_{ 2 }$ is taken in

Explanation

Yeast respires anaerobically (in the absence of oxygen) . The process is known as fermentation. Glucose is the respiratory substrate.

The glucose is converted to pyruvate by the process of glycolysis. This process is independent of oxygen. If oxygen is absent, the pyruvate is broken by yeast into ethanol releasing carbon dioxide along with the production of 2 ATP.

So, the correct answer is 'CO

$_2$ is given out'.

How many total dehydrogenetaion occur in citric acid cycle :-

0%
One
0%
Two
0%
Three
0%
Four

Which one is not correct with given marks?

0%
B-carboxylation- fixation of $CO_2$ the aldose sugar
0%
C- reduction - reverse of glycolysis
0%
A- regeneration - reformation of pentose sugar
0%
C- reduction - carbohydrate formation

At how many step there occurs substrate level phosphorylation in glycolysis?

0%
One
0%
Two
0%
Three
0%
Four

Which of the following statements regarding pyruvate during aerobic respiration is incorrect?

0%
It is formed by the glycolytic catabolism of carbohydrates in the mitochondrial matrix.
0%
It enters mitochondrial matrix and undergoes oxidative decarboxylation.
0%
The conversation of pyruvic acid to acetyl CoA is catalyzed by pyruvic dehydrogenase.
0%
Two molecules of NADH are produced from the metabolism of one glucose into two molecules of pyruvic acid.

What is fermentation?

0%
Storing of sugar
0%
Breaking of sugar
0%
Streaming of sugar
0%
Boiling of sugar

Explanation

Fermentation is anaerobic respiration that does not require oxygen for the breakdown (breaking of sugar) and transformation of organic nutrients.
Fermentation is controlled by enzymes.
The common product of fermentation are ethanol, CO $_2$ , and lactic acid.
Some amount of energy is also produced in the process of fermentation.
So, the correct answer is option B.

Compensation point is the value of the factor where there is

0%
Neither photosynthesis nor respiration
0%
Little photosynthesis
0%
Photosynthesis is equal to the rate of respiration
0%
Beginning of photosynthesis

The respiratory quotient during cellular respiration would depend upon

0%
Amount of $CO_{2}$ released
0%
Amount of $O_{2}$ utilized
0%
The nature of enzyme in invoked
0%
Nature of substrate
0%
Both (a) and (b)

Explanation

The respiratory quotient (R.Q) is the ration of the volume of the CO

$_{2}$ released to the volume of the O

$_{2}$ utilized by a substrate during the process of respiration. It solely depends on the nature of the substrate. The R.Q. reflect the nature of the substrate, for example, R.Q. 1 indicated that glucose is the respiratory substrate.

Hence, the correct answer is 'Nature of substrate'.

Connecting link between respiration (TCA cycle) and protein synthesis is

0%
Citric acid
0%
$\alpha$ - ketoglutaric acid
0%
Succinic acid
0%
Fumaric acid

CBSE Questions for Class 11 Medical Biology Respiration In Plants Quiz 14 - MCQExams.com

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Practice Class 11 Medical Biology Quiz Questions and Answers

CBSE Questions for Class 11 Medical Biology Respiration In Plants Quiz 14 - MCQExams.com

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Practice Class 11 Medical Biology Quiz Questions and Answers

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