Explanation
Solution
Correct answer is option A.
Explanation for correct option:
Correct answer: A
Option (A):
∙ Glycolysis is the first part of cellular respiration which occurs in both aerobic and anaerobic respiration.
∙ The end product of glycolysis is pyruvate. Pyruvate is oxidized to produce acetyl CoA.
∙ This acetyl CoA enters the Krebs cycle which occurs in the mitochondrial membrane. So, acetyl CoA acts as the connecting link between the two processes.
Option (B):
∙ Oxaloacetic acid is a residue which is part of the Krebs cycle and it is not the connecting link.
Option (C):
∙ Pyruvic acid is the end product of glycolysis and it needs to be oxidized.
∙ Pyruvate is not able to enter the Krebs cycle directly.
Option (D):
∙ Citrate is one of the intermediates in the Krebs cycle.
Hence, the correct answer is option (A).
Correct Option C
∙ Option A Option A. When the phosphate bond of creatine phosphate is hydrolyzed is a yield of high free energy. The reason for this high free energy is the difference between the free energies of the reactants and the products.
∙ Option B ADP is hydrolyzed the free energy released during the reaction is around a range of 7.3 Kcal/mol.
∙ Option C During the hydrolysis of glucose 6 phosphate the yield of free energy have a negative value which is around -3.3 Kcal/mol.
∙ Option D Reaction of hydrolysis of the phosphate found in ATP the range of the free energy released is 7.3 Kcal/mol.
So, the correct option is C.
Please disable the adBlock and continue. Thank you.