Explanation
Solution
Correct answer is option A.
Explanation for correct option:
Correct answer: ACorrect answer: A
Option (A):Option (A):
∙∙ Glycolysis is the first part of cellular respiration which occurs in both aerobic and anaerobic respiration.
∙∙ The end product of glycolysis is pyruvate. Pyruvate is oxidized to produce acetyl CoA.
∙∙ This acetyl CoA enters the Krebs cycle which occurs in the mitochondrial membrane. So, acetyl CoA acts as the connecting link between the two processes.
Option (B):Option (B):
∙∙ Oxaloacetic acid is a residue which is part of the Krebs cycle and it is not the connecting link.
Option (C):Option (C):
∙∙ Pyruvic acid is the end product of glycolysis and it needs to be oxidized.
∙∙ Pyruvate is not able to enter the Krebs cycle directly.
Option (D):Option (D):
∙∙ Citrate is one of the intermediates in the Krebs cycle.
Hence, the correct answer is option (A).
Correct Option CCorrect Option C
SolutionSolution
∙∙ Option AOptionA Option A. When the phosphate bond of creatine phosphate is hydrolyzed is a yield of high free energy. The reason for this high free energy is the difference between the free energies of the reactants and the products.
∙∙ Option BOptionB ADP is hydrolyzed the free energy released during the reaction is around a range of 7.3 Kcal/mol.
∙∙ Option COption C During the hydrolysis of glucose 6 phosphate the yield of free energy have a negative value which is around -3.3 Kcal/mol.
∙∙ Option DOptionD Reaction of hydrolysis of the phosphate found in ATP the range of the free energy released is 7.3 Kcal/mol.
So, the correct option is C.
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