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CBSE Questions for Class 12 Engineering Chemistry The P-Block Elements Quiz 14 - MCQExams.com
CBSE
Class 12 Engineering Chemistry
The P-Block Elements
Quiz 14
The electronic configuration of chlorine is _________
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0%
2, 7
0%
2, 8, 8, 7
0%
2, 8, 7
0%
2, 7, 8
In which of the following, oxidation number of chlorine is
+
5
?
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0%
C
l
2
O
7
0%
C
l
O
−
3
0%
C
H
O
−
0%
C
l
O
−
4
Explanation
Oxidation number of
C
l
2
O
7
:-
2
x
−
14
=
0
x
=
7
Oxidation number of
C
l
O
3
−
:-
x
−
6
=
−
1
x
=
5
Oxidation number of
C
l
O
−
:-
x
−
2
=
−
1
x
=
1
Oxidation number of
C
l
O
4
−
:-
x
−
8
=
−
1
x
=
7
hence option B is correct.
Which of the following compounds undergoes haloform reaction?
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0%
C
H
3
C
O
C
H
3
0%
H
C
H
O
0%
C
H
3
C
H
2
B
r
0%
C
H
3
−
O
−
C
H
3
Explanation
The haloform reaction comprises the reaction of a halogen with a methyl ketone (a molecule containing the
R
–
C
O
–
C
H
3
grouping) in the presence of a base.
Among the given compound, propanone undergoes haloform reaction as it contains a methyl group attached to carbonyl carbon.
Hence, option A is correct.
Which of the following is correct statement regarding
N
(
C
H
3
)
3
and
N
(
S
i
H
3
)
3
?
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0%
N
(
S
i
H
3
)
3
is planar and more basic than
N
(
C
H
3
)
3
0%
N
(
S
i
H
3
)
3
is planar and less basic than
N
(
C
H
3
)
3
0%
N
(
C
H
3
)
3
is planar and more basic than
N
(
S
i
H
3
)
3
0%
N
(
C
H
3
)
3
is pyramidal and less basic than
N
(
S
i
H
3
)
3
Explanation
N
(
S
i
H
3
)
3
is planar due to back bonding and
N
(
C
H
3
)
3
more basic due to presence of lone pair electrons.
What is the action of following reagents on ammonia ?
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0%
i)Excess of air
0%
ii)Excess of chlorine
0%
iii)Na metal
0%
none of these
Which of the following is incorrect?
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0%
Red
P
is toxic
0%
White
′
P
′
is highly soluble in
C
S
2
0%
Black
′
P
′
is thermodynamic is most stable
0%
White
′
P
′
is soluble in
N
a
O
H
evolves
P
H
3
Explanation
Red P is not considered as toxic in its pure form.
Which of the following is true for
N
2
O
5
?
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0%
Paramagnetic
0%
Anhydride of
H
N
O
2
0%
Brown gas
0%
Exist in solid In form of
[
N
O
+
2
]
[
N
O
−
3
]
Explanation
N
2
O
5
in solid form exists as
N
O
−
3
and
N
O
−
2
.
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2
3
4
5
6
7
1
2
3
4
5
6
7
0
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1
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Incorrect : 0
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