Explanation
F(x) is clearly continuous and differentiable at x = 0 zero with f`(0) = 0.
\displaystyle f\, (0)\, =\, \lim_{h \rightarrow 0} \frac{3h^2\, \sin \frac{1}{h}\, -\, h\, \cos \frac{1}{h}}{h} \displaystyle =\, 3h\sin\frac{1}{h}\, -\, \cos \frac{1}{h}
This limit doesn't exist, hence f(x) is non-differentiable at x = 0.
Also \displaystyle \lim_{x \rightarrow 0}\, f`(x)\, =\, 0.
Thus f`(x) is continuous at x = 0.
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