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CBSE Questions for Class 12 Commerce Applied Mathematics Probability Distribution And Its Mean And Variance Quiz 8 - MCQExams.com
CBSE
Class 12 Commerce Applied Mathematics
Probability Distribution And Its Mean And Variance
Quiz 8
Consider the following probability distribution :
$$X_{i}$$
$$1$$
$$3$$
$$5$$
$$6$$
$$P_{i}$$
$$0.1$$
$$0.2$$
$$0.4$$
$$0.3$$
Then $$E(X)=$$
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0%
$$4.5$$
0%
$$5.5$$
0%
$$6.5$$
0%
$$7.5$$
P(x) is a polynomial satisfying P(x+3/2)=p(x) for all real values of x. If P(5)=2010, what is the value of P(8)
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0%
$$2008$$
0%
$$2009$$
0%
$$2010$$
0%
None of these
For the following probability distribution.
$$X=x$$
$$1$$
$$0$$
$$4$$
P
$$1/2$$
$$3/8$$
$$1/8$$
The value of $$E[X-E(X)]$$ is?
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0%
$$1$$
0%
$$1/2$$
0%
$$0$$
0%
$$1/4$$
The following is the c.d.f. of a discrete r.v. X:
X
$$-3$$
$$-1$$
$$0$$
$$1$$
$$3$$
$$5$$
$$7$$
$$9$$
$$F(x)$$
$$0.1$$
$$0.3$$
$$0.5$$
$$0.65$$
$$0.75$$
$$0.85$$
$$0.90$$
$$1$$
Find $$P(X =-3/X < 0)$$.
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0%
$$0.3333$$
0%
$$0.35$$
0%
$$0.55$$
0%
$$0.25$$
Explanation
$$\alpha_i$$
$$f(x)$$
$$P(X = x_i)$$
$$-3$$
$$-1$$
$$0$$
$$1$$
$$3$$
$$5$$
$$7$$
$$9$$
$$0.1$$
$$0.3$$
$$0.5$$
$$0.65$$
$$0.76$$
$$0.85$$
$$0.90$$
$$1$$
$$0.1$$
$$0.2$$
$$0.2$$
$$0.15$$
$$0.1$$
$$0.1$$
$$0.05$$
$$0.1$$
$$P\left( X=-3\right) =0.1$$
$$\Rightarrow P\left( X<0\right) =P\left( X=-1\right) +P\left( X=-3\right)$$
$$=0.2+0.1$$
$$\Rightarrow \dfrac{P\left( X=-3\right)}{P\left( X<0\right) }=\dfrac{0.1}{0.3}=0.3333$$
Hence, the answer is $$0.3333.$$
Two cards are drawn successive with replacement from a pack of cards. Taking the random variable X= the variance of X is
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0%
$$\dfrac{2}{13}$$
0%
$$\dfrac{9}{13}$$
0%
$$\dfrac{24}{169}$$
0%
$$\dfrac{1}{13}$$
X is a continuous random variable with probability density function
$$f(x) = 3 (1 - 2x^2)$$ ; 0 < x < 1
= 0 ; otherwise
Then, value of $$P \left(\dfrac{1}{4} < X < \dfrac{1}{3} \right)$$ is
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0%
$$\dfrac{128}{752}$$
0%
$$\dfrac{331}{752}$$
0%
$$\dfrac{165}{864}$$
0%
$$\dfrac{179}{864}$$
if $$P(X=x)=C \left(\dfrac{2}{3}\right)^{x}; x=1,2,3,4,.......$$ is a probability mass function, the value of $$C$$ is
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0%
$$\dfrac{1}{4}$$
0%
$$\dfrac{1}{3}$$
0%
$$\dfrac{1}{2}$$
0%
$$\dfrac{1}{6}$$
If the range of a random variable $$X$$ is $${0,\ 1,\ 2,\ 3,....}$$ with $$P{X=K}=\dfrac {(k+1)a}{3^{k}}$$ for $$k\ge 0$$, then $$a=$$
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0%
$$2/3$$
0%
$$4/9$$
0%
$$89/27$$
0%
$$16/81$$
The c.d.f of a discrete r.v X is
Then $$P\left(X=-3|X<0\right)$$
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0%
$$0.3333$$
0%
$$0.35$$
0%
$$0.55$$
0%
$$0.25$$
Two coins are tossed 1000 times and the outcomes are recorded as below:
Number of heads
2
1
0
Frequency
200
550
250
Based on this information, the probability for atmost one head is
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0%
$$\frac{1}{5}$$
0%
$$\frac{1}{4}$$
0%
$$\frac{4}{5}$$
0%
$$\frac{3}{4}$$
A fair die is tossed repeatedly until a 6 is obtained. Let X denote the number of tosses required.
The probability that $$x \geq 3$$ equals
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0%
125/216
0%
25/36
0%
5/36
0%
25/216
An unbiased coin is tossed n times. Let X denote the number of times head occurs. If P(X=4), P(X=5) and P(X=6) are in AP, then the value of n can be
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0%
9
0%
10
0%
12
0%
14
$$f(x)=k\sqrt {k}, 0 < x < 1=0$$, otherwise is p.d.f of $$X$$. Then $$P(0.3 < X < 0.6)=$$ ____
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0%
$$(0.6-0.3)^{\dfrac {3}{2}}$$
0%
$$(0.3-0.6)^{\dfrac {3}{2}}$$
0%
$$(0.6)^{\dfrac {3}{2}}-(0.3)^{\dfrac {3}{2}}$$
0%
$$(0.3)^{\dfrac {3}{2}}-(0.6)^{\dfrac {3}{2}}$$
Three coins are thrown simultaneously 60 times, with the following frequencies:
No. of heads
3
2
1
0
Frequency
10
5
18
27
Based on these information find the probability of
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0%
P (getting 3 heads)
0%
P (getting no heads)
0%
P (at most 1 head)
0%
P (at least 1 head)
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