Explanation
Converting the given inequations into equations$$x + y = 3$$ …..(1)$$y = 6$$ …..(2)Region represented by $$x + y \leq 3$$ : The line $$x + y = 3$$ meets the coordinate axes are $$A(3,0)$$ and $$B(0,3)$$ respectively,$$x + y = 3$$
Region represented by $$y \leq 6$$: The line $$y = 6$$ is parallel to the x-axis and its every point will satisfy the inquation in first quadrant, region containing the origin represents the solution set of this inequation.$$A(3, 0); B(0, 3)$$Join points A and B to obtain the line. Clearly, $$(0, 0)$$ satisfies the inequation $$x + y \leq 3$$. So, the region containing the origin represent the solution set of the inequation.
Region represented by $$x \geq 0$$ and $$y \geq 0$$: Since every point in the first quadrant satisfy the inequations, so the first quadrant is the solution set of these inequations.
The shaded region is the common region of inequations. This is a feasible region of solution which is bounded and is in the first quadrant.Hence the region is bounded and is in the first quadrant.∴ Answer (c) is correct.
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