Explanation
Let $$ 2x -5 = y $$
Given, $$\left | y \right |< 1$$$$ => \left | y \right | - 1 < 0 $$Now, when $$ y > 0 $$ , we have $$ \left | y \right | = y $$So, $$ y - 1 < 0 $$ $$ => y < 1$$
$$ => 2x - 5 < 1 $$
$$ => x < \dfrac {6}{2} = 3 $$ -- (1)
And when $$ y < 0 $$ , we have $$ \left | y \right | = - y $$
So, $$ -y-1 < 0 $$
$$ y > -1 $$
$$ => 2x -5 > -1 $$
$$ => x > 2 $$ -- (2) From $$ (1), (2) ; x \in (2, 3) $$
$$ \dfrac {3x+2}{2x+3} \ge 4 $$
$$ => \dfrac {3x+2}{2x+3} - 4 \ge 0 $$
$$ => \dfrac {3x+2 -8x-12 }{2x + 3} \ge 0 $$
$$ \dfrac {-5x-10}{2x + 3 } \ge 0 $$
$$ \dfrac {5x + 10}{2x + 3 } \le 0 $$
Now, $$ 5x+ 10 \ge 0 $$ and $$ 2x + 3 < 0 $$
=> $$ x \ge -2$$ and $$ x < -\dfrac {3}{2} $$
Thus, $$x\in \left [ -2, -\dfrac{3}{2} \right )$$
In the given ratios "B" is thecommon term, and the values of B in both ratios are not equal. To make themequal, find the L.C.M. of values corresponding to B i.e., $$ 4 $$ and $$ 6 $$.L.C.M. of $$ 4 $$ and $$ 6 = 12 $$Therefore, an equivalent ratio of $$ A:B = 3:4 = 3 \times 3:4 \times 3 = 9:12 $$
Similarly, an equivalent ratio of $$ B:C = 6:7 = 6 \times 2:7 \times 2 = 12:14 $$Therefore, $$ A:C = 9:14 $$
Similarly, an equivalent ratio of $$ B:C = 6:7 = 6 \times 2:7 \times 2 = 12:14 $$Therefore,$$ A: B:C = 9:12:14 $$
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