Explanation
Step - 1: Finding n, p and q
We know that, mean = np and variance = np(1 - p)
∴ np = 2 and np(1 - p) = 1
Dividing, np(1 - p)np = 12
⇒ 1 - p = 12
⇒ p = 12
∵ q = 1 - p
⇒ q = 1 - 12
⇒ q = 12
Substituting value of p in np = 2
⇒ n × 12 = 2
⇒ n = 4
Step - 2: Calculating probability
Probability of value greater than 1, P(X > 1) = 1 - P(X = 0) - P(X = 1)
⇒ P(X > 1) = 1 - 124 - 4C1124
⇒ P(X > 1) = 1 - 116 - 416
⇒ P(X > 1) = 1 - 516
⇒ P(X > 1) = 1116
Hence option A is correct
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