MCQ Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 11

An organic compound containing

$-COOH$ functional group is called:

0%
aldehyde
0%
ketone
0%
amide
0%
carboxylic acid

Explanation

The compound containing

$-COOH$ as the functional group are called the carbonyl group. These groups are polar in nature because it acts both as hydrogen bond acceptor and hydrogen bond donors.

Explanation

Since

$LiAlH_4$ is very strong reducing agent, it reduces

$\alpha - \beta$ unsaturated double bond also of aldehyde due to strong polarization towards double bond.
987175_1067411_ans_aa6ce47b567441b09e30ad593e736dd3.PNG

987175_1067411_ans_aa6ce47b567441b09e30ad593e736dd3.PNG

The suitable reagent(s) will be:

0%
$CrO/{H}_{2}O/$ acetone
0%
$[Ag(NH_3)_2)^{\oplus} (aqueous), H^+$
0%
$CrO/HCl/$ pyridine
0%
$\overset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,COONa}{\overset{|}{\underset{\!\!\!\,\,\,\,\,\,\,\,\,\,\,\,COOK}{\underset{|}{(CHOH)_2}}}} + CuSO_4 + NaOH, \, H^+$

Explanation

Since aldehyde undergo fast silver mirror test to give corresponding acids and other groups do not react with Tollen's reagent, so it is better.

$R - CHO \xrightarrow{[Ag (NH_3)_2 ^{\oplus}] OH^-} R - COOH$

Corrosive sublimate (

$Hg{Cl}_{2}$ ) can be used to distinguish between:

0%
formaldehyde and propanone
0%
formic acid and acetic acid
0%
acetaldehyde and butanone
0%
all of the above

Explanation

Option

$B$ is the correct answer.

Formic acid gives white precipitate with

$HgCl_2$ but acitic acid does not react.

$HCO_2H+2HgCl_2\longrightarrow \underset{\text{white precipitate}}{Hg_2Cl_2\downarrow} +2HCl+CO_2\uparrow$

$CH_3COOH\xrightarrow[]{HgCl_2}\text{ No precipitate of }Hg_2Cl_2$

Formic acid acts as a reducing agent.

Which of the following compounds will give butanone on oxidation with alkaline

$KMn{O}_{4}$ solution?

0%
Butan-1-ol
0%
Butan-2-ol
0%
2-methylpropan-2-ol
0%
None of these

Odd one out among the following is:

0%
Tartaric acid
0%
Oxalic acid
0%
Citric acid
0%
Prussic acid

Explanation

Since all are acid having

$COOH$ functional group except Prussic acid which is

$HCN$ .

Structure of

$(x)$ is:

$C$ . Compound

$(3)$ is:

Most acidic hydrogen is present in :

0%
0%
0%
$(CH_{3}CO)_{3}CH$
0%
$(CH_{3})_{3}COH$

The product of following reaction is:

Which of the following reactions is/are not correct to get cinnamic acid?

0%
$C_{6}H_{5}CHO\xrightarrow [ \left( { CH }_{ 3 }CO \right) _{ 2 }O/CH_{ 3 }COONa ]{ }$
0%
$C_{6}H_{5}CHO\xrightarrow[{2)H_{3}O^{+},\Delta} ] {1)CH_{2}(COOC_{2}H_{2})_{2},pyridine}$
0%
$C_{6}H_{5}CHO\xrightarrow{CH_{3}CHO/OH^{-}}{}$
0%
$C_{6}H_{5}CHO\xrightarrow[{2)H_{2}O/H^{+}/ \Delta}]{1)BrCH_{2}COOC_{2}H_{3}/ZnI \Delta}$

Explanation

The correct option is

$A$ .

The reaction of

${ C }_{ 6 }{ H }_{ 5 }CHO$ and

$(C{ H }_{ 3 }CO{ ) }_{ 2 }O/C{ H }_{ 3 }COONa$ does not give cinnamic acid

Which will form two oximes with

$NH_{2}OH$ ?

0%
$CH_{3}CHO$
0%
$CH_{3}COCH_{2}CH_{3}$
0%
$HCHO$
0%
$CH_{3}COCH_{2}CH_{2}CH_{2}$

$CH_{3}CH=CHCHO\overset { { OH }^{ - } }{ \underset { Aldol }{ \longrightarrow } } { }A$ ,

$A$ is?

0%
$CH_{3}(CH=CH)_{3}CHO$
0%
$CH_{3}CH_{2}CH_{2}(CH=CH)_{2}CHO$
0%
$CH_{3}(CH_{2}CH_{2})CH=CH-CHO$
0%
$None\ of\ the\ above\ is\ correct$

Explanation

$CH_3-CH=CH-CHO\overset {\overset {\circleddash}{O}H/\Delta}{\underset {Aldol}{\longrightarrow}}CH_3(CH=CH)_3CHO$
This reaction is known as aldol condensation reaction.

________ is used in the preparation of chloroform, sulphonal, cordite etc.

0%
formalin
0%
ethyl alcohol
0%
acetone
0%
none of these

Explanation

Preparation of chloroform from acetone is:

$CaOCl_2+H_2O\longrightarrow Ca(OH)_2+Cl_2$

$CH_3COCH_3+3Cl_2\longrightarrow CCl_3COCH_3+3HCl$

$2CCl_3COCH_3+Ca(OH)_2\longrightarrow 2CHCl_3+(CH_3COO)_2Ca$

Preparation of sulphonal from ketone is shown in IMAGE

$01$

Preparation of cordite is shown in Image

$02$

Cordite is a propellant which is addition product of ketone.

Hence, above all are prepared from acetone.

Formaldehyde is used :

0%
for preserving biological specimens
0%
for the preparation of urotropine
0%
in the manufacture of bakelite
0%
all of these

Which of the following statement is true?

0%
Benzaldehyde is used in perfumery industry
0%
Formaldehyde is used for silvering mirrors
0%
Acetone is used as a commercial solvent
0%
All of the above

Which of the following is used as an acid bath in dyeing cotton and wool?

0%
Methanoic acid
0%
Acetic acid
0%
Benzoic acid
0%
Sulphuric acid

Which of the following chemical is used in removing ink stain from clothes?

0%
Ethyl alcohol
0%
Glycol
0%
Banzoic acid
0%
Oxalic acid

Which acid is used in medicine for the treatment of gout?

0%
Hydrochloric acid
0%
Methanoic acid
0%
Ethanoic acid
0%
None of these

Find a wrong statement from the given statements.

0%
oxalic acid is used for making metal polish
0%
benzoic acid is used in manufacture of dyes
0%
oxalic acid in form of ferrous potassium oxilate used as developer in photography
0%
benzoic acid is used for making metal polish

Which of the following is correct?

0%
Formic acid is used in medicine for the treatment of gout
0%
Propanoic acid is used as an antiseptic in the preservation of fruit juice
0%
Ethanoic acid is a coagulating agent in rubber industry
0%
None of these

Which acid is used in rubber industry as a coagulating agent?

0%
Methanoic acid
0%
Ethanoic acid
0%
Propanoic acid
0%
Butanoic acid

Which of the following chemical is used in making metal polishes:

0%
oxalic acid
0%
methanoic acid
0%
both A and B
0%
none of these

Tollen's reagent is:

0%
ammoniacal cuprous chloride
0%
ammoniacal cuprous oxide
0%
ammoniacal silver nitrate
0%
ammoniacal silver chloride

Explanation

Explanation:

Tollens reagent is ammoniacal silver nitrate.

It is also called a silver mirror test reagent.

It is used to detect the aldehyde functional group in a compound. Upon addition into the test tube containing aldehyde, it produces dark grey ppt or a silver mirror-like appearance.

Welcome to Chem Zipper.com......: What is Tollen's reagent?

Correct Option: $C$

Which acid is used as table vinegar?

0%
Formic acid
0%
Acetic acid
0%
Picric acid
0%
None of these

Which of the following is not a use of benzoic acid?

0%
Food preservative
0%
Anticeptic
0%
In manufacture of dye
0%
In metal polish

Acid present in honey bee sting is:

0%
formic acid
0%
propanoic acid
0%
butanoic acid
0%
none of these

The product C is:

Explanation

Then $N_2H_4$ attacks $B$ , which breaks the outer ring and forms two $-CONH_2$ groups

In a balanced equation , all the moles of different elements remains same hence,

$Ba + 2HCl \rightarrow Bacl_2 + H_2$

Is a balanced equation as there is one mole of $Ba$ and $2$ moles each of hydrogen and chlorine

1107882_1089498_ans_681d04e795cb42b98a581dc8581da844.png

Select the best way for reducing the

$C=O$ group in each of the following:

Which of the following set of reaction can not prepare

$R-\overset{O}{\overset{||}{C}}-OH$ as the final product?

0%
$R-MgX + O = C = O \xrightarrow{dry. ether} A \xrightarrow{H_3O^+}$
0%
$R-CN \xrightarrow[(ii) \, H_2O / H^+]{SnCl_2+HCl}$
0%
0%
$CH_3(CH_2)_8CH_2OH \xrightarrow[H_2SO_4]{CrO_3}$

Explanation

$R-CN \xrightarrow[ii) H_3O^{\oplus}]{i) ZnCl_2 + HCl} R-\overset{NH}{\overset{||}{C}}-H \xrightarrow{H_3O^{\oplus}} R- \overset{O}{\overset{||}{C}} - H$

This reaction doesn't produce

$R - \overset{O}{\overset{||}{C}} -OH$

The Compound E is:

Which of the following molecules contain more enol content at equilibrium?

0%
$OHC - CH_2 - CHO$
0%
$CH_3COCH_2COOCH_3$
0%
$CH_2(COOH)_2$
0%
$CH_3COCH_3$

When o-xylene is oxidised with alkaline

$KMnO_4$ , the product is:

0%
Terephthalic acid
0%
Phthalic acid
0%
Benzoic acid
0%
Salicylic acid

The acidity of alpha hydrogen of the carbonyl group is due to:

0%
The aldehydes and ketones undergo a number of reactions due to the acidic nature of $\alpha-hydrogen$ .
0%
The acidity of $\alpha-hydrogen$ atoms of carbonyl compounds is due to the strong electron withdrawing effect of the carbonyl group and resonance stabilization of the conjugate base.
0%
both A and B
0%
none of these

Which of the following is nucleophilic addition reaction?

0%
$CH_3COCl \xrightarrow {CH_3MgBr\ (1 eq.)} CH_3COCH_3$
0%
$CH_3COCH_3 \xrightarrow{I_2/OH^-/\triangle} CH_3COO^-+CHI_3$
0%
$PhCHO \xrightarrow{KCN/H^{\oplus}} PhCH(OH)(CN)$
0%
$CH_3C \equiv CMgBr \xrightarrow{CH_3Br}CH_3C\equiv CCH_3$

Explanation

$KCN$ adds to the carbonyl group of benzaldehyde.

Cyanide ion acts as nucleophile. This is followed by acid hydrolysis to form cyanohydrin.

Hence, the reaction

$PhCHO \xrightarrow{KCN/H^{\oplus}} PhCH(OH)(CN)$ is a nucleophilic addition reaction.

In option A the Grignard reagent which acts as nucleophile and adds across

$-C=O$ bond hence it is also nucleophillic addition.

Options A and C are correct.

The compound

$(S)$ is:

The compound (X) is:

0%
$PhCOONa$
0%
0%
0%
$Ph - CH = CH - Ph$

What will be the product of the following reaction :
(according to OPTIONS in the image shown)

0%
B
0%
C
0%
D
0%
A

Identify

$X$ in the following reaction.

A carbonyl compound '

$A$ ' reacts with hydrogen cyanide to form a cyanohydrin '

$B$ ' which on hydrolysis gives an optically active alpha-hydroxy acid '

$C$ '. '

$C$ ' also gives a positive iodoform test.

$A$ ', '

$B$ ' and '

$C$ ' is given by the set:-

0%
$HCHO$ ;
0%
$CH_{3}CHO$ ;
0%
$CH_{3}CH_{2}CHO$
0%

Which of the following is most reactive to give nucleophilic addition ?

0%
FCH $_2$ CHO
0%
ClCH $_2$ CHO
0%
BrCH $_2$ CHO
0%
ICH $_2$ CHO

R and S are:

0%
I only
0%
I and II
0%
III only
0%
None of these
0%
Blank

Explanation

Benzene undergo Friedal crafts acylation reaction to produce acetophenune, it form

$1$ - phenyl,

$1-, 3$ - butanedione. After halogenation reaction it produce iodoform and sodium containing salt.
1073812_330536_ans_e26ba1b9efcd47688b5ffbd0860a1398.png

1073812_330536_ans_e26ba1b9efcd47688b5ffbd0860a1398.png

Compound

$(C)\;\xrightarrow{P_4O_{10}}\;Product\;(F)$

The product

$F$ may be:

0%
Malonic anhydride
0%
Ethanoic anhydride
0%
Ethanal
0%
A lactone

The number of

$sp^2$ hybridized carbon atoms in the given compound is:

0%
3
0%
4
0%
5
0%
6

Explanation

$sp^{2}$ hybridised carbon must be attached with a double.

Here in the given compound, there were

$3$ carbon atoms attached with a double bond. So there were

$3$

$sp^{2}$ hybridised carbon atoms.

Hence option

$A$ is correct.

The final product

$(Y)$ in the following sequence of chemical reaction is:

$CH_3OH\xrightarrow[300^oC]{Cu} X \xrightarrow{NaOH} Y + CH_3OH$

0%
an alkene
0%
a carboxylic acid
0%
an aldehyde
0%
sodium salt of carboxylic acid

Explanation

$CH_3OH \xrightarrow[300^oC]{Cu} {\underset{(X)}{HC}HO}\xrightarrow{NaOH}\underset{(Y)}{HCOONa}+CH_3OH$

First reaction is oxidation reaction.

Second step the Cannizzaro reaction takes place.

Option D is correct.

When a nucleophile encounters a ketone, the site of attack is:

0%
the carbon atom of the carbonyl
0%
the oxygen atom of the carbonyl
0%
both the carbon and oxygen atoms, with equal probability
0%
no attack occurs as ketones do not react with nucleophiles

Identify

$(X),\ (Y)$ and

$(Z)$ in the given reaction.

$CH_3CHO \xrightarrow[H_2SO_4]{K_2Cr_2O_7}(X) \xrightarrow{PCl_5}(Y) \xrightarrow[anh.AlCl_3]{C_6H_6}(Z)$ :

0%
$(X) = HCOOH,\,\,\, (Y) = COCl_2, \,\,\, (Z) = C_6H_5Cl$
0%
$(X) = CH_3COOH,\,\,\, (Y) = CH_3COCl, \,\,\, (Z) = C_6H_5COCH_3$
0%
$(X) = CH_3COOH,\,\,\, (Y) = CH_3CH_2CH_2Cl, \,\,\, (Z) = C_6H_5CH_2CH_2CH_3$
0%
$(X) = CH_3COCH_3,\,\,\, (Y) = CH_3CH(Cl)CH_3, \,\,\, (Z) = C_6H_5COCH_3$

Explanation

Hence, option

$B$ is correct.

The correct order of

$pK_a$ for the following acid:

Oxalic acid

$pK_1$
Monalic acid

$pK_2$
Heptanedioic acid

$pK_3$

where

$pK_1$ ,

$pK_2$ ,

$pK_3$ are first ionization constants.

0%
$pK_1$ > $pK_2$ > $pK_3$
0%
$pK_1$ < $pK_2$ < $pK_3$
0%
$pK_3$ > $pK_2$ = $pK_1$
0%
$pK_3$ > $pK_1$ > $pK_2$

Identify

$(X)$ and

$(Y)$ in the given reaction sequence.

Which of the following compounds is most reactive towards nucleophilic addition reactions?

0%
$CH_3-{\overset{O}{\overset{||}{C}}}-CH_3$
0%
$CH_3-{\overset{O}{\overset{||}{C}}}-H$
0%
0%

CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 11 - MCQExams.com

0:0:1

Practice Class 12 Engineering Chemistry Quiz Questions and Answers

CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 11 - MCQExams.com

0:0:1

Practice Class 12 Engineering Chemistry Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.