MCQ Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 11

An organic compound containing

$-COOH$ functional group is called:

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aldehyde
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ketone
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amide
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carboxylic acid

Explanation

The compound containing

$-COOH$ as the functional group are called the carbonyl group. These groups are polar in nature because it acts both as hydrogen bond acceptor and hydrogen bond donors.

Explanation

Since

$LiAlH_4$ is very strong reducing agent, it reduces

$\alpha - \beta$ unsaturated double bond also of aldehyde due to strong polarization towards double bond.
987175_1067411_ans_aa6ce47b567441b09e30ad593e736dd3.PNG

987175_1067411_ans_aa6ce47b567441b09e30ad593e736dd3.PNG

The suitable reagent(s) will be:

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$CrO/{H}_{2}O/$ acetone
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$[Ag(NH_3)_2)^{\oplus} (aqueous), H^+$
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$CrO/HCl/$ pyridine
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$\overset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,COONa}{\overset{|}{\underset{\!\!\!\,\,\,\,\,\,\,\,\,\,\,\,COOK}{\underset{|}{(CHOH)_2}}}} + CuSO_4 + NaOH, \, H^+$

Explanation

Since aldehyde undergo fast silver mirror test to give corresponding acids and other groups do not react with Tollen's reagent, so it is better.

$R - CHO \xrightarrow{[Ag (NH_3)_2 ^{\oplus}] OH^-} R - COOH$

Corrosive sublimate (

$Hg{Cl}_{2}$ ) can be used to distinguish between:

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formaldehyde and propanone
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formic acid and acetic acid
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acetaldehyde and butanone
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all of the above

Explanation

Option

$B$ is the correct answer.

Formic acid gives white precipitate with

$HgCl_2$ but acitic acid does not react.

$HCO_2H+2HgCl_2\longrightarrow \underset{\text{white precipitate}}{Hg_2Cl_2\downarrow} +2HCl+CO_2\uparrow$

$CH_3COOH\xrightarrow[]{HgCl_2}\text{ No precipitate of }Hg_2Cl_2$

Formic acid acts as a reducing agent.

Which of the following compounds will give butanone on oxidation with alkaline

$KMn{O}_{4}$ solution?

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Butan-1-ol
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Butan-2-ol
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2-methylpropan-2-ol
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None of these

Odd one out among the following is:

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Tartaric acid
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Oxalic acid
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Citric acid
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Prussic acid

Explanation

Since all are acid having

$COOH$ functional group except Prussic acid which is

$HCN$ .

Structure of

$(x)$ is:

$C$ . Compound

$(3)$ is:

Most acidic hydrogen is present in :

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$(CH_{3}CO)_{3}CH$
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$(CH_{3})_{3}COH$

The product of following reaction is:

Which of the following reactions is/are not correct to get cinnamic acid?

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$C_{6}H_{5}CHO\xrightarrow [ \left( { CH }_{ 3 }CO \right) _{ 2 }O/CH_{ 3 }COONa ]{ }$
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$C_{6}H_{5}CHO\xrightarrow[{2)H_{3}O^{+},\Delta} ] {1)CH_{2}(COOC_{2}H_{2})_{2},pyridine}$
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$C_{6}H_{5}CHO\xrightarrow{CH_{3}CHO/OH^{-}}{}$
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$C_{6}H_{5}CHO\xrightarrow[{2)H_{2}O/H^{+}/ \Delta}]{1)BrCH_{2}COOC_{2}H_{3}/ZnI \Delta}$

Explanation

The correct option is

$A$ .

The reaction of

${ C }_{ 6 }{ H }_{ 5 }CHO$ and

$(C{ H }_{ 3 }CO{ ) }_{ 2 }O/C{ H }_{ 3 }COONa$ does not give cinnamic acid

Which will form two oximes with

$NH_{2}OH$ ?

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$CH_{3}CHO$
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$CH_{3}COCH_{2}CH_{3}$
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$HCHO$
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$CH_{3}COCH_{2}CH_{2}CH_{2}$

$CH_{3}CH=CHCHO\overset { { OH }^{ - } }{ \underset { Aldol }{ \longrightarrow } } { }A$ ,

$A$ is?

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$CH_{3}(CH=CH)_{3}CHO$
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$CH_{3}CH_{2}CH_{2}(CH=CH)_{2}CHO$
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$CH_{3}(CH_{2}CH_{2})CH=CH-CHO$
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$None\ of\ the\ above\ is\ correct$

Explanation

$CH_3-CH=CH-CHO\overset {\overset {\circleddash}{O}H/\Delta}{\underset {Aldol}{\longrightarrow}}CH_3(CH=CH)_3CHO$
This reaction is known as aldol condensation reaction.

________ is used in the preparation of chloroform, sulphonal, cordite etc.

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formalin
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ethyl alcohol
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acetone
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none of these

Explanation

Preparation of chloroform from acetone is:

$CaOCl_2+H_2O\longrightarrow Ca(OH)_2+Cl_2$

$CH_3COCH_3+3Cl_2\longrightarrow CCl_3COCH_3+3HCl$

$2CCl_3COCH_3+Ca(OH)_2\longrightarrow 2CHCl_3+(CH_3COO)_2Ca$

Preparation of sulphonal from ketone is shown in IMAGE

$01$

Preparation of cordite is shown in Image

$02$

Cordite is a propellant which is addition product of ketone.

Hence, above all are prepared from acetone.

Formaldehyde is used :

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for preserving biological specimens
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for the preparation of urotropine
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in the manufacture of bakelite
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all of these

Which of the following statement is true?

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Benzaldehyde is used in perfumery industry
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Formaldehyde is used for silvering mirrors
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Acetone is used as a commercial solvent
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All of the above

Which of the following is used as an acid bath in dyeing cotton and wool?

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Methanoic acid
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Acetic acid
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Benzoic acid
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Sulphuric acid

Which of the following chemical is used in removing ink stain from clothes?

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Ethyl alcohol
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Glycol
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Banzoic acid
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Oxalic acid

Which acid is used in medicine for the treatment of gout?

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Hydrochloric acid
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Methanoic acid
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Ethanoic acid
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None of these

Find a wrong statement from the given statements.

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oxalic acid is used for making metal polish
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benzoic acid is used in manufacture of dyes
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oxalic acid in form of ferrous potassium oxilate used as developer in photography
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benzoic acid is used for making metal polish

Which of the following is correct?

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Formic acid is used in medicine for the treatment of gout
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Propanoic acid is used as an antiseptic in the preservation of fruit juice
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Ethanoic acid is a coagulating agent in rubber industry
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None of these

Which acid is used in rubber industry as a coagulating agent?

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Methanoic acid
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Ethanoic acid
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Propanoic acid
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Butanoic acid

Which of the following chemical is used in making metal polishes:

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oxalic acid
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methanoic acid
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both A and B
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none of these

Tollen's reagent is:

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ammoniacal cuprous chloride
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ammoniacal cuprous oxide
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ammoniacal silver nitrate
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ammoniacal silver chloride

Explanation

Explanation:

Tollens reagent is ammoniacal silver nitrate.

It is also called a silver mirror test reagent.

It is used to detect the aldehyde functional group in a compound. Upon addition into the test tube containing aldehyde, it produces dark grey ppt or a silver mirror-like appearance.

Welcome to Chem Zipper.com......: What is Tollen's reagent?

Correct Option: $C$

Which acid is used as table vinegar?

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Formic acid
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Acetic acid
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Picric acid
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None of these

Which of the following is not a use of benzoic acid?

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Food preservative
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Anticeptic
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In manufacture of dye
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In metal polish

Acid present in honey bee sting is:

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formic acid
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propanoic acid
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butanoic acid
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none of these

The product C is:

Explanation

Then $N_2H_4$ attacks $B$ , which breaks the outer ring and forms two $-CONH_2$ groups

In a balanced equation , all the moles of different elements remains same hence,

$Ba + 2HCl \rightarrow Bacl_2 + H_2$

Is a balanced equation as there is one mole of $Ba$ and $2$ moles each of hydrogen and chlorine

1107882_1089498_ans_681d04e795cb42b98a581dc8581da844.png

Select the best way for reducing the

$C=O$ group in each of the following:

Which of the following set of reaction can not prepare

$R-\overset{O}{\overset{||}{C}}-OH$ as the final product?

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$R-MgX + O = C = O \xrightarrow{dry. ether} A \xrightarrow{H_3O^+}$
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$R-CN \xrightarrow[(ii) \, H_2O / H^+]{SnCl_2+HCl}$
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$CH_3(CH_2)_8CH_2OH \xrightarrow[H_2SO_4]{CrO_3}$

Explanation

$R-CN \xrightarrow[ii) H_3O^{\oplus}]{i) ZnCl_2 + HCl} R-\overset{NH}{\overset{||}{C}}-H \xrightarrow{H_3O^{\oplus}} R- \overset{O}{\overset{||}{C}} - H$

This reaction doesn't produce

$R - \overset{O}{\overset{||}{C}} -OH$

The Compound E is:

Which of the following molecules contain more enol content at equilibrium?

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$OHC - CH_2 - CHO$
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$CH_3COCH_2COOCH_3$
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$CH_2(COOH)_2$
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$CH_3COCH_3$

When o-xylene is oxidised with alkaline

$KMnO_4$ , the product is:

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Terephthalic acid
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Phthalic acid
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Benzoic acid
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Salicylic acid

The acidity of alpha hydrogen of the carbonyl group is due to:

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The aldehydes and ketones undergo a number of reactions due to the acidic nature of $\alpha-hydrogen$ .
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The acidity of $\alpha-hydrogen$ atoms of carbonyl compounds is due to the strong electron withdrawing effect of the carbonyl group and resonance stabilization of the conjugate base.
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both A and B
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none of these

Which of the following is nucleophilic addition reaction?

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$CH_3COCl \xrightarrow {CH_3MgBr\ (1 eq.)} CH_3COCH_3$
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$CH_3COCH_3 \xrightarrow{I_2/OH^-/\triangle} CH_3COO^-+CHI_3$
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$PhCHO \xrightarrow{KCN/H^{\oplus}} PhCH(OH)(CN)$
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$CH_3C \equiv CMgBr \xrightarrow{CH_3Br}CH_3C\equiv CCH_3$

Explanation

$KCN$ adds to the carbonyl group of benzaldehyde.

Cyanide ion acts as nucleophile. This is followed by acid hydrolysis to form cyanohydrin.

Hence, the reaction

$PhCHO \xrightarrow{KCN/H^{\oplus}} PhCH(OH)(CN)$ is a nucleophilic addition reaction.

In option A the Grignard reagent which acts as nucleophile and adds across

$-C=O$ bond hence it is also nucleophillic addition.

Options A and C are correct.

The compound

$(S)$ is:

The compound (X) is:

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$PhCOONa$
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$Ph - CH = CH - Ph$

What will be the product of the following reaction :
(according to OPTIONS in the image shown)

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B
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C
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D
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A

Identify

$X$ in the following reaction.

A carbonyl compound '

$A$ ' reacts with hydrogen cyanide to form a cyanohydrin '

$B$ ' which on hydrolysis gives an optically active alpha-hydroxy acid '

$C$ '. '

$C$ ' also gives a positive iodoform test.

$A$ ', '

$B$ ' and '

$C$ ' is given by the set:-

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$HCHO$ ;
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$CH_{3}CHO$ ;
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$CH_{3}CH_{2}CHO$
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Which of the following is most reactive to give nucleophilic addition ?

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FCH $_2$ CHO
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ClCH $_2$ CHO
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BrCH $_2$ CHO
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ICH $_2$ CHO

R and S are:

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I only
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I and II
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III only
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None of these
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Blank

Explanation

Benzene undergo Friedal crafts acylation reaction to produce acetophenune, it form

$1$ - phenyl,

$1-, 3$ - butanedione. After halogenation reaction it produce iodoform and sodium containing salt.
1073812_330536_ans_e26ba1b9efcd47688b5ffbd0860a1398.png

1073812_330536_ans_e26ba1b9efcd47688b5ffbd0860a1398.png

Compound

$(C)\;\xrightarrow{P_4O_{10}}\;Product\;(F)$

The product

$F$ may be:

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Malonic anhydride
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Ethanoic anhydride
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Ethanal
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A lactone

The number of

$sp^2$ hybridized carbon atoms in the given compound is:

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3
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4
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5
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6

Explanation

$sp^{2}$ hybridised carbon must be attached with a double.

Here in the given compound, there were

$3$ carbon atoms attached with a double bond. So there were

$3$

$sp^{2}$ hybridised carbon atoms.

Hence option

$A$ is correct.

The final product

$(Y)$ in the following sequence of chemical reaction is:

$CH_3OH\xrightarrow[300^oC]{Cu} X \xrightarrow{NaOH} Y + CH_3OH$

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an alkene
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a carboxylic acid
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an aldehyde
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sodium salt of carboxylic acid

Explanation

$CH_3OH \xrightarrow[300^oC]{Cu} {\underset{(X)}{HC}HO}\xrightarrow{NaOH}\underset{(Y)}{HCOONa}+CH_3OH$

First reaction is oxidation reaction.

Second step the Cannizzaro reaction takes place.

Option D is correct.

When a nucleophile encounters a ketone, the site of attack is:

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the carbon atom of the carbonyl
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the oxygen atom of the carbonyl
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both the carbon and oxygen atoms, with equal probability
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no attack occurs as ketones do not react with nucleophiles

Identify

$(X),\ (Y)$ and

$(Z)$ in the given reaction.

$CH_3CHO \xrightarrow[H_2SO_4]{K_2Cr_2O_7}(X) \xrightarrow{PCl_5}(Y) \xrightarrow[anh.AlCl_3]{C_6H_6}(Z)$ :

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$(X) = HCOOH,\,\,\, (Y) = COCl_2, \,\,\, (Z) = C_6H_5Cl$
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$(X) = CH_3COOH,\,\,\, (Y) = CH_3COCl, \,\,\, (Z) = C_6H_5COCH_3$
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$(X) = CH_3COOH,\,\,\, (Y) = CH_3CH_2CH_2Cl, \,\,\, (Z) = C_6H_5CH_2CH_2CH_3$
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$(X) = CH_3COCH_3,\,\,\, (Y) = CH_3CH(Cl)CH_3, \,\,\, (Z) = C_6H_5COCH_3$

Explanation

Hence, option

$B$ is correct.

The correct order of

$pK_a$ for the following acid:

Oxalic acid

$pK_1$
Monalic acid

$pK_2$
Heptanedioic acid

$pK_3$

where

$pK_1$ ,

$pK_2$ ,

$pK_3$ are first ionization constants.

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$pK_1$ > $pK_2$ > $pK_3$
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$pK_1$ < $pK_2$ < $pK_3$
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$pK_3$ > $pK_2$ = $pK_1$
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$pK_3$ > $pK_1$ > $pK_2$

Identify

$(X)$ and

$(Y)$ in the given reaction sequence.

Which of the following compounds is most reactive towards nucleophilic addition reactions?

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$CH_3-{\overset{O}{\overset{||}{C}}}-CH_3$
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$CH_3-{\overset{O}{\overset{||}{C}}}-H$
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0%

CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 11 - MCQExams.com

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Practice Class 12 Engineering Chemistry Quiz Questions and Answers

CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 11 - MCQExams.com

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Practice Class 12 Engineering Chemistry Quiz Questions and Answers

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