$$40$$% solution of formaldehyde

$$60$$% solution of formaldehyde

$$30$$% solution of formaldehyde

$$50$$% solution of formaldehyde

2, 3,5 - Hexane tricarboxylic acid

2, 4, 5-Hexane tricarboxylic acid

2-(1-carboxyethyl)-4-merthyl pentanedioic acid

3, 5-Dicarboxy-2-methyl hexanoic acid

MCQ Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 6

Aspirin is:

0%
Acetyl salicylic acid
0%
Benzoyl salicylic acid
0%
Chloro benzoic acid
0%
Anthranilic acid

Explanation

$Explanation:$

Aspirin is an analgesic (i.e. pain-reducing) drug. The chemical name of Aspirin is Acetyl salicylic acid.

The IUPAC name for Aspirin (i.e. Acetyl salicylic acid) is

$2-acetoxybenzoic acid$ .

The molecular formula and molar mass for Aspirin is

$C_9H_8O_4$ and

$180$ g/mol.

$Structure\ of\ Aspirin:$

1P2p0g0Go1Go9FoNBqNUvwD9AR41e2dQJEAAAAASUVORK5CYII= (245×206)

$Final\ Answer:$ Option

$A$ .

A student takes 2 mL acetic acid in a dry test tube and adds a pinch of sodium hydrogen carbonate to it. He makes the following observations:
I. A colourless and odourless gas evolves with a brisk effervescence.
II. The gas turns lime water milky when passed through it.
III. The gas burns with an explosion when a burning splinter is brought near it.
IV. The gas extinguishes the burning splinter that is brought near it.
The correct observations are:

0%
I, II, and III
0%
II, III and IV
0%
III, IV and I
0%
IV, I and II

Explanation

When acetic acid reacts with sodium hydrogen carbonate,

$CO_2$ gas is released. The gas is odorless and colorless and evolves with brisk effervescence.

$CO_2$ turns lime water milky when passed through it due to the formation of calcium carbonate.

The burning splinter extinguishes when the gas is brought near it as it does not support combustion and is not flammable.

I, II, and IV observations are correct. Option D is correct.

Find structure which has an organic acid functional group :

0%
$\displaystyle { CH }_{ 3 }-{ CH }_{ 2 }-{ CH }_{ 3 }$
0%
$\displaystyle CH_3-\underset {\displaystyle \underset {\displaystyle O}{ ||}}{C}-OH$
0%
$\displaystyle { CH }_{ 3 }-O-{ C }_{ 3 }{ H }_{ 7 }$
0%
$\displaystyle { CH }_{ 3 }-\overset { \overset { O }{ \parallel } }{ C } -{ CH }_{ 3 }$
0%
$CH_3 - CH_2 - NH_2$

Explanation

Acetic acid

$\displaystyle CH_3-\underset {\displaystyle \underset {\displaystyle O}{ ||}}{C}-OH$ has an organic acid functional group.

It is also called ethanoic acid. It can be considered as a compound formed by substituting the hydrogen atom of methane by the carboxylic group (

$-COOH$ ).

Hence option B is correct.

Polarity of carbonyl group increase with increase of ________.

0%
electronegative groups
0%
electropositive groups
0%
neutral group
0%
none of these

The IUPAC name of the formic acid:

0%
methanoic acid
0%
ethanoic acid
0%
propanoic acid
0%
butanoic acid

Explanation

Formic Acid is

$HCOOH$

IUPAC name is methanoic acid

The solubility of water decreases rapidly with the increase in the size of ------------ groups attached to carbonyl group.

0%
alkyl
0%
aryl
0%
phenyl
0%
benzyl

Aldehydes and ketones with ______ or more carbon atoms are either sparingly soluble or insoluble in water.

0%
5
0%
6
0%
7
0%
8

Explanation

Aldehydes and ketones more than

$C-5$ are soluble in benzene, ether etc.

Lower aldehydes and ketones are soluble in water.

Higher aldehydes and ketones the solubility in water decreases rapidly due to hydrogen bonding.

Hence the correct option is A.

Carbonyl group of aldehyde and ketone contain ________ groups.

0%
carbon and oxygen
0%
carbon and nitrogen
0%
carbon and sulphur
0%
none of these

Explanation

Aldehyde and ketone formula are

$R-CHO$ ,

$R-(C=O)-R$

Thus, they contain carbon and oxygen in their groups.

Which of the following IUPAC name will be used to name carboxylic acid functional group?

0%
-one
0%
-oic acid
0%
-al
0%
-ane

The carboxylic acid includes the functional group:

0%
carboxyl and amine group
0%
carboxyl and amide group
0%
carboxyl and hydroxyl group
0%
carboxyl and amine functional group

What is the product of the following reaction?

Explanation

$CrO_3 / H_2SO_4$ oxidises aldehyde to carboxylic acid.

Which of the following compounds are not soluble in water?

0%
Formaldehyde
0%
Acetaldehyde
0%
Acetone
0%
None of the above

IUPAC name of

$HOOCCH_2C(OH)(COOH)CH_2COOH$ is

0%
citric acid
0%
2-Hydroxy-1,2,3-propanetri-carboxylicacid
0%
2-Hydroxy-1,2,3-propanoic acid
0%
hexanetrioic acid

What is the IUPAC name of

$CH_3CH=CH-COOH$ ?

0%
2-Butenoic acid
0%
Crotonic acid
0%
2-Butanoic acid
0%
3-Butenoic acid

Explanation

$\overset{4}{C}H_3 \overset{3}{C}H= \,^{2}CH- \,^{1}COOH$

$But-2-ene-1-oic \, acid$

The organic acid that can be made from ethanol is:

0%
acetic acid
0%
formic acid
0%
$C_{3}H_{7}OH$
0%
valeric acid
0%
butanoic acid

What is the common name of

$CH_2=CHCOOH$ ?

0%
Anthranilic acid
0%
Citric acid
0%
Acrylic acid
0%
Propenoic acid

Explanation

Common name of

$CH_2=CHCOOH$ is acrylic acid.

As the carbon chain increases in aldehyde and ketone compounds, solubility in water:

0%
decreases
0%
increases
0%
may increase
0%
may decrease

Explanation

As the carbon chain increases in aldehyde and ketone compounds, solubility in water decreases.
Thus, aldehydes and ketones with few carbon atoms are water soluble whereas the one having several

$C$ atoms are water insoluble. With increase in the number of

$C$ atoms, the hydrophobic part of molecule increases. Hence, water solubility decreases.

What is the structure of carbonyl group?

0%
Tetrahedral
0%
Trigonal planar
0%
Pyramidal
0%
Linear

Explanation

The carbonyl carbon and the three atoms attached to it lie in the same plane and the

$\pi-$ electron cloud is above and below this plane. The bond angles are approximately

$120^0$ as expected of a trigonal planar structure.

Acetyl chloride cannot be obtained by treating acetic acid with:

0%
$CHCl_3$
0%
$PCl_3$
0%
$PCl_5$
0%
$SOCl_2$

Explanation

$CH_3COOH \xrightarrow {PCl_3} CH_3COCl +POCl +HCl$

$CH_3COOH \xrightarrow {PCl_5} CH_3COCl +HCl+POCl_3$

$CH_3COOH \xrightarrow {SOCl_2} CH_3COCl +SO_2 +HCl$

With chloroform acetyl chloride cannot be formed with acetic acid.

In the sequence of the given reactions, the starting compound

$P$ is:

0%
o-nitro toluene
0%
m-nitro toluene
0%
o-bromo toluene
0%
p-nitro toluene

Explanation

Hence, the correct option is

$\text{D}$

$CH_3-\overset{NH_2}{\overset{|}{C}H}-COOH$

IUPAC name of the given compound is:

0%
propanamine-oic acid
0%
2-Aminopropanoic acid
0%
amino propanoic acid
0%
none of these

Explanation

Parent functional group is

$-COOH$ hence that carbon numbered as 1 and

$-NH_2$ is substituent at 2nd carbon.

So, option B is correct.

IUPAC name of

$\begin{matrix} C{ H }_{ 3 }- & CH &-C{ H }_{ 2 }- CH -C{ H }_{ 3 } \\ & | & | & \\ & OH & COOH & \end{matrix}$ is:

0%
4-hydroxy-1-methylpentanoic acid
0%
4-hydroxy-2-methylpentanoic acid
0%
2-hydroxy-4-methylpentanoic acid
0%
2-hydroxy-2-methylpentanoic acid

Explanation

$\begin{matrix} \overset{5}{C}{ H }_{ 3 }- & \overset{4}{C}H &-\overset{3}{C}{ H }_{ 2 }- \overset{2}{C}H -C{ H }_{ 3 } \\ & | & | & \\ & OH & \overset{1}{C}OOH & \end{matrix}$

4-hydroxy-2-methylpentanoic acid

The compound

$X$ on oxidation gives a mixture of acetic acid and formic acid, while

$Y$ on oxidation forms only propionic acid.

$X$ and

$Y$ are :

0%
$X$ : $CH_3-CH(OH)-CH_3$ , $Y$ : $CH_3-CO-CH_3$
0%
$X$ : $CH_3 - CH_2 - CH_2 - CHO$ , $Y$ : $CH_3 - CO - CH_3$
0%
$X$ : $CH_3 - CO - CH_3$ , $Y$ : $CH_3 - CH_2 - CHO$
0%
$X$ : $CH_3 - CO - CH_3$ , $Y$ : $CH_3 - O - CH_2 - CH_3$

Explanation

The compound

$X$ on oxidation gives a mixture of acetic acid and formic acid, while

$Y$ on oxidation forms only propionic acid.

$X$ and

$Y$ are

$\displaystyle CH_3 - CO - CH_3$ and

$\displaystyle CH_3 - CH_2 - CHO$ respectively.

$\displaystyle CH_3 - CO - CH_3 \xrightarrow {\text {oxidation}} CH_3-COOH + H-COOH$

$\displaystyle CH_3 - CH_2 - CHO \xrightarrow {\text {oxidation}} CH_3-CH_2-COOH$

Option C is correct

IUPAC name of the compound is:

0%
2-methylbenzoic acid
0%
3-methyl benzenecarboxilic acid
0%
2-methylbenzeneoic acid
0%
3-methylbenzoic acid

Formaldehyde is used as formalin in industries:

0%
to preserve biological specimens
0%
to prepare bakelite
0%
both $A$ and $B$
0%
none of these

IUPAC name of compound is:

0%
3,3-dimethylpropanoic acid
0%
2-methylbutanoic acid
0%
3-Methylbutanoic acid
0%
none of these

IUPAC name of the compound is :

0%
butenoic acid
0%
butanoic acid
0%
2-butynoic acid
0%
none of these

IUPAC naming of the compound is:

0%
3-octanoic acid
0%
octane-3-oic acid
0%
2-ethylhexanoic acid
0%
3-ethylhexanoic acid

$Ph-\underset{OH}{\underset{|}{C}H}-\overset{O}{\overset{||}C}-OH$

Correct IUPAC naming of given acid is:

0%
1-hydroxy-1-phenylethanoic acid
0%
2-hydroxy-2-phenylethanoic acid
0%
2-phenyl hydroxy ethanoic acid
0%
none of these

The correct IUPAC name of the given compound is:

0%
2-phenyl-2-methylpropanoic acid
0%
2-phenyl-2,2-dimethylethanoic acid
0%
isopropyl benzanoic acid
0%
none of these

Explanation

From the above given Numbering IUPAC name is

$2-$ phenyl

$2-$ methylpropanoic acid.

1171598_592109_ans_dc7e5df4039e424999ecf90a2fe689d9.png

Which of the following aldehyde is mostly used as plasticizer?

0%
Formaldehyde
0%
Acetaldehyde
0%
Butyraldehyde
0%
Benzaldehyde

Which of the following does not uses formaldehyde in its preparation?

0%
Melamine polymer
0%
Bakelite
0%
PHBV
0%
preservation of biological specimens

Which is the commercially largest produced aldehyde?

0%
Acetaldehyde
0%
Formaldehyde
0%
Benzaldehyde
0%
Butyraldehyde

Which of the following is used as a food preservative?

0%
Aldehydes
0%
Ketones
0%
Carboxylic acid
0%
Alcohol

Formalin is used in the preparation of:

0%
bakelite
0%
nylon
0%
styrene
0%
teflon

Formalin is:

0%
$60$ % solution of formaldehyde
0%
$40$ % solution of formaldehyde
0%
$30$ % solution of formaldehyde
0%
$50$ % solution of formaldehyde

Explanation

Explanation:

Formalin is the aqueous solution of formaldehyde. It is a $40$ % (By Volume) solution of formaldehyde in water.
It means formalin has $40$ % of formaldehyde.
Formalin is most commonly used as an industrial disinfectant and also used to preserve food materials and also used as antiseptic.

Correct Option: $B$

The percentage of formaldehyde in formalin is:

0%
$40$ %
0%
$30$ %
0%
$20$ %
0%
$10$ %

Explanation

The percentage of formaldehyde in formalin is

$40$ %

$10$ ml formalin contains

$40$ ml formaldehyde and

$60$ ml of water.

Which of the Following reagents give reductive addition reaction to aldehyde and ketone ?

0%
$LiAlH_4$
0%
$NaBH_4$
0%
Both A and B
0%
None of them

A major constituent of vinegar is:

0%
Methanoic acic
0%
Benzoic acid
0%
Ethanoic acid
0%
Picric acid

Explanation

The main constituent of vinegar is acetic acid. The other constituents will depend on the nature of the raw material that has undergone fermentation.

Hence, option

$C$ is correct.

Manufacture of nylon

$-6,6$ uses:

0%
hexanoic acid
0%
pentanoic acid
0%
hexanedioic acid
0%
acetic acid

Explanation

Nylon

$-6,6$ is prepared from adipic acid and hexamethylene diamine condensation reaction.
1157038_599559_ans_c036670f0ec64f6ca0f67c47a2613e50.JPG

Which of the following doesn't use acetaldehyde as a starting material in its preparation?

0%
Ethyl acetate
0%
Ethanoic acid
0%
Methanoic acid
0%
Drugs

Explanation

Methanoic acid needs only single carbon compound not acetaldehyde.

$HCOOH$ -formic acid/Methanoic acid.

Number of moles of oxygen that one mole of benzoic acid uses in the production of phenol by oxidative decarboxylation?

0%
$3/2$
0%
$1$
0%
$1/2$
0%
$2$

Explanation

Benzoic acid is mainly consumed in the production of phenol by oxidative decarboxylation at

$300-400^0$ C:

$C_6H_5CO_2H + 1/2O_2 \longrightarrow C_6H_5OH + CO_2$

Which one of the following contains either aldehyde or ketones in it?

0%
Vanillin
0%
Acetone
0%
Camphor
0%
Formalin

Soaps and detergent industries uses:

0%
lower fatty acids
0%
higher fatty acids
0%
esters
0%
alcohols

Which is a common standard for calibrating a bomb calorimeter in teaching laboratories?

0%
Acetic acid
0%
Benzoic acid
0%
Picric acid
0%
Phenol

Which of the following aldehyde is very much used in perfumery and in dye industries?

0%
Formaldehyde
0%
Acetaldehyde
0%
Benzaldehyde
0%
Butyraldehyde

Carboxylic acids can be prepared from alcohols, nitriles or esters.
Which statements are correct?

$1$ . Both primary and secondary alcohols can be oxidised to carboxylic acids.

$2$ . Carboxylic acids can be made from nitriles by hydrolysis.

$3$ . Ethyl propanoate gives propanoic acid when reacted with hydrochloric acid.

0%
$1, 2$ and $3$ are correct
0%
$1$ and $2$ only are correct
0%
$2$ and $3$ only are correct
0%
$1$ only is correct

Explanation

Solution:- (C)

$2$ and

$3$ only are correct.

Primary alcohols can be oxidised to aldehyde or carboxylic acids depending on the reaction conditions and secondary alcohols are oxidised to ketones.

The hydrolysis of nitriles, which are organic molecules containing a cyano group, leads to carboxylic acid formation. These hydrolysis reactions can take place in either acidic or basic solutions.

Ethyl propanoate reacts with dilute hydrochloric acid and gives propanoic acid. The ester reacts with the water present to produce propanoic acid and ethanol. The dilute acid provides both the acid catalyst and the water.

Hence statements

$2$ and

$3$ are correct.

The IUPAC name of

0%
2, 4, 5-Hexane tricarboxylic acid
0%
2, 3,5 - Hexane tricarboxylic acid
0%
2-(1-carboxyethyl)-4-merthyl pentanedioic acid
0%
3, 5-Dicarboxy-2-methyl hexanoic acid

The major product

$'Y'$ in the following reaction is:

Which of the following compounds will show the maximum enol content?

0%
$CH_3COCH_2COCH_3$
0%
$CH_3COCH_3$
0%
$CH_3COCH_2CONH_2$
0%
$CH_3COCH_2COOC_2H_5$

Explanation

Solution:- (A)

$CH_3COCH_2COCH_3$

Due to intramolecular H-bonding and resonance stabilisation enol content is maximum.

1248760_1613970_ans_73b73b1127364f92bc05bcb0fd19fc1b.png

CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 6 - MCQExams.com

0:0:1

Practice Class 12 Engineering Chemistry Quiz Questions and Answers

CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 6 - MCQExams.com

0:0:1

Practice Class 12 Engineering Chemistry Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.