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CBSE Questions for Class 12 Engineering Chemistry Aldehydes,Ketones And Carboxylic Acids Quiz 8 - MCQExams.com
CBSE
Class 12 Engineering Chemistry
Aldehydes,Ketones And Carboxylic Acids
Quiz 8
When the reaction of
B
r
2
with acetone is catalysed by hydroxide ion, which of the following are the likely products ?
Report Question
0%
C
H
B
r
3
and acetate ion
0%
Bromoacentic acid
0%
Tribromoacetic acid
0%
Acetyl bromide
Explanation
O
O
C
H
3
−
|
|
C
−
C
H
3
+
B
r
2
⊝
O
H
→
A
c
e
t
o
n
e
C
H
3
−
|
|
C
−
O
⊝
A
c
e
t
a
t
e
I
o
n
+
C
H
B
r
3
It is a type of Haloform reaction which takes place in presence of
B
r
2
in basic medium.
What will be the prefix in the following compound ?
H
O
O
C
−
C
H
−
2
−
H
O
O
C
−
C
H
2
|
C
H
−
C
H
2
−
C
H
2
−
C
O
O
H
Report Question
0%
m
e
t
h
y
c
a
r
b
o
x
y
0%
c
a
r
b
o
x
y
m
e
t
h
y
l
0%
c
a
r
b
o
x
y
e
t
h
y
l
0%
e
t
h
y
l
c
a
r
b
o
x
y
Explanation
2
,-carboxymethyl hexanedioic acid
1-butyne reacts with cold alkaline
K
M
n
O
4
to produce
Report Question
0%
C
H
3
C
H
2
C
H
2
C
O
O
H
0%
C
H
3
C
H
2
C
O
O
H
0%
C
H
3
C
H
2
C
O
O
H
+
C
O
2
0%
C
H
3
C
H
2
C
O
O
H
+
H
C
O
O
H
Explanation
Terminal alkynes on oxidation give a mixture of
C
O
2
and a carboxylic acid with one
C
−
atom less than that of the starting alkyne.
C
H
3
−
C
H
2
−
C
≡
C
H
a
l
k
.
K
M
n
O
4
→
C
H
3
−
C
H
2
−
C
O
O
H
+
C
O
2
Hunsdiecker reaction involves the conversion of
Report Question
0%
R
C
O
O
A
g
to
R
C
l
using
C
l
2
0%
R
C
O
O
A
g
to
(
R
C
O
)
2
O
using
R
C
O
C
l
0%
R
C
O
O
A
g
to
R
C
O
O
R
using
I
2
0%
All the above
The number of carbon atoms in the principle chain of the given compound are :
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0%
7
0%
5
0%
4
0%
6
Vinegar is :
Report Question
0%
H
C
H
O
0%
H
C
O
O
H
0%
C
H
3
C
H
O
0%
C
H
3
C
O
O
H
Explanation
Vinegar is the diluted solution of acetic acid (CH_3COOH). It is formed by the fermentation of ethyl alcohol in the presence of enzyme acetobacter.
The IUPAC name of the compound is :
Report Question
0%
2-ethenyl-3-methylcyclohexa-1,3-diene
0%
2,5-dimethylhepta-2,6-dienoic acid
0%
2,6-dimethylhepta-2,5-dienoic acid
0%
2,3-dimethylepoxyethane
C
H
3
C
O
O
H
L
i
A
l
H
4
→
X
C
u
/
300
o
C
→
Y
d
i
l
.
N
a
O
H
→
Z
in the above reaction
Z
is
Report Question
0%
Acetal
0%
Ketal
0%
Aldol
0%
Acid
Write IUPAC name of the following compound.
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0%
3-Hydroxy-2-methylpentanoic acid
0%
4-Methyl-3-hydroxypentanoic acid
0%
3-hydroxy-4-methylpentanoic acid
0%
2-Methyl-2-hydroxypentanoic acid
Explanation
3-Hydroxy-4-methylpentanoic acid
Report Question
0%
0%
0%
0%
The IUPAC name for
C
H
3
−
O
∥
C
−
C
H
2
−
C
H
2
−
O
∥
C
−
O
H
Report Question
0%
1-hydroxypentane-1,4-dione
0%
1,4-dioxopentanol
0%
1-Carboxybutan-3-one
0%
4-Oxopentanoic acid
What are the suitable reagent for following conversion
Report Question
0%
B
r
2
/
F
e
B
r
3
,
K
M
n
O
4
,
H
N
O
3
/
H
2
S
O
4
0%
K
M
n
O
4
,
B
r
2
/
F
e
B
r
3
,
H
N
O
3
0%
H
N
O
3
,
B
r
2
/
F
e
B
r
3
,
K
M
n
O
4
0%
H
N
O
3
,
K
M
n
O
4
,
B
r
2
/
F
e
B
r
3
Explanation
this is suitable answer
The correct product of the following reaction is:
Report Question
0%
0%
0%
0%
Explanation
Solution:- (A)
C
6
H
5
−
C
2
H
5
Alkaline
K
M
n
O
4
→
H
3
O
+
C
6
H
5
−
C
O
O
H
(
Benzoic acid
)
Compound X produces a carboxylic acid when heated under reflux with acidified potassium dichromate(VI). Compound X does not react with sodium metal.
What could be the identity of compound X?
Report Question
0%
Propanal
0%
Propanone
0%
Propan-
1
-ol
0%
Propan-
2
-ol
Explanation
Ptopanal which is aldehyde gives carboxylic acid when heated under reflux with acidified potassium dichromate(VI)
It is a oxidation reaction.
Propanal does not react with Na metal.
Find the end product of reaction.
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0%
0%
0%
0%
Explanation
Solution:- (D)
The end product of the reaction is
1
,
2
-dihydronaphthalen-
2
-one.
Which product is formed when
3
-methylpentane-
1
,
3
,
4
-triol is heated under reflux with an excess of acidified potassium dichromate(VI)?
Report Question
0%
H
O
2
C
C
H
2
C
(
C
H
3
)
(
O
H
)
C
O
C
H
3
0%
H
O
2
C
C
H
2
C
O
C
(
O
H
)
(
C
H
3
)
2
0%
O
H
C
C
H
2
C
(
C
H
3
)
(
O
H
)
C
O
C
H
3
0%
H
O
2
C
C
H
2
C
O
(
C
H
3
)
C
O
C
H
3
Explanation
Solution:- (A)
H
O
O
C
−
C
H
2
−
C
H
3
|
C
|
O
H
−
O
|
|
C
−
C
H
3
H
3
C
−
O
H
|
C
H
2
−
C
H
3
|
C
H
2
|
O
H
−
C
H
2
−
C
H
3
−
O
H
K
2
C
r
2
O
7
(
acidified
)
→
H
O
O
C
−
C
H
2
−
C
H
3
|
C
|
O
H
−
O
|
|
C
−
C
H
3
The acidified potassium dichromate
(
V
I
)
will oxidise
−
O
H
group attached primary carbon to carboxylic group and secondary carbon to ketone.
Alcohols, aldehydes and nitriles can each be converted into carboxylic acids. Which descriptions of their conversions into carboxylic acids are correct?
alcohols
aldehydes
nitriles
A
hydrolysis
hydrolysis
hydrolysis
B
hydrolysis
hydrolysis
oxidation
C
oxidation
oxidation
hydrolysis
D
oxidation
oxidation
oxidation
Report Question
0%
A
0%
B
0%
C
0%
D
Explanation
1.Oxidation of alcohols converted into carboxylic acid.
2.Oxidation of aldehydes converted into carboxylic acid.
3.Nitriles can be converted into carboxylic acid by hydrolysis..
The general formula
C
n
H
2
n
O
2
could be for open chain:
Report Question
0%
diols
0%
diketones
0%
carboxylic acids
0%
dialdehydes
Explanation
for example:
C
2
H
4
O
2
could be
C
H
3
C
O
O
H
{Acetic acid} or
H
O
−
C
H
=
C
H
−
O
H
{1,2-Ethenediol}
hence (A) and (C) are the correct options.
Aldehydes are more reactive than ketones.
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0%
True
0%
False
Which of the following is isobutyric acid?
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0%
C
H
3
C
H
2
C
H
2
C
O
O
H
0%
(
C
H
3
)
2
C
H
C
O
O
H
0%
C
H
3
C
H
2
C
O
O
H
0%
(
C
2
H
5
)
C
H
(
C
H
3
)
C
O
O
H
Explanation
Isobutyric acid, also known as 2-methyl propanoic acid is a carboxylic acid with structural formula
(
C
H
3
)
2
C
H
C
O
O
H
.
Hence option (B) is correct.
Which one of the following statements is wrong?
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0%
Aldehydes and ketones are good reducing agents
0%
Aldehydes and ketones are polar compounds
0%
Aldehydes are more reactive than ketones
0%
Aldehydes and ketones are reduced to alcohols
C
H
3
C
H
2
I
K
C
N
→
H
2
O
→
Δ
here the end product would be:
Report Question
0%
2-cyanorpopanoic acid
0%
ethane-1,1-dicarboxylic acid
0%
2-methyl ethanoic acid
0%
propanoic acid
Explanation
Complete Reaction:
C
H
3
−
C
H
2
I
K
C
N
→
C
H
3
C
H
2
−
C
N
H
2
O
→
Δ
C
H
3
C
H
2
C
O
O
H
P
r
o
p
a
n
o
i
c
A
c
i
d
Hence, Option "D" is the correct answer.
Which of the following as the lowest
p
K
a
value?
Report Question
0%
0%
0%
0%
Explanation
The acidic nature of compound depends on the stability of its conjugate base.
The order of acidic nature of given compounds is
C
>
D
>
B
>
A
.
Greater the acidicity of an acid, lower is its
p
K
a
value.
So, the order of
p
K
a
value of given compounds is
A
>
B
>
D
>
C
So, the lowest
p
K
a
value is of Benzoic acid.
Hence, Option "C" is the correct answer.
Which of the following has the highest
p
K
a
value?
Report Question
0%
0%
0%
0%
Explanation
The order of acidic strengths of given compounds is
B
>
D
>
C
>
A
Stronger the acid is, lower is its
p
K
a
value.
So, the order of
p
K
a
values of given compounds is
A
>
C
>
D
>
B
Hence, Option "A" is the correct answer.
Aldehydes are sweet smelling while ketones have pungent smell.
Report Question
0%
True
0%
False
Carbonyl compounds undergo nucleophilic addition.
Report Question
0%
True
0%
False
State, whether the following statements are True or False:
Benzamide on treatment with
N
a
O
H
and
B
r
2
forms benzoic acid.
Report Question
0%
True
0%
False
Explanation
Thus it forms anilline and not benzoic acid.
The compound is used as
Report Question
0%
Antiseptic
0%
Antibiotic
0%
Analgesic
0%
Pesticide
Explanation
o-acetylsar cyclic acid is an analgesic
Which of the following has lowest
p
K
a
value?
Report Question
0%
0%
0%
0%
Explanation
Closer is the electron-withdrawing group to the carboxylic group, greater is the acidic character of the compound.
Thus, option A has lowest
p
K
a
value.
Soaps can be classified as:
Report Question
0%
carbohydrates
0%
ethers
0%
salts of fatty acids
0%
none of these
Explanation
Soaps can be classified as
salts of fatty acids.
The strongest of the four acids listed below is:
Report Question
0%
H
C
O
O
H
0%
C
H
3
C
O
O
H
0%
C
l
C
H
2
C
O
O
H
0%
F
C
H
2
C
O
O
H
Explanation
As the fluorine is electronegative atom stabilises the conjugate base, hence it is stronger acid.
The general formula for monocarboxylic acids is
Report Question
0%
C
n
H
n
C
O
O
H
0%
C
n
H
2
n
+
1
C
O
O
H
0%
C
n
H
2
n
−
1
C
O
O
H
0%
C
n
H
2
n
O
2
Explanation
General formula of monocarboxylic acid is
C
n
H
2
n
+
1
C
O
O
H
or
C
n
H
2
n
O
2
.
Write the
I
U
P
A
C
name of
C
H
3
C
H
2
C
O
O
H
.
Report Question
0%
Ethyl formic acid
0%
Ethyl carboxylic acid
0%
Ethane methanoic acid
0%
Propanoic acid
Explanation
C
H
3
3
−
C
H
2
2
−
C
O
O
H
1
Propanoic acid
The IUPAC name of the following compound is
H
O
O
C
−
C
H
2
−
C
H
−
C
H
2
−
C
H
2
−
C
O
O
H
|
C
O
O
H
Report Question
0%
2
−
(Carboxy methyl)-pentane
−
1
,
5
−
dioic acid
0%
3
−
Carboxy hexane
−
1
,
6
−
dioic acid
0%
Butane
−
1
,
2
,
4
−
tricarboxylic acid
0%
4
−
Carboxy hexane
−
1
,
6
−
dioic acid
0%
1
,
2
dicarboxypentanoic acid
Explanation
The IUPAC name of the compound is Butane
−
1
,
2
,
4
−
tricarboxylic acid.
H
O
O
C
−
1
C
H
2
−
2
C
H
−
3
C
H
2
−
4
C
H
2
−
C
O
O
H
|
C
O
O
H
The
I
U
P
A
C
name of succinic acid is
Report Question
0%
1
,
4
−
butanedioic acid
0%
Dimethyl
−
2
−
acid
0%
1
,
2
−
dimethyldioic acid
0%
None of these
Explanation
The IUPAC name of succinic acid is 1,4−butanedioic acid.
1
C
O
O
H
−
2
C
H
2
−
3
C
H
2
−
4
C
O
O
H
1
,
4
−
butanedioic acid
Which of the following statement is correct about tropolone?
Report Question
0%
0%
Tropolone has more stability and aromatic character than tropolone.
0%
Tropolone has higher dipole moment than tropone.
0%
Tropolone has lower boiling point than tropone.
Explanation
in stability and aromatic character
The typical reactions of aldehydes is :
Report Question
0%
Electrophilic addition
0%
Nucleophilic substitution
0%
Nucleophilic addition
0%
Nucleophilic elimination
Explanation
Nucleophilic as addition of
H
C
N
,
N
a
H
S
O
3
etc.
Which one is called ethanoic acid
Report Question
0%
H
C
O
O
H
0%
C
H
3
C
O
O
H
0%
C
H
3
C
H
2
C
O
O
H
0%
C
H
3
C
H
2
C
H
2
C
O
O
H
To get DDT , chlorobenzene has to react with which of the following compounds in the presence of concentrated sulphuric acid
Report Question
0%
Trichloroethane
0%
Dichloroacetone
0%
Dichloroacetaldehyde
0%
Trichloroacetaldehyde
Explanation
trichloroacetaldehyde reacts with chlorobenzene in the presence of conc.
H
2
S
O
4
to produce DDT.
Hence option D is correct
The above reaction is
Report Question
0%
Electrophilic substitution
0%
Electrophilic addition
0%
Nucleophilic addition
0%
Nucleophilic substitution
Explanation
It is an example of nucleophilic addition reaction
The most acidic of the following is
Report Question
0%
C
l
C
H
2
C
O
O
H
0%
C
6
H
5
C
O
O
H
0%
C
D
3
C
O
O
H
0%
C
H
3
C
H
2
C
O
O
H
Explanation
Any electron-withdrawing substituent (having
′
−
I
−
e
f
f
e
c
t
) stabilises the anion by dispersing the negative charge and therefore, increases the acidity. Chlorine is an electron-withdrawing group.
Order of reactivity is
Report Question
0%
Acid Chloride > Acid Anhydride > Ester > Amide.
0%
Acid Chloride > Amide >
Acid Anhydride > Ester
0%
Amide > Acid Anhydride > Ester > Acid Chloride
0%
Ester > Acid Chloride > Acid Anhydride > Amide.
By aerial oxidation, which one of the following gives phthalic acid
Report Question
0%
Naphthalene
0%
Banzene
0%
Mesitylene
0%
Toluene
Reaction of primary amines with aldehyde yields
Report Question
0%
amides
0%
aldimines
0%
nitriles
0%
nitro compounds
Explanation
primary amine + aldyhyde it gives aidimines
Carbonyl compounds are usually
Report Question
0%
Ethers , aldehydes , ketones and carboxylic acids
0%
Aldehydes , ketones and carboxylic acids
0%
Aldehydes and ketones
0%
Carboxylic acids
Explanation
carbonyl compound are the compound which have
−
C
O
−
group. and they are usually Aldehydes and Ketones.
Oleic, stearic and palmitic acids are
Report Question
0%
Fatty acid
0%
Amino acid
0%
Nucleic acid
0%
Essential acid
Explanation
Oleic acid, stearic acid and palmitic acids are produced by the hydrolysis of fats and the acid produced by hydrolysis of fats
are called fatty acid.
When toluene is treated with
K
M
n
O
4
, what is produced ?
Report Question
0%
Benzene
0%
Chlorobenzene
0%
Benzaldehyde
0%
Benzoic acid
The rose odour from an ester is formed by the action of
H
C
O
O
H
on
Report Question
0%
Pine oil
0%
Olive oil
0%
Geraniol
0%
Turpentine oil
Explanation
C
10
H
17
O
H
(Geraniol) a liquid terpene alcohol forms ester of rose odour with
H
C
O
O
H
.
2
,
4
−
dichloro phenoxyacetic
acid is used as a
Report Question
0%
Fungicide
0%
Insecticide
0%
Herbicide
0%
Moth repellent
Explanation
It is herbicide (kill herbs)
The order of susceptibility of nucleophilic attack on aldehydes follows the order
Report Question
0%
1
∘
>
3
∘
>
2
∘
0%
1
∘
>
2
∘
>
3
∘
0%
3
∘
>
2
∘
>
1
∘
0%
2
∘
>
3
∘
>
1
∘
Explanation
As the alkyl group increases, carbonyl becomes a weak electrophile and the reactivity becomes low. So, the order is
1
∘
>
2
∘
>
3
∘
0:0:1
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
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Practice Class 12 Engineering Chemistry Quiz Questions and Answers
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