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CBSE Questions for Class 12 Engineering Chemistry Amines Quiz 14 - MCQExams.com
CBSE
Class 12 Engineering Chemistry
Amines
Quiz 14
Arrange he following compounding in decreasing order of basicity
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1 > 2 > 3 > 4
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4 > 1 >2 > 3
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1 > 4 > 2 > 3
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all are incorrect
Which of the following series is arranged in decreasing order of basic strength?
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The correct order of basicities of the following compounds is:
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$$II>I>III$$
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$$I>III>II$$
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$$III>I>II$$
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$$I>II>III$$
Correct order of basic strength of this compound is:
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$$IV> II> III> I$$
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$$III> II> I> IV$$
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$$III> I> II> IV$$
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$$I> IV> III> II$$
Which of the following order is not correct?
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Which is the strongest base?
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Methanamine
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Ethanamine
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Propan-2-amine
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Phenyl methanamine
Arrange basicity of the following compounds in decreasing order
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I > II > III > IV
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IV > III > II > I
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III > II > I > IV
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I > III > II > IV
Basic strength in decreasing order for the following compounds is:
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I >IV > III > II
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IV > I > III > II
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II > III > I > IV
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IV > II > III > I
In the following compounds, the order of basicity is
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$$I>IV>II>III$$
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$$II>I>IV>III$$
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$$III>I>IV>II$$
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None of these
Which of the following statements is correct regarding the preparation of ethers?
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Ethers can be prepared by the action of Grignard regent
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Ethers can be prepared by action of diazomethane with acetic acid
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Ethers can be prepared by heating alkyl halides with dry ferrous sulphide
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Beala (b) and (c)
Identify the strongest base from the given compound.
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All have same basic strength
If $$k _ { h }$$(hydrolysis constant) for anilinium ion is $$2.4 \times 10 ^ { - 5 }$$, then $$\mathrm { K } _ { \mathrm { b } }$$ for aniline will be:
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$$4.1 \times 10 ^ { 10 }$$
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$$4.1 \times 10 ^ { - 10 }$$
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$$2.4 \times 10 ^ { 9 }$$
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$$2.4 \times 10 ^ { - 19 }$$
The correct order of basicities of the following compounds is:
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$$II> I > III > IV$$
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$$I > III > II > IV$$
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$$II > I > III > IV$$
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$$III > I > II > IV$$
correct basic strength order is
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IV > II > III > I
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IV > II > I > IV
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III > I > II > IV
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I > IV > III > II
Guanidine is the strongest base among neutral organic compounds. The reason for the greater basicity of guanidine is:
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presence of three nitrogen atoms in the compound
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The delocalization of lone pairs of N
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The planar structure of guanidine molecule
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The stability of conjugate acid due to resonance
Basic strength order is
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A > B > C
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B > A > C
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B > C > A
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C > B > A
Arrange the following compounds in increasing order of basicity
$$CH_3 NH_2,(CH_3)_2NH,NH_3,C_6H_5NH_2$$
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$$C_6H_5NH_2<NH_3<(CH_3)_2NH<CH_3NH_2$$
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$$CH_3NH_2<(CH_3)_2NH<NH_3<C_6H_5NH_2$$
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$$C_6H_5NH_2<NH_3<CH_3NH_2<(CH_3)_2NH$$
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$$(CH_3)_2NH<CH_3NH_2<NH_3<C_6H_5NH_2$$
Which of the following diazonium salts cannot be isolated ?
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Among the following compounds, the correct increasing order of their basic strength is:
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$$( I ) < ( I I ) < ( I II ) < ( I V )$$
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$$( I ) < ( I I ) < ( IV ) < ( III )$$
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$$( I I ) < ( I ) < ( I II ) < ( I V )$$
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$$( I I ) < ( I ) < ( IV ) < ( III )$$
Which of the following is soluble in dil. aqueous $$HCl?$$
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$$\mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { NH } _ { 2 }$$
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$$\mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { CH } _ { 2 } \mathrm { NH } _ { 2 }$$
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$$\mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { CONH } _ { 2 }$$
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Carbonyl compound and primary Amine react together to form which type of compound?
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Imines
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Aldehyde
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Amine
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Quinones
Most basic amine among the following is
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$$ CH_3NH_2 $$
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$$ CH_3CONH_2 $$
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$$ (CH_3)_2 NH $$
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$$ ( CH_3)_3N $$
What is the decreasing order of basicity ?
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$${ NH }_{ 3 }>{ C }_{ 2 }{ H }_{ 5 }{ NH }_{ 2 }>\left( { C }_{ 2 }H_{ 5 } \right) _{ 2 }NH>\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 3 }N$$
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$$\left( { C }_{ 2 }{ H }_{ 5 } \right) _{3 }N>\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }NH>{ C }_{ 2 }{ H }_{ 5 }{ NH }_{ 2 }>{ NH }_{ 3 }$$
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$$\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }NH>{ C }_{ 2 }{ H }_{ 5 }{ NH }_{ 2 }>\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 3 }N>{ NH }_{ 3 }$$
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$$\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 2 }NH>{ C }_{ 2 }{ H }_{ 5 }{ NH }_{ 2 }>{ NH }_{ 3 }>\left( { C }_{ 2 }{ H }_{ 5 } \right) _{ 3 }N$$
Choose the correct statement
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$$1^{\circ}$$ amine are more basic then $$2^{\circ}$$ amines
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$$2^{\circ}$$ amines are more basic than $$1^{\circ}$$ amines
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basicity of $$1^{\circ}$$ and $$2^{\circ}$$ amines are equal
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$$1^{\circ}$$ and $$2^{\circ}$$ amines are not basic
Which of following has least p$$K_b$$, value?
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Which one of the following is the strongest base in aqueous solution?
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Dimethylamine
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Methylamine
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Trimethylamine
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None of these
Correct decreasing order of $$pK_b$$ value of following compounds:
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I $$>$$ IV $$>$$ II $$>$$ III
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I $$>$$ II $$>$$ IV $$>$$ III
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IV $$>$$ I $$>$$ II $$>$$ III
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I $$>$$ II $$>$$ III $$>$$ IV
Which of the following is strongest base?
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When pure aniline is kept in air then .. colour is obtained.
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dark red
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dark pink
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black
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dark yellow
Which nitrogen in lysergic acid diethylamide (LSD) is most basic?
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1
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2
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3
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all are equally basic
Among the following compounds, the increasing order of their basic strength is
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( I ) < ( I I ) < ( I I I ) < ( I V )
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$$(I) < ( \mathrm { II } ) < ( \mathrm { IV } ) < ( \mathrm { III } )$$
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( I I ) < ( I ) < ( I I ) < ( I V )
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$$( \mathrm { II } ) < ( \mathrm { I } ) < ( \mathrm { IV } ) < ( \mathrm { III } )$$
Which of these alkyl halides can be used to prepare amines using Gabriel phthalimide synthesis?
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Vinyl bromide
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1- bromo-3- methylpentane
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Bromobenzene
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2- bromo- 2,3 - dimethylbutane
The relationship between the values of osmotic pressure of 0.1 M solutions of $${ KNO }_{ 3 }\left( { P }_{ 1 } \right) { CH }_{ 3 }COOH\left( { P }_{ 2 } \right) $$ is
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$${ p }_{ 1 }>{ p }_{ 2 }$$
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$${ p }_{ 2 }>{ p }_{ 1 }$$
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$${ p }_{ 1 }={ p }_{ 2 }$$
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$$\dfrac { { p }_{ 1 } }{ { p }_{ 1 }+{ p }_{ 2 } } =\dfrac { { p }_{ 2 } }{ { p }_{ 1 }+{ 2p }_{ 2 } } $$
Which of the following compound are less basic than aniline?
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$$RX$$ can be converted into $$R{CH}_{2}{NH}_{2}$$ by treatment with $$KCN$$ and
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reduction with reducing agent as $$Na$$ in alcohol
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hydrolysis with dil. $$HCl$$
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hydrolysis with alkaline $${H}_{2}{O}_{2}$$
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none of these
$$X$$ is mixed with a mixture of phenol and aniline in acidic medium.The product obtained is:
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What is the decreasing order of strength of the bases?
(I) $${OH}^{-}$$ (ii) $${NH}_{2}^{-}$$ (III) $$H-C\equiv {C}^{-}$$ (IV) $${CH}_{3}{CH}_{2}^{-}$$
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IV> II> III> I
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III> IV> II> I
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I> II> III> IV
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II> III> I> IV
Explanation
Order of basic strength of given compounds:
IV> II> III> I
Hence, Option "A" is the correct answer.
$$o-Br - C_{6}H_{5}-NH_{2}$$
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aliphatic $$1^{\circ}$$ - amine
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aromatic $$1^{\circ}$$ - amine
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aliphatic $$2^{\circ}$$ - amine
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aromatic $$2^{\circ}$$ - amine
What is the most basic nature ?
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Which of the following amine will be prepared by Gabriel phthalimide reaction?
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n-Butylamine
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Triethylamine
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neo-Pentylamine
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tert-Butylamine
Explanation
Gabriel phthalimide reaction is used to prepare primary unhindered amine only. because in
Gabriel phthalimide reaction no other place for nitrogen, therefor it attack at terminal position only and after hydrolysis it give primary amine i.e n-Butylamine.
In the following compounds, the decreasing order of basic strength will be:
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$$(C_2H_5)_2NH>C_2H_5NH_2>NH_3$$
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$$(C_2H_5)_2NH>NH_3>C_2H_5NH_2$$
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$$NH_3>C_2H_5NH_2>(C_2H_5)_2NH$$
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$$C_2H_5NH_2>NH_3>(C_2H_5)_2NH$$
Explanation
Solution:- (A) $$(C_2H_5)_2NH>C_2H_5NH_2>NH_3$$
Basic strength order
$$(CH_3CH_2)_2NH>CH_3CH_2NH_2>NH_3$$
$$2^0$$ amine $$1^0$$ amine
Alkyl group shows $$+I$$ effect, and hence increases basicity.
What will be the product of the given reaction?
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Explanation
Diazo coupling will take place from the least hindered (ortho, para) position of most activated phenolic ring.
Which of the following is not correct regarding basic strength ?
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Explanation
Amines are basic in nature. There basic nature is result of presence of lone pair of electrons on nitrogen. Amines when dissolved in water attract a proton to form alkylammonium ion and a hydroxide ion. The order of basicity is primary <tertiary>secondary. The aromatic amines are weaker bases than ammonia.
Amino acid of the above ion exist as shown above at pH:
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1
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7
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11
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13
Explanation
As COOH group remains as it is i.e. it does not get ionised. So, the pH of the solution must be as that of a acid.
So, at pH=1, amino acid will exist as shown above.
Hence, Option "A" is the correct answer.
The correct order of basicities of the following compounds
(2) $$ CH_3CH_2NH_2 $$
(3) $$ (CH_3)_2 NH $$
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2 > 1 > 3> 4
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1 > 3 > 2 > 4
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3 > 1 > 2 > 4
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3 > 2 > 1 > 4
Explanation
Basicity is the ability to donate electrons.
So, the order of basicity is:
$$\mathrm{3>2>1>4}$$
Hence, Option "D" is the correct answer.
Which of the following amines can be prepared by Gabriel phthalimide reaction?
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Neo-pentylamine
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n-butylamine
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Triethylamine
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t-butylamine
Explanation
The only primary amine can be prepared from Gabriel phthalimide reaction.
Thus only n-butylamine can be prepared by Gabriel phthalimide reaction.
Ethylamine $$(C_2H_5NH_2)$$ can be obtained from N-ethylphthalimide on treatment with:
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$$NaBH_4$$
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$$CaH_2$$
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$$H_2O$$
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$$NH_2NH_2$$
Explanation
Solution:- (D) $$N{H}_{2} N{H}_{2}$$
Arrange the basicity of the following compounds in decreasing order.
$$ (I) \ CH_3CH_2NH_2 $$
$$(II) \ H_2C=CH-NH_2 $$
$$(III)\ HC\equiv C-NH_2 $$
$$(IV)\ C_6H_5NH_2 $$
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I > II > III > IV
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IV > III > II > I
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III > II > I > IV
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I > III > II > IV
Explanation
Order of basicity depends upon the ability to donate electrons.
Among the given options, compounds II, III & IV have their lone pair of electron of nitrogen involved in resonance. So, I is the most basic compound.
Compound II has higher tendency to donate electrons than III because electronegativity of $$sp^2$$ hybridized carbon is less than that of $$sp$$ hybridized carbon.
So, the order of basicity of given compounds is:
$$\mathrm{I>II>III>IV}$$
Hence, Option "A" is the correct answer.
Aniline dissolved in dilute $$HCl$$ is reacted with sodium nitrite at $${0}^{o}C$$. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. $$HCl$$. The structure of the major product is:
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Explanation
Aniline undergoes diazo coupling in acidic medium with $$PhN_2^{+}$$
The correct order of basicity of the following compounds is:
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$$2>1>3>4$$
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$$4>3>1>2$$
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$$3>1>2>4$$
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$$1>2>3>4$$
Explanation
$$\text{The correct order of basicity is:}$$
$$4>3>1>2$$
$$\text{The basic strength order depends on }$$
$$\text{Accumulation of negative charge on N (double-bonded) by another }−NH_2 \text{ group, thus intensifying the}$$$$\text{ donor ability of N.}$$
$$\text{The higher donor ability of }sp^3\text{ hybrid N as compared to }sp^2\ N.$$
Option B is correct.
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