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CBSE Questions for Class 12 Engineering Chemistry Amines Quiz 7 - MCQExams.com
CBSE
Class 12 Engineering Chemistry
Amines
Quiz 7
In the following componds the order of basicity is:
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I > IV > II > III
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II > I > IV > III
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III > I > IV > II
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IV > I > III > II
Explanation
A specie with a higher ability to donate electrons is more basic.
In III, electrons of Nitrogen are in resonance. So, it has the least tendency to donate electrons. Hence, is the least basic among the all given.
$$\mathrm{sp^3}$$ hybridized Nitrogen has more tendency to donate electrons than $$\mathrm{sp^2}$$ hybridized Nitrogen.
In Iv, the compound has a lesser tendency to donate electrons than that in I because of steric hindrance.
So, the order of basicity is:
$$\mathrm{I>IV>II>III}$$
Hence, Option "A" is the correct answer.
Which one of the following is the weakest base?
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$$ (C_2H_5)_3 N $$
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$$ (C_2H_5)_2 NH $$
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$$ C_2H_5NH_2 $$
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$$ NH_3 $$
Explanation
The $$+I$$ effect increases with increase in the alkyl group.Therefore the basic strength will be the highest in $$(C_2H_5)3N$$ and least in $$NH_3$$. Therefore the decreasing order of basic strength in gas phase will be $$(C_2H_5)3N > (C_2H_5)2NH > C_2H_5NH_2 > NH_3$$.
Strongest base is:
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Explanation
Order of basicity of given compounds:
A (lesser electronegativity of Nitrogen) > D (great
er electronegativity of oxygen)
> B (sp-2 hybridisation of nitrogen) > C (delocalisation of electrons of nitrogen)
Hence, Option "A"' is the correct answer.
Among the following which one is most basic?
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$$ NH_3 $$
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$$ CH_3 NH_2 $$
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$$ CH_3 CH_2NH_2 $$
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$$ C_6H_5NH_2 $$
Explanation
The basicity of the among compounds is due to the presence of lone pair on Nitrogen.
$$CH_3CH_2NH_2$$ is more basic than $$NH_3$$ because of electron-donating group in
$$CH_3CH_2NH_2$$ increases the
electron density on nitrogen atom. $$CH_3NH_2$$ is less basic than
$$CH_3CH_2NH_2$$
because of ethyl group present in ethylamine which increases electron density on N in ethylamine and attracts $$H^+$$ better than methylamine.
$$C_6H_5NH_2$$ is less basic than ethylamine because in
$$C_6H_5NH_2$$
the lone pair of electron on nitrogen is less available for protonation. It is delocalised into the Benzene ring by resonance. In ethylamine no such delocalisation takes place.
Hence, among them
$$CH_3CH_2NH_2$$ is most basic.
The strongest base among the following is:
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Amide ion
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Hydroxide ion
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Trimethylamine
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Ammonia
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Aniline
Explanation
Lesser the stability of the species ion, more basic be the given species. As $$NH_2^-$$ (amide ion) is the least stable species ion. Thus, it is the most basic species.
Hence, option A is the correct answer.
Which of the following is the strong base?
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Explanation
Among the given options, compound "A" has the highest tendency to donate electrons. So, it is the strongest base.
Hence, Option "A" is the correct answer.
Which nitrogen is prtonated redily in the guanidine?
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1
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2
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3
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None of these
Explanation
Nitrogen which is attached with double bond i.e. 1 nitrogen is readily protonated because double-bonded nitrogen is $$sp^2$$ hybridized and on protonating double-bonded nitrogen enables effective resonance stabilization. The positive charge can be delocalized across the molecule
$$\mathbf{Hence\ the\ correct\ answer\ is\ option (A)}$$
The basicity of aniline is less than that of cyclohexylamine. This is due to:
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-R effect of $$ - NH_2 \ group $$
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-I effect of $$ - NH_2 \ group$$
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+ R effect of $$ NH_2 \ group $$
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Hyperconjugation effect
Explanation
The basicity of aniline is less than that of cyclohexylamine because of
+ R effect of $$ NH_2 \ group $$ in aniline.
Hence, Option "C" is the correct answer.
This set contains the questions with single correct answer.
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primary amine
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secondary amine
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tertiary amine
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quaternary salt
Explanation
N attech with one carbon so it is primary amine
The compound
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Alkyne, $$3^{\circ} amine$$
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Alkene, $$2^{\circ} amine$$
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Alkene, $$3^{\circ} amine$$
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Alkyne, $$2^{\circ} amine$$
Amines are more basic than:
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alcohols
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ethers
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esters
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all of these
Explanation
-OH, -COOR,-COC group
all are correct
Which of the following is the most basic amine ?
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$$CH_3-NH_2$$
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$$ClCH_2NH_2$$
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$$Cl_2CH-NH_2$$
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$$CCl_3-NH_2$$
Explanation
$$CCl_3−NH_2$$ this is most basic amine
Which among the following is amphoteric ?
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$$CH_3-NH_2$$
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$$(CH_3)_2NH$$
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$$(CH_3)_3N$$
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$$CH_3CONH_2$$
Explanation
here $$CH_3CONH_2 $$ is amphoteric
Gabriel phthalimide synthesis is used in the preparation of:
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$$1^o$$ amine
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$$2^o$$ amine
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$$3^o$$ amine
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$$4^o$$ amine
Explanation
primary amine
Which of the following is insoluble in dil. HCI ?
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Aniline
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Triphenylamine
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Ethylamine
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Dimethylamine
Explanation
Triphenylamine is insoluble in Dil HCl
Which of the following has the highest $$pK_b$$ value ?
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0%
Explanation
chloroform added and long carbon chain amine is contain ahighest pKb value
$$ {C}_{2} {H}_{5} {NH}_{2} $$ is neutral to litmus.
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True
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False
Explanation
Ethylamine is a primary amine with availability of one lone pair on nitrogen atom, hence it is basic to litmus.
$${ (CH }_{ 3 })_{ 2 }{NH}$$ is a stronger base than $${ (CH }_{ 3 })_{ 3 }{N}$$.
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True
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False
Which of the following may be prepared by Gabriel phthalimide synthesis ?
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Aliphatic amines
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Aromatic amines
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Aliphatic amides
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Aromatic amides
Explanation
Aliphatic amines are
prepared by Gabriel phthalimide synthesis
Amides are the oxidation products of nitriles (cyanides).
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True
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False
Explanation
Nitriles can be converted to amides. This reaction can be acid or base catalyzed. In the case of acid catalysis the nitrile becomes protonated. Protonation increases the electrophilicity of the nitrile so that it will accept water, a poor nucleophile.
Hence, amides are the oxidation product of nitriles.
Aliphatic amines are insoluble in water.
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True
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False
Arrange following amines in the decreasing order of their basicity:
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$$I>III>II$$
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$$I>II>III$$
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$$III>II>I$$
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$$II>III>I$$
Explanation
I>III>II this is correct because of ii option in amine is under resonanc eso this is less basicity
$$CH_3CH_2NH_2$$ contains a basic $$NH_2$$ group, but $$CH_3CONH_2$$ does not because:
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in $$CH_3CONH_2$$, the lone pair of electron on N-atom is delocalised due to resonance
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$$CH_3CONH_2$$ is amphoteric in nature
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in $$CH_3CH_2NH_2$$, the lone pair of electrons on N-atom is delocalised due to resonance
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$$CH_3CONH_2$$ is an acidic derivative
Explanation
in $$CH_3CONH_2$$, the lone pair of electron on N-atom is delocalised due to resonance
Which one of the following on reduction with $${ LiAlH }_{ 4 }$$ yields a secondary amine?
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Methyl cyanide
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Nitroethane
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Methyl isocyanide
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Acetamide
Explanation
On catalytic reduction or with lithium aluminium hydride (LiAlH4) or with nascent hydrogen, alkyl isocyanide yield 2∘ amine whereas cyanide gives 1∘ amine on reduction.
hence c is correct answer
A solution of ethylamine:
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turns blue litmus red
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turns red litmus blue
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does not affect the litmus
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bleaches the litmus
Explanation
ethylamine is a base so turns red litmus to blue
$${ C }_{ 3 }{ H }_{ 9 }N$$ represents
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primary amine
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secondary amine
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tertiary amine
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all of these
Explanation
this compound have all 3 type of amine
Amines are Lewis acids.
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True
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False
Explanation
Lewis base is an electron-pair donor and Lewis acid is an electron pair acceptor.
Hence, amines are Lewis bases.
Mark the correct statement:
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methylamine is slightly acidic
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methylamine is less basic than ammonia
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methylamine is more basic than ammonia
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methylamine forms salts with alkalies
Explanation
methylamine is more basic than ammonia because methyl group are present inductive effect
Primary amines are less soluble than tertiary amines.
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True
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False
Explanation
Primary amines are more soluble than tertiary amines.
Which of the following is the least basic amine?
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Methylamine
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Ethylamine
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Diethylamine
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Aniline
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Benzylamine
Explanation
following compound aniline is least basic amine
The correct order of basic nature of $$CH_3NH_2,(CH_3)_2NH,(CH_3)_3N$$ and $$NH_3$$ is:
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$$CH_3NH_2>(CH_3)_2NH>(CH_3)_3N>NH_3$$
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$$(CH_3)_3N>(CH_3)_2NH>CH_3NH_2>NH_3$$
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$$(CH_3)_2NH>CH_3NH_2>(CH_3)_3N>NH_3$$
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$$NH_3>(CH_3)_3N>CH_3NH_2>(CH_3)_2NH$$
Explanation
$$(CH_3)_2NH>CH_3NH_2>(CH_3)_3N>NH_3$$
correct answer
Comparing basic strength of $$NH_3$$, $$CH_3NH_2$$ and $$C_6H_5NH_2$$, it may be concluded that:
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basic strength remains unaffected
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basic strength of $$NH_3$$ is highest
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basic strength of alkylamine is lowest
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basic strength of arylamine is lowest
Explanation
basic strength of arylamine is lowest
because of present in amine bond
What is the_decreasing order of basicity of pri., sec., tert., ethyl amines and $$NH_3?$$
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$$NH_3>C_2H_5NH_2>(C_2H_5)_2NH>(C_2H_5)_3N$$
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$$(C_2H_5)_3N>(C_2H_5)_2NH>C_2H_5NH_2>NH_3$$
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$$(C_2H_5)_2NH>C_2H_5NH_2>NH_3>(C_2H_5)_3N>NH_3$$
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$$(C_2H_5)_2NH>C_2H_5NH_2>NH_3>(C_2H_5)_3N$$
Explanation
$$(C_2H_5)_2NH>C_2H_5NH_2>NH_3>(C_2H_5)_3N$$
this option is correct answer
The correct increasing order of basic strengths in,
$$CH_3CH_2CN$$,
$$CH_3CH_2NH_2$$,
$4CH_3N=CHCH_3$$ is:
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$$CH_3N=CHCH_3,CH_3CH_2NH_2,CH_3CH_2CN$$
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$$CH_3CH_2NH_2,CH_3N=CHCH_3,CH_3CH_2CN$$
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$$CH_3CH_2CN,CH_3N=CHCH_3,CH_3CH_2NH_2$$
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$$CH_3CH_2CN,CH_3CH_2NH_2,CH_3N=CHCH_3$$
Explanation
$$CH_3CH_2CN,CH_3N=CHCH_3,CH_3CH_2NH_2$$
the correct order is
The boiling points of amines and their corresponding alcohols and acids vary in the order:
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$$RCH_2NH_2>RCOOH>RCH_2OH$$
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$$RCH_2NH_2>RCH_2OH>RCOOH$$
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$$RCH_2NH_2$$ $$<$$ $$RCOOH$$ $$<$$ $$RCH_2OH$$
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$$RCH_2NH_2$$ $$<$$ $$RCH_2OH$$ $$<$$ $$RCOOH$$
Explanation
$$RCH_2NH_2$$ $$<$$ $$RCH_2OH$$ $$<$$ $$RCOOH$$
Hence D is correct
Among following the weakest base is:
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$$C_6H_5CH_2NH_2$$
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$$C_6H_5CH_2NHCH_3$$
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$$O_2N-CH_2NH_2$$
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$$CH_3NHCHO$$
Explanation
$$O_2N-CH_2NH_2$$ No2 is electron withdrowing group so this is week base
An isonitrile on reduction gives:
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$$3^oamine$$
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$$2^oamine$$
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$$1^oamine$$
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quaternary ammonium salts
Explanation
Reduction of isocyanide by LiAlH4 gives secondary amines, in which nitrogen is directly attached to one hydrogen and two alkyl groups.
Choose the correct order for the boiling points of amines:
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$${ CH }_{ 3 }\ddot { N } { H }_{ 2 }>({ CH }_{ 3 })_{ 2 }\ddot { N } H>(CH_{ 3 })_{ 3 }\ddot { N } $$
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$$({ CH }_{ 3 })_{ 2 }\ddot { N } H>(CH_{ 3 })_{ 3 }\ddot { N } >{ CH }_{ 3 }\ddot { N } { H }_{ 2 }$$
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$$(CH_{ 3 })_{ 3 }\ddot { N } <{ CH }_{ 3 }\ddot { N } { H }_{ 2 }<({ CH }_{ 3 })_{ 2 }\ddot { N } H$$
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$$C{ H }_{ 3 }\ddot { N } { H }_{ 2 }<({ CH }_{ 3 })_{ 2 }\ddot { N } H<(CH_{ 3 })_{ 3 }\ddot { N } $$
Explanation
$${ CH }_{ 3 }\ddot { N } { H }_{ 2 }>({ CH }_{ 3 })_{ 2 }\ddot { N } H>(CH_{ 3 })_{ 3 }\ddot { N } $$
Which has the highest $$pK_b$$ value?
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$$R_3C-NH_2$$
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$$R_2NH$$
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$$RNH_2$$
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$$NH_3$$
Explanation
when a compound attech with alkyl compound so the pKb value is less so amine NH3 have highest value of Pkb
Which on reduction does not give primary amine?
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$${ CH }_{ 3 }CN$$
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$${ C }_{ 2 }{ H }_{ 5 }NC$$
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$${ CH }_{ 3 }{ CONH }_{ 2 }$$
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All of these
Explanation
$$C_2H_5NC$$ is after reaction not give primary amine
The basicity of compounds I, II, III and IV varies in the order:
$$\underset { I }{ { CH }_{ 3 }{ NH }_{ 2 } } $$, $$\underset { II }{ { (CH }_{ 3 }{ )_{ 2 }NH } } $$, $$\underset { III }{ { (CH }_{ 3 }{ )_{ 3 }N } } $$, $$\underset { IV }{ { C }_{ 6 }{ H }_{ 5 }{ CH }_{ 2 }{ NH }_{ 2 } } $$
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I>II>III>IV
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II>I>III>IV
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III>I>II>IV
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IV>I>II>III
Explanation
$$(i)$$ The order of basicity of amines in aqueous solution is :
secondary $$>$$ primary $$>$$ tertiary
$$(ii)$$ In case of benzylamine, the phenyl ring $$(C_6H_5)$$ is slightly electron withdrawing. So, the electron density on the nitrogen atom is less in benzylamine in comparison to that of primary amine.
Hence, from the above two points, the correct order of basicity of amines is : $$(CH_{3})_{2}NH>CH_{3}NH_{2}>(CH_{3})_{3}N>C_6H_5CH_{2}NH_{2}$$
$$II$$ $$I$$ $$III$$ $$IV$$
So, option (B) is correct.
The correct order of basic nature in aqueous solution is:
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$$C_6H_5NH_2>NH_3>CH_3NH_2>(CH_3)_2NH$$
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$$NH_3>C_6H_5NH_2>CH_3NH_2>(CH_3)_2NH$$
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$$(CH_3)_2NH>CH_3NH_2>NH_3>C_6H_5NH_2$$
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$$CH_3NH_2>(CH_3)_2NH>NH_3>C_6H_5NH_2$$
Explanation
$$(CH_3)_2NH>CH_3NH_2>NH_3>C_6H_5NH_2$$
the secondry amine is most basic than primary then amine other molecule
Which one of the following is most basic?
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$$FCH_2NH_2$$
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$$FCH_2CH_2NH_2$$
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$$C_6H_5NH_2$$
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$$C_6H_5CH_2NH_2$$
Explanation
benzene structure is more resonance and increase the basicity so ateech benzene with CH3Nh2 is more basic
hence D is correct answer
State, whether the following statements are True or False:
Aniline forms phenol when treated with nitrous acid.
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True
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False
Explanation
Aniline reacts with nitrous acid from $$NaNO_2/ HCl$$
at 0-5$$^oC$$ to form a diazoniumsalt.
$$C_6H_5NH_2 \xrightarrow {NaNO_2/HCl\\\ {0-5 }^oC} C_6H_5N_2^+Cl^-$$
The given statement is false.
Reduction of alkyl nitrile produces:
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secondary amine
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primary amine
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tertiary amine
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amide
Explanation
The nitrile reacts with the lithium tetrahydridoaluminate in solution in ethoxyethane (diethyl ether, or just "ether") followed by treatment of the product of that reaction with dilute acid. Overall, the carbon-nitrogen triple bond is reduced to give a primary amine. Primary amines contain the -NH2 group.
hence B is correct answer
Potassium phthalimide reacts with 'A' which on hydrolysis gives isopentylamine, whiat is 'A'?
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0%
0%
0%
Explanation
hence A is correct answer
Ethyl nitrite on reduction with $$Sn/HCI$$ gives:
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$$C_2H_5NH_2+HNO_2$$
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$$C_2H_5NH_2+H_2O$$
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$$C_2H_5OH+NH_4OH$$
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$$C_2H_5OH+NaNO_2$$
Ethyl isocyanide on reduction with sodium and alcohol gives:
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ethylamine
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propylamine
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dimethylamine
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ethyl methylamine
Explanation
Ethylamine possesses two hydrogen atoms that can form hydrogen bonds wheras diethylamine having only one hydrogen atom is capable of forming only one hydrogen bond.
An orange dye p-hydroxy azobenzene can be synthesized
from benzene diazonium chloride by
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Sandmeyer reaction
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Gomberg reaction
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Coupling reaction
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Gattermann reaction
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Etard reaction
Explanation
This is known as coupling reaction
Among the following, the strongest base is
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$$C_{6}H_{5}NH_{2}$$
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$$p-NO_{2}-C_{6}H_{4}NH_{2}$$
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$$p-CH_{2} - C_{6}H_{4}NH_{2}$$
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$$C_{6}H_{5}CH_{2}NH_{2}$$
Explanation
d>a>b>c , $$EWG (-NO_2)$$ decreases basicity.
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