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CBSE Questions for Class 12 Engineering Chemistry Amines Quiz 9 - MCQExams.com

Which of the following is correct formula for BDC?
  •   C6H4N2Cl
  •   C6H5N2
  •   C6H5N2Cl
  •    C6H4N2
In the reaction series: C6H5ClNH3Cu2O,200oCX;XHNO2050CZ;X+ZA, the number of σ and π bonds in A are:
  • 25σ and 6π
  • 25σ and 7π
  • 27σ and 7π
  • 27σ and 6π
Reaction at 050C between aniline, NaNO2 and HCl is known as____________
  • Suphonation of benzene
  • Acylation of aniline
  • Alkylation of aniline
  • Diazotisation
Among the following which is more basic :

Statement I: Aniline on reaction with NaNO2/HCl at 0oC followed by coupling with β-naphthol gives a dark blue coloured precipitate.
Statement II: The colour of the compound formed in the reaction of aniline with NaNO2/HCl at 0oC followed by coupling with β-naphthol.
  • Statement I and statement II are true and statement II is the correct explanation of statement I
  • Statement I and statement II are true and statement II is not the correct explanation of statement I
  • Statement I is true and the statement II is false
  • Statement I is false and the statement II is true
A compound A has molecular formula C7H7NO. On treatment with Br2 and KOH, A gives an amine B which gives carbylamine test. B upon diazotization and coupling with phenol gives an azo dye. A can be:
  • C6H5CONHCOCH3
  • C6H5CONH2
  • C6H5NO2
  • o,m or p-C6H4(NH2)CHO
The starting reagents needed to make the azo compound shown below is:
26636_ef344524a146453fab9b41a5fb9f38e8.png
Which of the following orders with regards to the basic strength of substituted aniline is correct?
  • p - methylaniline > p - chloroaniline > p - aminoacetophenone
  • p - methylaniline > p - aminoacetophenone > p - chloroaniline
  • p - aminoacetophenone > p - methylaniline > p - chloroaniline
  • p - aminoacetophenone > p - chloroaniline > p - methylaniline
Which of the following forms unstable diazonium ion when treated with NaNO2 in aqueous HCl?
  • p-nitrotoluene
  • ethylamine
  • N,N-dimethyl aniline
  • All of the above
The correct order of increasing basic nature for the bases  NH3,CH3NH2and(CH3)2NH in gas phase is :
  • (CH3)2NH<NH3<CH3NH2
  • NH3<CH3NH2<(CH3)2NH
  • CH3NH2<(CH3)2NH2<NH3
  • CH3NH2<NH3<(CH3)2NH
Amongst the following the most basic compound is :
  • p - nitroaniline
  • acetanilide
  • aniline
  • benzylamine
The major product expected, when Phthalmide is treated with NaOH, is :
Which of the following order for basic strength of amines is correct?

74900_983e8f8b3bdb4cdc93af1b54acd8ae3c.png
  • I>III>IV>II
  • IV>I>II>III
  • I>IV>II>III
  • I>II>IV>III
The increasing order of basic strength for the following compounds is:
(I) CH3CH2NH2
(II) CH3NHCH3
(III) CH3NHPh
(IV) CH3NHCHO
  • IV<III<I>II
  • III<IV<I>II
  • IV<III<II>I
  • II<I<III>IV
The product U is:

72533_45ed6e42e3af44fb953433b72f7f74b9.jpg
Which compound does not give positive test in Lassaigne's test for nitrogen?
  • Urea
  • Hydrazine
  • Azobenzene
  • Phenyl hydrazine
The correct order of basicity of the above compounds is given.
Identify the correct statement(s).
43841.PNG
  • In III, lone pair of electrons is involved in delocalisation but not in II.
  • In IV, lone pair of electrons is involved in delocalisation but not in III.
  • I is more basic than II because six membered ring is more stable than five membered ring.
  • In III, lone pair of electrons is present in sp orbital but in I, II and IV lone pair of electrons are present in sp^{2} orbital.
Aniline when diazotized in cold and then treated with dimethylaniline gives a coloured product. Its structure would be:
3HC\equiv CH \xrightarrow {polymerisation} X \xrightarrow[conc.\ HNO_{3}]{conc.\ H_{2}SO_{4}} Y \xrightarrow {Sn/HCl}Z\xrightarrow[NaNO_{2},HCl]{(0-5^{0}C)} V\xrightarrow[Phenol]{dil\ NaOH}W
Product W is :
Which of the following is weakest base?
  • H_2N-CH_2-NO_2
  • CH_3NH-CH=O
Which compound is soluble in water :
  • \displaystyle \left [ \left ( CH_{3} \right )_{2}NH_{2}\right ]^{+}Cl^{-}
  • \displaystyle \left [ CH_{3}NH_{3} \right ]^{+}Cl^{-}
  • \displaystyle \left [ \left ( CH_{3} \right )_{3}NH\right ]^{+}Cl^{-}
  • \displaystyle PhNO_{2}
What is the principle product when aniline is treated with NaNO_2 and HCl at 0-5^{\circ}C, and this mixture is added to p-toludine (p-methyl aniline)?
The following product(s) will be obtained from the above reaction:
121309_d6d1d31057454058810397464eb9aaac.png
\displaystyle - Ethyl pthalimide on hydrolysis gives:
  • methyl alcohol
  • ethyl amine
  • dimethyl amine
  • diethyl amine
Which compound will liberate \displaystyle CO_{2} from \displaystyle NaHCO_{3} solution :
  • \displaystyle CH_{3}CO\:NH_{2}
  • \displaystyle CH_{3}NH_{2}
  • \displaystyle \left ( CH_{3} \right )_{4}N^{+}OH^{-}
  • \displaystyle CH_{3}N^{+}H_{3}Cl^{-}
Which of the following diazonium salt is relatively stable of 0-5^\circ C- :
  • CH_{3}CH_2N\equiv N\left. \right \} ^\oplus Cl^{-}
  • CH_{3}-C(CH_{3})_{2}-N\equiv N\left. \right \} ^\oplus Cl^{-}
  • CH_{3}-N\equiv N\left. \right \} ^\oplus Cl^{-}
  • (CH_{3})_{3}C-N\equiv N\left. \right \} ^\oplus Cl^{-}
Which of the following diazonium salt is relatively stable at \displaystyle 0-5^{\circ}C?
  • \displaystyle CH_{3}-N\equiv N^{\oplus }Cl^{-}
  • \displaystyle CH_{3}CH\left ( CH_{3} \right )-N\equiv N ^{\oplus }Cl^{-}
  • \displaystyle C_{6}H_{5}-N\equiv N ^{\oplus }Cl^{-}
  • \displaystyle \left ( CH_{3} \right )_{3}C-N\equiv N ^{\oplus }Cl^{-}
Of the following statements :
(P)\:C_{6}H_{5}N=CH-C_{6}H_{5} is a Schiff's base.
(Q)\:A dye is obtained by the reaction of aniline and C_{6}H_{5}N^+ \equiv NCl.
(R)\:C_{6}H_{5}CH_{2}NH_{2} on treatment with [NaNO_{2}+HCl] gives diazonium salt.
(S)\:p-Toluidine on treatment with [HNO_{2}+HCl] gives diazonium salt.
  • only (P)\:and\:(Q) are correct
  • only (P)\:and\:(R) are correct
  • only (R)\:and\:(S) are correct
  • (P),\:(Q)\:and\:(S) are correct
Arrange the following in the increasing order of their basicities.
I.  p - Toluidine
II.  N, N - Dimethyl - p - toluidine
III.  p - Nitroaniline
IV.  Aniline
  • III < IV < I < II
  • II < IV < I < III
  • III < II < I < IV
  • I < IV < III < II
Which one(s) is/are true?
244984_4a91c8421a5843ef99c951718adf0721.png
  • (I) and (III) are modest Bronsted bases whereas (II) is not
  • In (III) {N}^{a} is more basic than {N}^{b}
  • When (II) is protonated in the presence of a strong acid, protonation occurs at C - 2
  • All the nitrogen present in (I), (II), and (III) is s{p}^{2} hybridised
Arrange the following in their decreasing order of acidity.

244989_b3f46e7b98d94e01bbdc8ed803a45d2c.png
  • III > IV > I > II
  • I > II > III > IV
  • IV > III > II > I
  • II > III > I > IV
Which of the following is the product of the reaction shown above?
206794.png
  • (CH_3)_2CHCH_2CH_2NHNH_2
  • [(CH_3)_2CHCH_2CH_2]_2NH
  • (CH_3)_2CHCH_2CH_2NH_2
  • (CH_3)_2CHCH_2CH_2CONH_2
The decreasing order of basic characters of the following is :
245041_86a21bdb1e854fd1a74329652e535599.png
  • III > IV > I > II
  • II > I > IV > III
  • IV > III > II > I
  • I > II > III > IV
Which of the following statement(s) is/are correct?
244985_4a1a58265d4940aab28debbcc7a7befa.png
  • (I) and (II) are aromatic and have equal basic strength
  • (I) is aromatic and (II) is anti-aromatic, but (II) is stronger base than (I)
  • The order of basicity of the above compounds is (IV) > (III) > (II) > (I)
  • The conjugate acid of (IV) is more stabilised than the conjugate acid of (II)
Identify the most basic amine among the above compounds :
246541_5a5d451b1658448ebf39783fa8bd5e68.png
  • i
  • ii
  • iii
  • iv
Alkyl isocyanides (R N^{\bigoplus} \equiv C^{\ominus}) are reduced to 2^{\circ} amines(R-NH-CH_3) with:
  • LAH
  • NaBH_4
  • HI + P
  • H_2 / Pt
Which statements are correct? 
  • Phenol and aniline give coupling reaction with diazonium salt.
  • Phenol couples with diazonium salt in mild basic conditions (\displaystyle pH = 8-10).
  • Aniline couples with diazonium salt in mild acidic condition (\displaystyle pH = 4-6).
  • Both phenol and aniline couple with diazonium salt in neutral condition ( pH = 7).
Compound (E) is:
Compound (A) is:
  • Ethylbenzene
  • p-Xylene
  • m-Xylene
  • o-Xylene
Compound (F) is:
Compound (D) is:
The following reaction is:
253878_ce022c735cb140a394a3fab0eb63a738.png
  • benzidine rearrangement
  • pinacol-pinacolone rearrangement
  • fries rearrangement
  • benzil-benzilic acid arrangement
The decreasing order of the rate of bromination of the following compounds is:
I. Ph\overset { \oplus  }{ N{ Me }_{ 3 } }  
II. Ph{CH}_{3}\overset { \oplus  }{ N{ Me }_{ 3 } }  
III. PhMe  
IV. PhN{Me}_{2}
  • (I)>(II)>(III)>(IV)
  • (IV)>(III)>(II)>(I)
  • (III)>(IV)>(I)>(II)
  • (III)>(IV)>(II)>(I)
Gabriel synthesis is used for the preparation of: 
  • \displaystyle { 1 }^{ o } amine
  • \displaystyle { 2 }^{ o } amine
  • \displaystyle { 3 }^{ o } amine
  • all of the above
Which of the following orders regarding the basic strength of substituted aniline is correct?
  • p-methylaniline> p-chloroaniline > p-aminoacetophenone
  • p-methylaniline> p-aminoacetophenone> p-chloroaniline
  • p-aminoacetophenone> p-methylaniline> p-chloroaniline
  • p-aminoacetophenone> p-chloroaniline> p-methylaniline
Most basic compound in gaseous phase is :
  • {NH}_{3}
  • {CH}_{3}{CH}_{2}{NH}_{2}
  • ({CH}_{3}{CH}_{2})_2NH
  • {({CH}_{3}{CH}_{2})}_{3}N
Benzenediazonium chloride on reaction with aniline in a weakly basic medium gives :
  • diphenyl ether
  • p-aminoazobenzene
  • chlorobenzene
  • benzene
Which of the following compounds has the lowest boiling point?
  • 2-propanamine
  • ethylmethylamine
  • 1-propanamine
  • N,N-dimethylmethanamine
Among the following, the strongest base is :
  • C_6H_5NH_2
  • p-NO_2C_6H_4NH_2
  • m-NO_2C_6H_4NH_2
  • C_6H_5CH_2NH_2
Which of the following statement(s) is/are correct?
  • Primary amines show intermolecular hydrogen bonding.
  • Secondary amines intermolecular hydrogen bonding.
  • Tertiary amines show intermolecular hydrogen bonding.
  • Amines have lower boiling points as compared to those of alcohols and carboxylic acid of comparable molar masses.
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