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CBSE Questions for Class 12 Engineering Chemistry Coordination Compounds Quiz 15 - MCQExams.com
CBSE
Class 12 Engineering Chemistry
Coordination Compounds
Quiz 15
Which of the following complex compounds will exhibit highest paramagnetic behaviour? (At. No. $$Ti = 22, Cr = 24, Co = 27, Zn = 30$$)
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$$[Zn (NH_3)_6]^{2+}$$
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$$[Ti (NH_3)_6]^{3+}$$
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$$[Cr(NH_3)_6]^{3+}$$
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$$[Co(NH_3)_6]^{3+}$$
Explanation
a. $$[Zn(NH_3)_6]^{2+}$$ : In this complex because of $$3d^{10}$$ configuration no $$(n - 1)d $$ orbital is available for $$d^2 sp^3$$ hybridisation and thus forms outer orbital complex. The complex is diamagnetic.
b. $$[Ti(NH_3)_6]^{3+}$$ : $$Ti$$ has $$3d^1$$ configuration and thus has one unpaired electron.
c. $$[Cr(NH_3)_6]^{3+}$$ : The complex is inner orbital complex but $$3d^3$$ configuration has three unpaired electrons with weak as well as with strong field ligand.
d. $$[Co(NH_3)_6]^{3+}$$ : The cobalt ion is in $$+3$$ oxidation state with $$3d^6$$ configuration and thus is a diamagnetic octahedral complex.
If d-d transition energy and electron pair energy for an octahedral complex have values $$45000$$ $$cm^{-1}$$ and $$14000$$ $$cm^{-1}$$ the value of CFSE is:
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$$6.2 \times 10^{14} J$$
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$$7.0\times 10^{-19}J$$
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$$2.5\times10^{-20}J$$
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$$8.94\times10^{-19}J$$
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