Explanation
Where,
k = specific rate (or) rate constant
A = pZ = Frequency factor
p = probability factor or steric factor or orientation factor
Z = no. of binary collisions per unit time
Ea = Activation energy
R = Universal Gas constant
T = Absolute Temperature
It is clear that the rate of a reaction is proportional to the temperature but inversely proportional to the activation energy.
For endothermic reaction, $$ \Delta H={ H }_{ P }-{ H }_{ R }=positive.$$
For exothermic reaction, $$ \Delta H=negative$$ From the above figures, it is confirmed that
(i) For an endothermic reaction, $$E_a$$ is always greater than $$\Delta H.$$
(ii) For an exothermic reaction, $$E_a$$ may or may not be greater than $$\Delta H.$$ While catalysts decrease the activation energy only and does not affect the $$\Delta H $$ of the reaction.
Therefore, option $$(A)$$ is the correct answer.
$$ k={ A.e }^{ { -E }_{ a }/RT }$$
(i) If the value of $$A$$ increases, the value of $$k$$ increases.
(ii) If the value of $$T$$ increases, $$ { E }_{ a }/RT $$ decreases. Therefore $$ { e }^{ { -E }_{ a }/RT }$$ increases. Therefore, $$k$$ increases.
(iii) If $$ { E }_{ a } $$ increases,$${ e }^{ { -E }_{ a }/RT } $$ decreases. Therefore, $$k$$ decreases.
(iv) If $$R$$ increases, $$ { e }^{ { -E }_{ a }/RT } $$ increases. Therefore, $$k$$ increases.
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