For the first order decomposition of $${ SO }_{ 2 }{ Cl }_{ 2} (g), { SO }_{ 2 }{ Cl }_{ 2 } \longrightarrow { SO }_{ 2 }(g) + { Cl }_{ 2 }(g)$$A graph of $$log ({ a } -x)\ vs\ t $$ is shown in figure. What is the rate constant $$({ sec }^{ -1 })$$?
Explanation
Let the rotation of Sucrose be $$r_1^o$$ per mole and the initial moles of Sucrose be a. $$ \implies r_0 = ar_1^0$$
Let the moles converted be x. $$\implies r_t = (a-x)r_1^0 $$$$\implies \frac{a}{a-x} = \frac{r_o}{r_t}$$ $$\implies k = \frac{1}{t} \ln \frac{a}{a-x} = \frac{1}{t} \ln\frac{r_o}{r_t}$$$$\implies k = \frac{2.303}{10}\log\frac{100}{50}$$$$\implies k = 0.069 \space min^{-1}$$
times the Initial concentration.
Here $$n=3$$ . So Amount of Reactant left is $$\dfrac{1}{8}$$
So Amount of reactant decayed is $$a-\dfrac{1}{8}=7a/8$$
Option A is correct.
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