Explanation
$$Orbital\ angular\ momentum\ = \dfrac{h}{{\sqrt 2 \pi }}$$
The orbital angular momentum $$ = \dfrac{h}{{\sqrt 2 \pi }}$$
From the structural point of the view, we see that,
$$NF_{3}$$ is pyramidal whereas $$BF_{3}$$ is planar triangular in structure.
$$BF^{-}_{4}$$ and $$NH^{+}_{4}$$ ions both are tetrahedral in structure.
$$BCl_{3}$$ is triangular planar whereas $$BrCl_{3}$$ is pyramidal in structure.
$$NH_{3}$$ is pyramidal whereas $$NO_{3}$$ is triangular planar structure.
So as we can see the only option B has both the elements same in structure.
The correct answer is option B.
Now for the other (anionic part):
Here the ligand is chloride. Since there are $$4$$ chlorides so we’ll call it tetrachloride. We have the central metal atom as platinum again, but since it is in the anionic coordination sphere.
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