Explanation
$$Mn{O^{ - 4}} = M{n^{ + 2}} + 5{e^ - }$$
$$Mn$$ in $$Mn{O_4{^{ -}}}$$ has an oxidation state of +7.
Going from +7 to +2 requires an additional 5 electrons
1 mol of $$e=1\ F$$
5 mol of $$e = 5\ F$$
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