Explanation
Faraday’ first law of electrolysis states that the mass of the substance (m) deposited or liberated at any electrode is directly proportional to the quantity of electricity or charge (Q) passed.
For a given interval of time an electric current arises whenever there is a flow of charges (for example, electrons) and is defined as the rate at which charge flows. So, the mass of ions deposited during a given interval of time in the process of electrolysis depends on the current at that interval. [Option A]
According to Faraday’s First Law of Electrolysis, mass of the substance (m) deposited or liberated at any electrode is directly proportional to the quantity of electricity or charge (Q) passed.
m = Z x I x t ; (I = Q/t)
where m is the mass of the substance produced in g; Z is the electrochemical equivalent, which is the mass of a substance produced at the electrode during electrolysis by one coulomb of charge
Z=(atomic weight/ nF)
I is the current in Ampere(A); t is the time in seconds;
Hence if the duration of the passage of current (t) is doubled then,
m’ = Z x I x (2t) = 2 (Z x I x t) = 2m
So, the mass liberated (m) will also be doubled. [Option A]
Electrolyte Solution or molten salt can conduct electricity by the process of electrolysis. In electrolytes, current is carried by positive and negative ions, rather than by electrons.
For example, in a lead-acid car battery, the electrolyte is dilute sulphuric acid, which contains negative sulphate ions and positive hydrogen ions. [Option C]
The electrochemical cell stops working after some time because:
During conductometric titration of 0.1 M HCl with 1.0 M KOH, which of the following will be observed?
Conductometric titration is a type of titration in which the electrolytic conductivity of the reaction mixture is continuously monitored as one reactant is added. During titration, the conductance of the solution first decreases, reaches a minimum value at equivalence point (end point) and then increases (as shown in graph).
Since, resistance is the inverse quantity of conductance. It increases first up to the equivalence point and then decreases.
Given standard electrode potentials:
$$Fe^{3+}+3e^{-}\rightarrow Fe;E^{0}=-0.036V$$
$$Fe^{2+}+2e^{-}\rightarrow Fe;E^{0}=-0.440V$$
The standard electrode potential $$E^o$$ for $$Fe^{3+}+e^-\rightarrow Fe^{2+}$$ is:
Oxidation occurs at the electrode X which is the anode and it has negative polarity.Anode: $$X \rightarrow X^{+2}+2e^-$$
Cathode: $$Y^{3+}+3e^-\rightarrow Y$$
Here, the electron is flowing from X to Y.
Option D is correct.
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