Explanation
IUPAC name of $$(CH_3)_3CCl$$ is:
In the given reactant, the two groups which are present on the benzene rings $$(-OCH_3 \ and \ -CH_3 )$$ are electron-donating and ortho- para- directing groups.
The ortho- para- directing nature of the groups are in the following order:-
$$NH_2 > -NR_2> -OH > -OCH_3 > -NHAc> -CH_3 > -X$$
Thus, they both will direct $$ Br$$ group on ortho- and para- position. But due to the steric hindrance, the compound at the para position will be a major product.
Hence, option B is correct.
Which of the following is most reactive toward $$Ag^{\oplus} NO_3^{\ominus}$$ or rate of $$S_{N_1}$$ reaction?
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