Explanation
This pathway for $$S_N1$$ mechanism is a multi-step process with the following characteristics:
In the presence of ultraviolet light (but without a catalyst present), hot benzene will also undergo an addition reaction with chlorine or bromine. The ring delocalisation is permanently broken and a chlorine or bromine atom adds on to each carbon atom.
For example, if you bubble chlorine gas through hot benzene exposed to UV light for an hour, you get $$1,2,3,4,5,6$$-hexachlorocyclohexane or benzenehexachloride.
The criteria for optical isomerism are:
Which of the following is/are optically active compound/s?
A carbon atom which is having all the four atoms attached to it are different is chiral and can show optically activity. Among the given compounds, sec- butyl bromide is optically active compound. In sec-butyl bromide, the four atoms or groups attached to the carbon marked by asterisk in the above image are different and hence it is chiral.
Haloalkanes in the presence of alcoholic KOH undergoes elimination reaction or dehydrohalogenation reaction.
$$CH_3CH_2CH_2Br+alc. KOH\rightarrow CH_3CH=CH_2+KBr+H_2O$$
In allylic and benzylic halides, halogen is attached to the $$sp^3$$ hybridised carbon.
As $$ CH_3-CH_2Cl$$ and $$C_6H_5-CH_2Cl$$
There are three dichlorobenzene isomers- 1,2-dichlorobenzene, 1,3-dichlorobenzene, and 1,4-dichlorobenzene.
Dichlorobenzenes do not occur naturally.
1,2-Dichlorobenzene is a colorless to pale yellow liquid.
1,3- Dichlorobenzene is a colorless liquid.
1,4-Dichlorobenzene, the most important of the three chemicals, is a colorless white solid with a strong, pungent odor.
Options B and C are correct.
Alkyl bromides and iodides develop colour when exposed to light. Halogens have lower bond dissociation energy. This low enthalpy means that even at normal temperature or on exposure to sunlight, they decompose and form free ions, which are coloured and hence impart colour on exposure to light.
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