Match the column I with column II and mark the appropriate choice. Column I Column II (A) PVC (i) Rubber (B) Condensation polymer (ii) Thermoplsatic (C) Polysaccharide (iii) Dacron (D) Elastomer (iv) Natural Polymer

(A) $$\rightarrow$$ (ii), (B) $$\rightarrow$$ (iii), (C) $$\rightarrow$$ (iv), (D) $$\rightarrow$$ (i)

(A) $$\rightarrow$$ (i), (B) $$\rightarrow$$ (ii), (C) $$\rightarrow$$ (iv), (D) $$\rightarrow$$ (iii)

(A) $$\rightarrow$$ (iii), (B) $$\rightarrow$$ (iv), (C) $$\rightarrow$$ (i), (D) $$\rightarrow$$ (ii)

(A) $$\rightarrow$$ (iv), (B) $$\rightarrow$$ (i), (C) $$\rightarrow$$ (iii), (D) $$\rightarrow$$ (ii)

Match the column I with column II and mark the appropriate choice. Column I Column II (A) Buna-N (i) Phthalic acid and ethylene glycol (B) Nylon-6,6 (ii) Terephthalic acid and ethylene glycol (C) Dacron (iii) Hexamethylenediamine and adipic acid (D) Glyptal plastic (iv) Acrylonitrile and butadiene

(A) $$\rightarrow$$ (iv), (B) $$\rightarrow$$ (iii), (C) $$\rightarrow$$ (ii), (D) $$\rightarrow$$ (i)

(A) $$\rightarrow$$ (ii), (B) $$\rightarrow$$ (iii), (C) $$\rightarrow$$ (iv), (D) $$\rightarrow$$ (i)

(A) $$\rightarrow$$ (i), (B) $$\rightarrow$$ (ii), (C) $$\rightarrow$$ (iv), (D) $$\rightarrow$$ (i)

(A) $$\rightarrow$$ (iii), (B) $$\rightarrow$$ (iv), (C) $$\rightarrow$$ (i), (D) $$\rightarrow$$ (ii)

MCQ Questions for Class 12 Engineering Chemistry Polymers Quiz 12

Which one is classified as a condensation polymer?

0%
Teflon
0%
Acrylonitrile
0%
Dacron
0%
Neoprene

Explanation

Correct answer: Option

$C$ .

Explanation:

There are two types of polymers:

1. Addition polymers.

2. Condensation polymers.

They are classified based on the method by which they are polymerized.

During addition polymerization, no molecule is eliminated. But during condensation polymerization, a small molecule like water, ethanol, or hydrogen chloride is eliminated.

A) Addition polymer

B) Monomer of PAN

C) Condensation polymer

D) Addition polymer

Gutta Percha is_________.

0%
trans-polyisoprene
0%
non-elastic and softens to a plastic-like material on heating
0%
used in underwater cables and golf balls
0%
All of the above

Which of the following are used as free radical chain initiators ?

0%
Benzoyl peroxide
0%
di-tert-butyl peroxide
0%
Carbon tetrachloride
0%
Benzoquinone

Which of the following are biodegradable polymers?

0%
Nylon - $6,\: 6$
0%
PHBV
0%
Nylon - $2$ - Nylon - $6$
0%
Polychloroprene

Explanation

$\text {Biodegradation}:$ The backbone of the polymer is hydrolytically unstable. That is, the polymer is unstable in a water based environment. This is the prevailing mechanism for polymers degradation.
Water penetrates the bulk of the device, attacking the chemical bonds in the amorphous phase and converting long polymer chains into shorter water-soluble fragments.

Poly (

$3$ -hydroxybutyrate-co-

$3$ -hydroxyvalerate (PHBV) is a polyhydroxyalkanoate-type polymer. It is biodegradable, nontoxic, biocompatible plastic produced naturally by bacteria and a good alternative for many non-biodegradable synthetic polymers. It is a thermoplastic linear aliphatic polyester. When disposed, PHBV degrades into carbon dioxide and water. .

Nylon-

$2$ -nylon-

$6$ is a biodegradable polymer, it is also hydrolytically unstable. So, the bonds are broken and hence, the molecular weight of the polymer is lost.
It has

$-NH-CO-$ bond which is formed from by the removal of

$H_2O$ molecule.
The below attached is PHBV.

Nylon

$-5,\:10$ can be prepared by:

0%
$H_2N(CH_2)_5NH_2+$ $\text{Decanoic acid (Sebacic acid)}$
0%
$HOOC(CH_2)_3COOH+H_2N(CH_2)_{10}NH_2$
0%
$H_2N(CH_2)_6NH_2+HOOC(CH_2)_8COOH$
0%
$H_2N(CH_2)_{10}NH_2+HOOC(CH_2)_4COOH$

Explanation

Nylon -

$5,\:10$ is made from pentamethylene diamine and sebacic acid as per the reaction shown.

Isoprene is the repeating unit in :

0%
vitamin A
0%
terpenes
0%
natural rubber
0%
All of the above

Which of the following polymers contains

$1,\: 3$ -butadiene as one of the monomers ?

0%
Butyl rubber
0%
Nitrile rubber
0%
ABS plastic
0%
SBR

Explanation

The polymers Nitrile rubber, ABS plastic and SBR contains

$1,\: 3$ -butadiene as one of the monomers.

Butyl rubber is copolymer of isobutylene and isoprene.

Nitrile rubber (Buna - N) is copolymer of acrylonitrile and

$1,\: 3$ -butadiene.

ABS plastic is copolymer of

$1,\: 3$ -butadiene and acrylonitrile.

SBR (Buna S) is copolymer of

$1,\: 3$ -butadiene and styrene.

Polymerisation of buta -

$1,\:3$ - diene by free radical mechanism gives___________.

0%
trans - $1,\: 4$ - Polybutadiene
0%
cis - $1, \:4$ - Polybutadiene
0%
Polyvinyl polyethene
0%
Polyallyl polythene

Explanation

$1,\:3$ - Butadiene is an organic compound that is a simple conjugated diene hydrocarbon (dienes have two carbon-carbon double bonds).
Polybutadiene forms by linking many

$1,\:3$ - butadiene monomers to make a much longer polymer chain molecule. In terms of the connectivity of the
polymer chain, butadiene can polymerize in three different ways, called cis, trans and vinyl.
The cis and trans forms arise by connecting the butadiene molecules end-to-end, so-called

$1,\:4$ -polymerisation. The properties of the resulting isomeric forms of polybutadiene differ. For example, "high cis" - polybutadiene has a high elasticity and is very popular, whereas the so-called "high trans" is a plastic crystal with few useful applications. The vinyl content of polybutadiene is typically no more than a few percents. In addition to these three kinds of connectivity, polybutadienes differ in terms of their branching and molecular weights.
Hence, options A, B & C are correct.

Terylene (Dacron) is the polyester of

0%
Hexamethylenediamine and adipic acid
0%
Vinyl chloride and formaldehyde
0%
Melamine and formaldehyde
0%
Ethylene glycol and terephthalic acid

SBR (GRS, Buna-S, Cold Rubber) is obtained by free radical copolymerisation of :

0%
$70\%$ Buta - $1, \:3$ - diene and $30\%$ phenly ethene (styrene)
0%
chloroprene and styrene
0%
vinly-acetylene and styrene
0%
isoprene and $1,\: 3$ - butadiene

Explanation

Styrene rubber or SBR (Styrene butadiene rubber) or GRS (Government controlled styrene rubber) is prepared by the copolymerization of buta -

$1,\:3$ - diene (

$70\%$ ) and styrene (

$30\%$ ). The name Buna-S is made up of Bu which indicates Buta -

$1,\:3$ - diene, NA is for Sodium (

$Na$ ) and S indicates Styrene.

Option A is correct.

GRA is a copolymer of __________________.

0%
butadiene and acrylonitrile
0%
butadiene and adipic acid
0%
chloroprene and acrylonitrile
0%
chloroprene and adipic acid

Free radical polymerisation requires a free radical initiator. The most commonly used free radical initiator is:

0%
$Ph-CO-O-O-COPh$ (benzoylperoxide)
0%
$(CH_3)_3C-O-O-C(CH_3)_3$ (tert-butyl peroxide)
0%
$Ph-N-(NO)-Ph$ (azoxybenzene)
0%
$CH_2N_2$ (diazomethane)

Saran is a copolymer of ___________.

0%
vinyl chloride and vinyl acetate
0%
vinylidene chloride and vinyl chloride
0%
ethylene chloride and vinyl chloride
0%
vinyl acctate and methyl acetate

Explanation

Saran is a copolymer of vinylidene chloride (

$1,\:1$ -dichloroethene) and vinyl chloride.

$N_1,\ N_2, \ N_3,....$ are the number of molecules with molecular masses

$M_1,\ M_2,\ M_3, ...$ respectively, then mass average molar mass is expressed as :

0%
$\dfrac{\sum NiMi^2}{\sum NiMi}$
0%
$\dfrac{\sum NiMi}{\sum Ni}$
0%
$\dfrac{\sum Mi^2}{\sum Ni}$
0%
$\dfrac{\sum NiMi}{\sum Mi}$

Explanation

Polymer molecules come in different sizes (chain lengths for linear polymers) even ones of the same type.

So, the average molecular mass will depend on the method of averaging. The number average molecular mass is the ordinary arithmetic mean or average of the molecular masses of the individual macromolecules.

Thus, the right equation for mass average molar mass measurement is

$\dfrac{\sum NiMi^2}{\sum NiMi}$ .

Molecular weights of macromolecules are determined by :

0%
elevation of boiling point
0%
depression in freezing point
0%
osmotic pressure
0%
None of these

Average molecular mass of a polymer is determined by:

0%
light scattering and ultracentrifuge method.
0%
osmotic pressure.
0%
depression of freezing point.
0%
elevation in boiling point.

The monomer

$\left(G = Me \ or \ Cl\right)$ when treated with Zieglar - Natta catalyst undergo polymerisation as shown in the figure. Which of the following statement is not true considering the process given above?

0%
The general class of polymer formed is known as homopolymer
0%
The polymer obtained is stereoregular
0%
Buna-N can be prepared using above process
0%
Synthetic rubber can be formed by above process using $1,3$ - butadiene

Which one of the following is prepared using only one type of material ?

0%
Polycot
0%
Polywool
0%
Terrycot
0%
Polyester

Explanation

Polyester is a polymer that is made using only one type of material. It is a synthetic derived from coal, air, water and petroleum. The fibres are formed from the reaction between acid and alcohol.

In this

$2$ or more molecules combine to form a molecule whose structure repeats throughout the length.

Hence, option D is correct.

Which of the following statements is not true?

0%
Silk is a protein
0%
Polyurethane foams are used for making pillows
0%
HDPE is prepared by Ziegler Natta polymerization
0%
Viscose fabric is not made from cellulose

The polymer obtained with methylene bridges by condensation polymer is:

0%
PVC
0%
Buna-S
0%
Polyacrylonitrile
0%
Bakelite

The natural rubber is the polymer of

0%
1,3-butadiene
0%
Polyamide
0%
Isoprene
0%
None of these

Identify from the above monomers which undergo condensation polymerization.

0%
3, 5
0%
1, 3
0%
1, 6
0%
2, 4

Explanation

3 and 5 are addition polymers:
Addition polymers form:

When unsaturated carbon (organic) molecules react to form a long chain polymer molecule
No small molecules or atoms are eliminated during the reaction chloroethene (vinyl chloride) $CH_2=CHCl$ monomer forms polymer polyvinyl chloride (PVC) $-[-CH_2-CHCl-]n-$ (Tetrafluoroethene (tetrafluoroethylene))

$CF_2=CF_2$ monomer forms polymer polytetrafluorethene (polytetrafluoroethylene, teflon)

$-[CF_2-CF_2-]_n-$

Condensation polymers form:
When bifunctional monomers react to form a long chain polymer molecule small molecules, such as water, are eliminated during the reaction. Polyesters, polyamides, proteins and polysaccharides such as cellulose, are all examples of condensation polymers.
Example:
terephthalic acid + ethylene glycol gives polyethylene terephthalate (PET, PETE, or terylene or dacron)

$nHOOC-C_6H_4-COOH + nHO-(CH_2)_2-OH \rightarrow$

$-(-OC C_6H_4-COO-(CH_2)_2-O-)n- + (2n-1)H_2O$

The polymer used as packaging material in orthopaedic devices and for controlled drug release is:

0%
Kevlar
0%
PHBV
0%
Glyptal
0%
Bakelite

Explanation

PHBV [Poly(3-hydroxybutyrate-co-3-hydroxyvalerate)] find its applications in controlled release of drugs, medical implants and repairs, speciality packaging, orthopaedic devices and manufacturing bottles for consumer goods.
Hence, the correct option is

$B$

Formation of polyethylene from calcium carbide taken place as follows:

$CaC_2+2H_2O\rightarrow Ca(OH)_2+C_2H_2$

$C_2H_2+H_2\rightarrow C_2H_4$

$nC_2H_4\rightarrow (CH_2-CH_2)n$

The amount of polyethylene obtained from 64.0 kg of

$CaC_2$ is:

0%
27 kg
0%
24 kg
0%
22 kg
0%
28 kg

Explanation

$M_{CaC_2}=40 + 2 \times 12=64 g/mol$ ,

No. of moles of

$CaC_2$ in 64 Kg =1000 mole= No. of moles of

$C_2H_2$ formed= No. of moles of

$C_2H_4$ formed

Thus n=1000

Amount of polyethylene

$= 28\times 1000= 28000\ g= 28\ kg$

The structure of the polymer obtained by the following reaction is:

0%
I
0%
II
0%
III
0%
IV

The monomers of Buna-S rubber are:

0%
vinyl chloride and sulphur
0%
butadiene
0%
styrene and butadiene
0%
isoprene and butadiene

Explanation

Styrene and 1,3 butadiene polymerizes in the presence of

$Na$ metal and forms Buna-S rubber.

So, the monomer units in Buna-S rubber are Styrene and 1,3 butadiene.

Hence, option C is correct.

Soft drink and baby feeding bottles are generally made up of:

0%
Polyester
0%
Polyurethane
0%
Polyurea
0%
Polystyrene

In the reaction sequence,

$X$ is:

0%
cyclohexanone
0%
caprolactam
0%
$HO(CH_2)_6NH_2$
0%
hexamethyline disocyanate

Explanation

Caprolactam is the monomer of nylon-

$6$ . Nylon

$- 6$ is made by heating caprolactam to about

$250^0\ C$ with about

$5-10\%$ water thrown in.

Hence, the compound X is caprolactam.

Which of the following is fully fluorinated polymer?

0%
Neoprene
0%
Teflon
0%
Thiokol
0%
PVC

Explanation

Hint: A large molecule made up of small repeating subunits is termed as a polymer.

Explanation:

Neoprene is a polymer of the chlorine-containing compound. The molecular formula of the subunit is $CH_2=CCl-CH=CH_2$ .
Teflon is a polymer of tetrafluoroethylene. The chemical formula of the subunit is $C_2F_4$ .
So, it is a fully fluorinated polymer.
Thiokol is a polymer of ethylene thiosulphide.the chemical formula of the subunit is $CH_2CH_2S_4$ .
PVC stands for polyvinyl chloride. The chemical formula is $CH_2CHCl$ .

Since the constituent unit that contains fluorine in it is Teflon.

Correct Option: $B$

Bakelite is formed by the reaction of:

0%
phenol and formaldehyde
0%
formaldehyde and aniline
0%
adipic acid and ethylene glycol
0%
phthalic acid and ethylene glycol

Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.

$CH_2=CH-C_6H_4(NO_2)$
II.

$CH_2=CH-C_6H_4(CH_3)$
III.

$CH_2=CH-C_6H_4(OCH_3)$

0%
$I > II > III$
0%
$II > I > II$
0%
$III > II > I$
0%
$I > III > II$

Explanation

Electron releasing groups such as

$-CH_3, -OCH_3$ activate the monomer towards cationic polymer as it stabilizes the carbocation formed. On the other hand,

$-NO_2$ is an electron-withdrawing group. So, it reduces the stability of carbocation formed.

Thus, the correct order is:

$CH_2=CH-C_6H_4(OCH_3) > CH_2=CH-C_6H_4(CH_3) >CH_2=CH-C_6H_4(NO_2)$ .

Novolac on heating with formaldehyde undergoes _______ to form an infusible solid mass called _______.

0%
polymerization, melamine
0%
vulcanization, resin
0%
cross-liking, bakelite
0%
condensation, polystyrene

In which of the following polymers, ethylene glycol is one of the monomer units?

0%
0%
$(\!\!\!\!-CH_2 - CH_2 -\!\!\!\!)_n$
0%
0%
$[\!\!\!- O - \underset{CH_3}{\underset{|\,\,\,\,\,}{CH}} - CH_2 - \underset{O}{\underset{||}{C}} - O - \underset{\,\,\,\,\,CH_2CH_3}{\underset{|\,\,\,\,\,\,}{CH}} - CH_2 - \underset{O}{\underset{||}{C}} -\!\!\!]_n$

Match the column I with column II and mark the appropriate choice.

	Column I		Column II
(A)	PVC	(i)	Rubber
(B)	Condensation polymer	(ii)	Thermoplsatic
(C)	Polysaccharide	(iii)	Dacron
(D)	Elastomer	(iv)	Natural Polymer

0%
(A) $\rightarrow$ (ii), (B) $\rightarrow$ (iii), (C) $\rightarrow$ (iv), (D) $\rightarrow$ (i)
0%
(A) $\rightarrow$ (i), (B) $\rightarrow$ (ii), (C) $\rightarrow$ (iv), (D) $\rightarrow$ (iii)
0%
(A) $\rightarrow$ (iii), (B) $\rightarrow$ (iv), (C) $\rightarrow$ (i), (D) $\rightarrow$ (ii)
0%
(A) $\rightarrow$ (iv), (B) $\rightarrow$ (i), (C) $\rightarrow$ (iii), (D) $\rightarrow$ (ii)

Synthetic rubbers are usually obtained by copolymerisation of:

0%
styrene and $1, 3$ - butadiene
0%
$1, 4$ - polyisoprene
0%
urea and formaldehyde
0%
alkane and $1, 3$ - butadiene

The difference in the densities of low-density (LDP) and high-density polymers (HDP) is due to the fact that:

0%
LDP are highly branched structures while HDP consists of closely packed linear molecules
0%
LDP are linear chains while HDP are branched chains of polythene
0%
both LDP and HDP are unbranched linear chains with different lengths
0%
at high temperature, the density of polymer is reduced

Which one of the following is a condensation polymer?

0%
PVC
0%
Teflon
0%
Dacron
0%
Polystyrene

Natural rubber or raw rubber consists of basic material latex which is a dispersion of isoprene. During the treatment, this isoprene forms a high molecular weight polymer of isoprene. Natural rubber can be obtained from five hundred different species of plants.
Which rubber is not a polydiene?

0%
Polyisoprene
0%
Polychloroprene
0%
Thiokal rubber
0%
Nitrile rubber

Explanation

Thiokol rubber is a type of artificial elastomer, which is invariably a polymer.

it can be prepared by the condensation of 1,2-dichloroethane with sodium polysulphide. It does not contain any

$C=C$ bond. So it is not a polydiene.

Which of the following is a natural polymer?

0%
Polyester
0%
Glyptal
0%
Starch
0%
Nylon-6

Explanation

Natural Polymers are those substances which are obtained naturally.

Polyester is a synthetic fiber derived from coal, air, water, and petroleum.

Glyptal is formed by ethylene glycol and phthalic acid formed by step-growth polymerization.

Starch or amylum is a polymeric carbohydrate consisting of numerous glucose units joined by glycosidic bonds. This polysaccharide is produced by most green plants as energy storage and hence, naturally occurring polymer.

Nylon-6 is made from one kind of monomer called caprolactam.

Hence, option

$C$ is correct.

Match the column I with column II and mark the appropriate choice.

	Column I		Column II
(A)	Buna-N	(i)	Phthalic acid and ethylene glycol
(B)	Nylon-6,6	(ii)	Terephthalic acid and ethylene glycol
(C)	Dacron	(iii)	Hexamethylenediamine and adipic acid
(D)	Glyptal plastic	(iv)	Acrylonitrile and butadiene

0%
(A) $\rightarrow$ (ii), (B) $\rightarrow$ (iii), (C) $\rightarrow$ (iv), (D) $\rightarrow$ (i)
0%
(A) $\rightarrow$ (i), (B) $\rightarrow$ (ii), (C) $\rightarrow$ (iv), (D) $\rightarrow$ (i)
0%
(A) $\rightarrow$ (iii), (B) $\rightarrow$ (iv), (C) $\rightarrow$ (i), (D) $\rightarrow$ (ii)
0%
(A) $\rightarrow$ (iv), (B) $\rightarrow$ (iii), (C) $\rightarrow$ (ii), (D) $\rightarrow$ (i)

Explanation

Buna $-N$	(iv) Acrylonitrile and butadiene
Nylon-6,6	(iii) Hexamethylenediamine and adipic acid
Dacron	(ii) Terephthalic acid and ethylene glycol
Glyptal plastic	(i) Phthalic acid and ethylene glycol

Condensation polymerisation

This type of polymerisation generally involves a repetitive condensation reaction between two bi-functional monomers. These polycondensation reactions may result in the loss of some simple molecules as water, alcohol, etc., and lead to the formation of high molecular mass condensation polymers

The correct option is [D].

The monomers of biodegradable polymer, nylon 2-nylon 6 are:

0%
glycine + adipic acid
0%
glycol + phthalic acid
0%
phenol + urea
0%
glycine + amino caproic acid

Explanation

Nylon 2-nylon 6 is an alternating polyamide copolymer of glycine

$(H_2N–CH_2–COOH)$ and aminocaproic acid

$[H_2N (CH_2)_5 COOH]$ .

Hence, the correct answer is option

$\text{D}$ .

Match the polymers given in column I with monomers in column II and mark the appropriate choice.

0%
(A) $\rightarrow$ (iv), (B) $\rightarrow$ (ii), (C) $\rightarrow$ (i), (D) $\rightarrow$ (iii)
0%
(A) $\rightarrow$ (i), (B) $\rightarrow$ (iii), (C) $\rightarrow$ (iv), (D) $\rightarrow$ (ii)
0%
(A) $\rightarrow$ (iv), (B) $\rightarrow$ (i), (C) $\rightarrow$ (ii), (D) $\rightarrow$ (iii)
0%
(A) $\rightarrow$ (ii), (B) $\rightarrow$ (iv), (C) $\rightarrow$ (iii), (D) $\rightarrow$ (i)

Explanation

Melamine formaldehyde polymer- (iv) melamine+formaldehyde

Bakelite - (i) phenol + formaldehyde

Neoprene - (ii) 2-chloro 1,3 butadiene (Chloroprene)

Natural rubber - (iii) 2-methyl 1,3 butadiene (isoprene)

Formation of phenol-formaldehyde polymer-

These are obtained by the condensation reaction of phenol with formaldehyde in the presence of either an acid or a base catalyst. The reaction starts with the initial formation of o-and/or p-hydroxymethyl phenols derivatives, which further react with phenol to form compounds having rings joined to each other through –

$CH_2$ groups. The initial product could be a linear product like novolac.

The correct option is

$[C]$ .

Nylon-

$6$ is prepared by linear condensation homopolymerization reaction of:

0%
caprolactum
0%
hexamethylene diamine and adipic acid
0%
$6$ -aminohexanoic acid
0%
acrylonitrile

Explanation

Solution:- (A) Caprolactam

Nylon-

$6$ is prepared by linear condensation homopolymerization reaction of caprolactam.

$n \left( \text{Caprolactum} \right) \xrightarrow[{N}_{2}]{533 \; K} \text{Nylon}-6$

Which monomer is responsible for the flexibility property in

$PHBV$ ?

0%
$HO -\underset {\underset {CH_{3}}{|\,\,\,\,}}{CH} - CH_{3} - COOH$
0%
$HO - \underset {\underset {\,\,\,\,\,\,\,\,CH_{2} - CH_{3}}{|\,\,\,\,}}{CH} - CH_{2} - COOH$
0%
$HO - \underset {\underset {CH_{3}}{|\,\,\,\,\,}}{CH} - CH_{2} - CH_{2} - COOH$
0%
$HO - \underset {\underset {\,\,\,\,\,\,\,CH_{2} -CH_{3}}{|\,\,\,\,\,\,}}{CH} - CH_{2} - CHO$

Identify X and Y in the given polymerization reactions :

0%
X = Bakelite, Y = Novolac
0%
X = Novolac, Y = Melamine
0%
X = Bakelite, Y = Malamine
0%
X = Novolac, Y = Bakelite

The monomer that undergo radical polymerisation most easily is?

0%
$CH_2=CH_2$
0%
$C_6H_5CH=CH_2$
0%
$CH_2=C{(Me)}_2$
0%
$CH_3-CH=CH_2$

Which polymer is matched with incorrect use?

0%
High density polythene $-$ Buckets, pipes
0%
Nylon 6,6 $-$ Ropes, bristles for brushes
0%
Orlon $-$ Synthetic wool, carpets
0%
Glyptal $-$ Electrical switches, combs

Which of the following polymer is biodegradable?

0%
$-\!\!\!(CH_2-\underset{Cl}{\underset{|}{C}}=CH-CH_2)\!\!\!-_n$
0%
$-\!\!\!(CH_2-CH=CH-CH_2-CH_2-\overset{CN}{\overset{|}{CH}})\!\!\!-_n$
0%
$-\!\!\!(O-\underset{CH_3}{\underset{|}{CH}}-CH_2-\underset{O}{\underset{||}{C}}-O-\underset{CH_2CH_3}{\underset{|}{CH}}-CH_2-\underset{O}{\underset{||}{C}})\!\!\!-_n$
0%
$-\!\!\!(\overset{H}{\overset{|}{N}}-(CH_2)_6-\overset{H}{\overset{|}{N}}-\overset{O}{\overset{||}{C}}-(CH_2)_4-\overset{O}{\overset{||}{C}})\!\!\!-_n$

Explanation

In view of the general awareness and concern for the problems created by the polymeric solid wastes, certain new biodegradable synthetic polymers have been designed and developed. These polymers contain functional groups similar to the functional groups present in biopolymers.

Example- PHBV.

The correct option is [C].

$\underset{3-Hydroxybutanoic\, acid}{CH_3-\overset{OH}{\overset{|}{CH}}-CH_2-COOH}\,+\, \underset{3-Hydroxypentanoic\, acid}{CH_3-CH_2\overset{OH}{\overset{|}{CH}}-CH_2-COOH} \rightarrow\underset{PHBV}{ -\!\!\!(O-\underset{CH_3}{\underset{|}{CH}}-CH_2-\underset{O}{\underset{||}{C}}-O-\underset{CH_2CH_3}{\underset{|}{CH}}-CH_2-\underset{O}{\underset{||}{C}})\!\!\!-_n}$

Which one of the following is an elastomer?

The copolymer formed by addition polymerization of styrene and acrylonitrile in the presence of peroxide is:

CBSE Questions for Class 12 Engineering Chemistry Polymers Quiz 12 - MCQExams.com

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Practice Class 12 Engineering Chemistry Quiz Questions and Answers

CBSE Questions for Class 12 Engineering Chemistry Polymers Quiz 12 - MCQExams.com

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Practice Class 12 Engineering Chemistry Quiz Questions and Answers

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