Explanation
An activity coefficient is a factor used in thermodynamics to account for deviations from ideal behavior in a mixture of chemical substances. Hence, for an ideal liquid solution, that deviation is 0, as the mole fraction of other substance is 0. So, the activity coefficient is unity.
Given: Mass of $$N_{2}$$ = 56g
Mass of $$CO_{2}$$ = 44g
Mass of $$CH_{4}$$ = 16g
Solution: Moles of $$N_{2}$$ = $$\dfrac{56}{28}$$ = 2
Moles of $$CO_{2}$$ = $$\dfrac{44}{44}$$ = 1
Moles of $$CH_{4}$$ = $$\dfrac{16}{16}$$ = 1
Now, as we know, partial pressure of a gaseous component = mole fraction of the component * total pressure
Thus, partial pressure of $$CH_{4}$$ = ($$\dfrac{1}{2 + 1 +1}$$ * 720) mm Hg
= 180 mm Hg
Thus, the correct option is (B).
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