Explanation
As we know the Partial pressure of A is greater than B in pure state means A is more volatile than B, Therefore A is more in the vapour state.
From Raoult's law, $$P_A=P_{A}^{0} \times x_{A}$$
In vapour phase,
$$ x_{A} > x_{B} $$ $$[\because B.P. _{A} < B.P._{B}]$$In liquid phase,$$ x_{B} > x_{A} $$Comparing A itself in liquid and vapour phase$$ x_{A} (vapour) > x_{A} (liquid)$$
The correct option is C.
When salt is added to water for making the solution, the vapour pressure of solution gets decreases. This is because due to a decrease in the surface covered by the solvent molecule which leads to a decrease in the number of solvent molecule escaping from the surface corresponding to pure solvent.
It must be noted that NaCl is a non-volatile solute and it will reduce the vapour pressure of the solution. So, the vapour pressure of pure water in container A is more than in container B. Hence, vapour pressure also get reduces.
So, the correct option is A.
For an ideal solution with spontaneous process, according to Raoult's law, for an ideal solution
$$\Delta H = 0$$
$$\Delta V _{mix} = 0 $$
Since there is no exchange of the heat energy between system and surroundings
$$\Delta S_{surroundings} = 0 $$
Thus $$\Delta S_{sys} = +ve$$
Now, from the relation
$$ \Delta{G} = \Delta{H} –T \Delta{S}$$
$$\Delta G$$ will be –ve.
So, ii, iii and iv are correct.
$$18.0\ g$$ of glucose$$\left( {{C_6}{H_{12}}{O_6}} \right)$$ is added to $$178.2\ g$$ of water. The vapour pressure of water for this aqueous solution at $${100^o}\ C$$ is :
Given
Colorless gas - $$X$$
Brown gas - $$Y$$
The bromine does not change its color at a given temperature, but nitrogen dioxide and dinitrogen tetraoxide change their color at a given temperature and give the same color as given in the question.
Heat dinitrogen tetroxide
$${N_2}{O_4}$$ $$\xrightarrow{{{{160}^{\rm O}}C}}$$ $$2N{O_2}$$ $$\xrightarrow{{{{600}^{\rm O}}C}}$$ $$2NO$$ $$ + $$ $${O_2}$$
In this reaction,
$${N_2}{O_4}$$ - dinitrogen tetroxide (colorless)
$$2N{O_2}$$ - nitrogen dioxide (brown)
$$2NO$$ - Nitric oxide (colorless)
Therefore, the name of $$Y$$ gas is dinitrogen tetroxide that is brown.
Hence, option (C) is the correct answer.
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