Explanation
The most abundant element in the earths crust by weight is oxygen.
When calcium nitride reacts with di nitrogen it forms ammonia and calcium hydroxide.
$$Ca_3N_2 + 6 H_2O\rightarrow 3 Ca(OH)_2 + 2 NH_3$$.
Preparation of Ammonia:
$$N_2 + 3H_2\rightarrow 2NH_3$$
At high pressure about 200-250 atm, and a moderate temperature of $$750K$$, the reaction takes place. Removal of ammonia is done by liquefaction, In the process, iron is used as a catalyst and molybdenum as a promoter.
When $$CaNH$$ reacts with hot water it forms $$NH_3,Ca(OH)_2$$.
$$CaNH+2H_2O\rightarrow Ca(OH)_2+NH_3$$.
Manganese dioxide($$MnO_2$$) is heated with concentrated $$HCl$$ to form $$Cl_2$$
$$MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O$$
$$HCl$$ in action with potassium permanganate gives $$C_2$$
$$2KMnO_4+16HCl\rightarrow 2KCl+2MnCl_2+8H_2O+5Cl_2$$.
Hence option A and C is correct.
The structure of white phosphorus is tetrahedral.Phosphorus or s tetraphosphorus ($$P_4$$) exists as molecules made up of four atoms in a tetrahedral structure. The molecule is described as consisting of six single P–P bonds.
Hence option C is correct.
$$NH_4NO_2$$ will not give ammonia on heating.It gives $$NO_2H_2O$$
$$NH_4NO_2(s)\rightarrow N_2(g) + 2H_2O(g)$$
Oxygen florides forms $$HF,O_2$$ on hydrolysis.
$$OF_2 + H_2O\rightarrow O_2 + 2 HF$$
$$2O_2F_2 + 2H2O\rightarrow O_2 + 4HF$$
so oxygen florides do not form forms hypohalous acids.
So the given statement oxygen florides forms oxoacids is wrong.
N-N sigma bond (single bod) is weaker than P-P sigma bond (single bond) due to the small bond length between the nitrogen atoms. The lone pair of electrons of both the atoms nitrogen repel each other making the single bon between $$N-N$$ weaker than P-P sigma bond.In $$P-P$$ bond the repulsion between sigma bond and lone pair electrons is less as the size of phosphorous is large.
So statement A is wrong.
Hence option A is correct.
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