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CBSE Questions for Class 5 Maths Parts And Whole Quiz 4 - MCQExams.com
CBSE
Class 5 Maths
Parts And Whole
Quiz 4
$$ \displaystyle \frac{2}{7} $$ of a week $$=$$ _____ days
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0%
$$7$$
0%
$$3$$
0%
$$4$$
0%
$$2$$
Explanation
One week has $$7$$ days
So, $$\dfrac{2}{7} $$ of a week $$=\dfrac{2}{7}\times 7=2$$ days.
Hence, the answer is $$2$$.
$$ \displaystyle \frac{1}{7} $$ of $$49$$ litre $$=$$ ____litre
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0%
$$1$$
0%
$$5$$
0%
$$7$$
0%
$$6$$
Explanation
$$\dfrac{1}{7}$$ of $$49$$ litre $$=\dfrac{1}{7}\times 49=7$$ litre.
Hence, the answer is $$7$$.
In a unit fraction the numerator is ____.
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0%
$$0$$
0%
$$1$$
0%
$$2$$
0%
$$3$$
Explanation
In a unit fraction, the numerator is $$1$$.
Thus, the answer is $$1$$.
Two-fifth of $$10$$ litre $$=$$ _____ litres
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0%
$$2$$
0%
$$3$$
0%
$$4$$
0%
$$5$$
Explanation
$$\dfrac{2}{5} $$ of $$10$$ litre $$=\dfrac{2}{5}\times 10=4$$ litres.
Hence, the answer is $$4$$
$$\displaystyle \frac{2}{5} $$ of a rupee = ____ paise
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0%
$$20$$
0%
$$10$$
0%
$$40$$
0%
$$50$$
Explanation
We know that $$1$$ Rs $$=100$$ paisa.
So, $$\dfrac{2}{5} \times 100=40$$ paisa.
Hence, the answer is $$40$$.
Which of the following is an improper fraction?
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0%
0%
0%
0%
Explanation
The fraction that represents the figure is $$\displaystyle \frac{9}{9}$$ It is an improper fraction
Here is a collection of $$6$$ shapes. Of the $$6$$ shapes, $$5$$ are shaded. The fraction of the unshaded shapes is:
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$$\displaystyle \frac{5}{6}$$
0%
$$\displaystyle \frac{4}{6}$$
0%
$$\displaystyle \frac{1}{6}$$
0%
$$\displaystyle \frac{3}{6}$$
Explanation
Total number of shapes $$=6$$
Total number of shaded shapes $$=5$$
Total number of unshaded shapes $$=1$$
So the fraction of unshaded shape is $$\frac{1}{6}$$..
The model is shaded to show which fraction?
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0%
$$\displaystyle \frac{1}{4}$$
0%
$$\displaystyle \frac{3}{4}$$
0%
$$\displaystyle \frac{1}{3}$$
0%
$$\displaystyle \frac{2}{3}$$
Explanation
The given figure has $$4$$ equal parts in the shape of triangles.
Out of $$4$$, one part is shaded and $$3$$ parts are not shaded.
So, the fraction of shaded to the whole part is $$\dfrac{1}{4}$$.
How many one-sevenths make one?
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0%
$$17$$
0%
$$1$$
0%
$$7$$
0%
$$5$$
Explanation
There are $$7$$ one seventh which make the one.
One seventh means $$\dfrac{1}{7}$$.
So, if add this one seventh seven times we will get the whole.
Hence, the answer is $$7$$.
What fraction of the fruits (total $$8$$) on the plate are apples?
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0%
$$\displaystyle \frac{3}{8}$$
0%
$$\displaystyle \frac{5}{8}$$
0%
$$\displaystyle \frac{3}{5}$$
0%
$$\displaystyle \frac{5}{3}$$
Explanation
Total number of fruit is $$8$$.
The number of apple is $$3$$.
The fractional part of apple to the fruits is $$\dfrac{3}{8}$$.
Hence, the answer is $$\dfrac{3}{8}$$.
Consider the shown figure represents the flag of a country. How much part of it is covered with stripes?
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0%
$$\dfrac{1}{4}$$
0%
$$\dfrac{1}{3}$$
0%
$$\dfrac{2}{3}$$
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$$\dfrac{1}{2}$$
Explanation
Total number of divisions in flag $$= 3$$
Striped divisions $$= 1$$
$$\Rightarrow$$ Part of flag covered with stripes $$=$$ Striped divisions $$\div$$ Total divisions $$= \dfrac{1}{3}$$
Find the mean of the given fractions:
$$2\dfrac {1}{7}$$ and $$3\dfrac {1}{7}$$
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0%
$$\dfrac {37}{7}$$
0%
$$\dfrac {19}{7}$$
0%
$$\dfrac {37}{14}$$
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$$2$$
Explanation
The given fractions are
$$2\dfrac {1}{7}$$ and $$3\dfrac {1}{7}$$
$$Mean = \dfrac{\left (2\dfrac {1}{7}+3\dfrac {1}{7}\right )}{2} $$
$$= \dfrac{\left (\dfrac {15}{7} + \dfrac {22}{7}\right )}{2} $$
$$= \left (\dfrac {15 + 22}{7}\right ) \times \dfrac {1}{2}$$
$$ = \dfrac {37}{7}\times \dfrac {1}{2}$$
$$= \dfrac {37}{14}$$
Hence, the mean of the given fractions is $$ \dfrac {37}{14}$$ .
A handkerchief is divided in four squares. Each part is to be embroidered with a flower. How much part has design of flower?
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0%
$$\dfrac{3}{4}$$
0%
$$\dfrac{1}{4}$$
0%
$$\dfrac{1}{2}$$
0%
$$\dfrac{1}{3}$$
Explanation
Total number of divisions in handkerchief $$= 4$$
Divisions with embroidery $$= 3$$
$$\Rightarrow$$ Parts with design $$=$$ Embroidered divisions $$\div$$ Total divisions $$= \dfrac{3}{4}$$
What fraction is represented by all of these figures?
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0%
$$\dfrac{1}{2}$$
0%
$$\dfrac{1}{3}$$
0%
$$\dfrac{2}{3}$$
0%
$$\dfrac{1}{4}$$
Explanation
In the given first object, there are a total of $$2$$
rectangles
and $$1$$
rectangle
is shaded amongst them. Therefore, the ratio of shaded
rectangles
to the total number of
rectangles
is:
$$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 2 }$$
Now, consider the second object, there are a total of $$4$$
squares
and $$2$$
squares
are shaded amongst them. Therefore, the ratio of shaded
squares
to the total number of
squares
is:
$$\dfrac {Shaded}{Total}=\dfrac {2 }{ 4 }=\dfrac {1}{2}$$
Now, in the third object,
there are a total of $$6$$
rectangles
and $$3$$
rectangles
are shaded amongst them. Therefore, the ratio of shaded
rectangles
to the total number of
rectangles
is:
$$\dfrac {Shaded}{Total}=\dfrac { 3 }{ 6 }=\dfrac {1}{2}$$
Since the
fraction of
all of the three given objects is same that is $$\dfrac {1}{2}$$.
Hence, the fraction
$$\dfrac {1}{2}$$ represented by all of the given figures
.
What part of the rectangle is coloured?
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0%
$$\dfrac{4}{16}$$
0%
$$\dfrac{1}{6}$$
0%
$$\dfrac{1}{4}$$
0%
Both A and C
Write the equivalent fractions represented by the shaded portions of these figures.
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$$\cfrac { 2 }{ 10 } =\cfrac { 3 }{ 5 } $$
0%
$$\cfrac { 6 }{ 15 } =\cfrac { 2 }{ 5 } $$
0%
$$\cfrac { 6 }{ 10 } =\cfrac { 2 }{ 5 } $$
0%
$$\cfrac { 3 }{ 15 } =\cfrac { 1 }{ 5 } $$
Explanation
Given: The shaded portion of the figures
Total boxes in the figure $$1=15$$
Shaded boxes in the figure $$1=6$$
Equivalent fraction $$=\dfrac{6}{15}$$ (figure 1)
Total boxes in the figure $$2=5$$
Shaded boxes in the figure $$2=2$$
Equivalent fraction $$=\dfrac{2}{5}$$ (figure 2)
$$\therefore$$ option B is correct.
What fraction of the figure is shaded?
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$$\displaystyle\frac{7}{16}$$
0%
$$\displaystyle\frac{1}{2}$$
0%
$$\displaystyle\frac{9}{16}$$
0%
$$\displaystyle\frac{17}{32}$$
Explanation
If we rearrange the figure then we can conclude that half of the square is shaded
$$\therefore$$ The total fraction of figure shaded is $$\dfrac{1}{2}$$
Hence the correct answer is option B.
Identify the figure which represent equal parts?
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2 and 3
0%
1 and 2
0%
1 and 3
0%
2 and 4
Explanation
In the given first circular object, there are a total of $$4$$
parts
and $$1$$
part
is shaded amongst them. Therefore, the ratio of shaded
part
to the total number of
parts
is:
$$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 4 }$$
Now, consider the second circular object, there are a total of $$4$$
parts
and $$2$$
parts
are shaded amongst them. Therefore, the ratio of shaded
parts
to the total number of
parts
is:
$$\dfrac {Shaded}{Total}=\dfrac {2 }{ 4 }=\dfrac {1}{2}$$
Now, in the third object,
there are a total of $$4$$
squares
and $$3$$
squares
are shaded amongst them. Therefore, the ratio of shaded
squares
to the total number of
squares
is:
$$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 4 }$$
Finally, in the last object,
there are a total of $$4$$
squares
and none of the
squares
are shaded amongst them. Therefore, the ratio of shaded
squares
to the total number of
squares
is:
$$\dfrac {Shaded}{Total}=\dfrac { 0 }{ 4 }=0$$
Since the
fraction of
all of first and third objects is same that is $$\dfrac {1}{4}$$.
Hence, the figure 1 and 3 represents the equal parts
.
Which figure shows greater fraction?
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0%
Fig. a shows greater fraction.
0%
Fig. b shows greater fraction.
0%
None
0%
we cannot say.
Explanation
In the given first
circular
object,
there are a total of $$4$$
parts
and $$1$$
part
is shaded amongst them. Therefore, the ratio of shaded
part
to the total number of
parts
is:
$$\dfrac {Shaded}{Total}=\dfrac {1 }{ 4 }$$
Now, consider the second circular object, there are a total of $$8$$
parts
and $$1$$
part
is shaded amongst them. Therefore, the ratio of shaded
part
to the total number of
parts
is:
$$\dfrac {Shaded}{Total}=\dfrac {1 }{ 8 }$$
Since the fraction $$\dfrac {1}{4}=0.25$$ and
$$\dfrac {1}{8}=0.125$$, that means the fraction
$$\dfrac {1}{4}$$ is greater than
$$\dfrac {1}{8}$$.
Hence, figure a is greater than figure b
.
Is the simplified fraction form:
$$6\times \cfrac { 1 }{ 5 } $$
$$=1\cfrac { 2 }{ 5 } $$
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0%
True
0%
False
Explanation
We have, $$6\times\dfrac{1}{5}=\cfrac{6}{5}=\cfrac{1\times5+1}{5}=1\cfrac{1}{5}\quad[\because a\cfrac{b}{c}=\cfrac{a\times c+b}{c}]$$
So, above statement is false.
Hence, $$\text{B}$$ is the correct option.
How many of the shape of the given figure must be shaded so that $$\dfrac {2}{5}$$ of the figure is unshaded?
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0%
$$5$$
0%
$$10$$
0%
$$15$$
0%
$$20$$
Explanation
Total number of shapes $$= 25$$
Unshaded fraction $$= \dfrac {2}{5}$$
$$\therefore$$ Shaded fraction $$= 1 - \dfrac {2}{5} $$
$$= \dfrac {3}{5}$$
Now, number of shape to be shaded $$= \dfrac {3}{5}\times 25 $$
$$= 15$$
Hence, option $$C$$ is correct.
State true/false:
For the given ,
$$\dfrac{6}{7} \times 2$$
the answer as a mixed fraction is
$$1\dfrac{5}{7} $$
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0%
True
0%
False
Explanation
$$\dfrac{6}{7} \times 2$$
Can be written as
$$=\dfrac{12}{7} $$
$$=1\dfrac{5}{7} $$
In which figure does the shaded part represents $$0.3$$?
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0%
0%
0%
What fraction of the figure is shaded.
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0%
$$\displaystyle\frac{1}{4}$$
0%
$$\displaystyle\frac{3}{8}$$
0%
$$\displaystyle\frac{5}{8}$$
0%
$$\displaystyle\frac{8}{11}$$
Explanation
$$\Rightarrow$$ Total number of equal parts = $$8$$
$$\Rightarrow$$ Number of shaded parts = $$3$$
$$\therefore$$ Shaded fraction = $$\dfrac{Shaded\,\,parts}{Total\,number\,of\,equal\,parts}$$
$$\therefore$$ Shaded fraction =
$$\dfrac{3}{8}$$
Pictorial representation of $$3\times \displaystyle \frac{2}{3}$$ is?
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0%
0%
0%
0%
Explanation
We have given Pictorial representation of $$3\times \dfrac{2}{3}$$
$$\Rightarrow$$ $$3\times \dfrac{2}{3}=\dfrac{2}{3}+\dfrac{2}{3}+\dfrac{2}{3}$$
$$\therefore$$ Option $$B$$ is correct answer.
What is the sum of shaded parts of the given figures?
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0%
1$$\dfrac{2}{3}$$
0%
1$$\dfrac{1}{4}$$
0%
1$$\dfrac{3}{4}$$
0%
2$$\dfrac{1}{4}$$
Explanation
In figure I,
Total number of equal parts $$=4$$
Number of shaded parts $$= 3$$
Therefore shaded fraction $$=\dfrac{3}{4}$$
In figure II,
Total number of equal parts $$= 16$$
Number of shaded parts $$=8$$
Therefore shaded fraction $$=\dfrac{8}{16}=\dfrac{1}{2}$$
So, required sum $$=\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{3+2}{4}=\dfrac{5}{4}= 1\dfrac{1}{4}$$
$$\dfrac { 2 }{ 5 }$$ of 15 is
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0%
4
0%
7
0%
6
0%
9
Explanation
$$\dfrac{2}{5}$$
$$\times 15$$
= 6
How many $$\frac{1}{8}$$ are there in $$\frac{1}{2}$$?
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0%
3
0%
4
0%
6
0%
8
Represent the answer in fraction
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0%
$$\dfrac{2}{4}$$
0%
$$\dfrac{1}{4}$$
0%
$$\dfrac{1}{2}$$
0%
Both A and C
Which of the following options represents $$\displaystyle\frac{3}{4}$$ of $$8$$ parts shaded?
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0%
0%
0%
0%
None of these
Explanation
We know, $$\dfrac{3}{4}\,of\,8=\dfrac{3}{4}\times 8=6$$
$$\Rightarrow$$ So, in option $$B$$ has 6 parts shaded out of $$8$$
$$\therefore$$ Correct answer is option $$B$$.
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