MCQ Questions for Class 5 Maths Parts And Whole Quiz 4

$\displaystyle \frac{2}{7}$ of a week

$=$ _____ days

0%
$7$
0%
$3$
0%
$4$
0%
$2$

Explanation

One week has

$7$ days

So,

$\dfrac{2}{7}$ of a week

$=\dfrac{2}{7}\times 7=2$ days.

Hence, the answer is

$2$ .

$\displaystyle \frac{1}{7}$ of

$49$ litre

$=$ ____litre

0%
$1$
0%
$5$
0%
$7$
0%
$6$

Explanation

$\dfrac{1}{7}$ of

$49$ litre

$=\dfrac{1}{7}\times 49=7$ litre.

Hence, the answer is

$7$ .

In a unit fraction the numerator is ____.

0%
$0$
0%
$1$
0%
$2$
0%
$3$

Explanation

In a unit fraction, the numerator is

$1$ .

Thus, the answer is

$1$ .

Two-fifth of

$10$ litre

$=$ _____ litres

0%
$2$
0%
$3$
0%
$4$
0%
$5$

Explanation

$\dfrac{2}{5}$ of

$10$ litre

$=\dfrac{2}{5}\times 10=4$ litres.

Hence, the answer is

$4$

$\displaystyle \frac{2}{5}$ of a rupee = ____ paise

0%
$20$
0%
$10$
0%
$40$
0%
$50$

Explanation

We know that

$1$ Rs

$=100$ paisa.

So,

$\dfrac{2}{5} \times 100=40$ paisa.

Hence, the answer is

$40$ .

Which of the following is an improper fraction?

Explanation

The fraction that represents the figure is

$\displaystyle \frac{9}{9}$ It is an improper fraction

Here is a collection of

$6$ shapes. Of the

$6$ shapes,

$5$ are shaded. The fraction of the unshaded shapes is:

0%
$\displaystyle \frac{5}{6}$
0%
$\displaystyle \frac{4}{6}$
0%
$\displaystyle \frac{1}{6}$
0%
$\displaystyle \frac{3}{6}$

Explanation

Total number of shapes

$=6$

Total number of shaded shapes

$=5$

Total number of unshaded shapes

$=1$

So the fraction of unshaded shape is

$\frac{1}{6}$ ..

The model is shaded to show which fraction?

0%
$\displaystyle \frac{1}{4}$
0%
$\displaystyle \frac{3}{4}$
0%
$\displaystyle \frac{1}{3}$
0%
$\displaystyle \frac{2}{3}$

Explanation

The given figure has

$4$ equal parts in the shape of triangles.

Out of

$4$ , one part is shaded and

$3$ parts are not shaded.

So, the fraction of shaded to the whole part is

$\dfrac{1}{4}$ .

How many one-sevenths make one?

0%
$17$
0%
$1$
0%
$7$
0%
$5$

Explanation

There are

$7$ one seventh which make the one.

One seventh means

$\dfrac{1}{7}$ .

So, if add this one seventh seven times we will get the whole.

Hence, the answer is

$7$ .

What fraction of the fruits (total

$8$ ) on the plate are apples?

0%
$\displaystyle \frac{3}{8}$
0%
$\displaystyle \frac{5}{8}$
0%
$\displaystyle \frac{3}{5}$
0%
$\displaystyle \frac{5}{3}$

Explanation

Total number of fruit is

$8$ .

The number of apple is

$3$ .

The fractional part of apple to the fruits is

$\dfrac{3}{8}$ .

Hence, the answer is

$\dfrac{3}{8}$ .

Consider the shown figure represents the flag of a country. How much part of it is covered with stripes?

0%
$\dfrac{1}{4}$
0%
$\dfrac{1}{3}$
0%
$\dfrac{2}{3}$
0%
$\dfrac{1}{2}$

Explanation

Total number of divisions in flag

$= 3$

Striped divisions

$= 1$

$\Rightarrow$ Part of flag covered with stripes

$=$ Striped divisions

$\div$ Total divisions

$= \dfrac{1}{3}$

Find the mean of the given fractions:

$2\dfrac {1}{7}$ and

$3\dfrac {1}{7}$

0%
$\dfrac {37}{7}$
0%
$\dfrac {19}{7}$
0%
$\dfrac {37}{14}$
0%
$2$

Explanation

The given fractions are

$2\dfrac {1}{7}$ and

$3\dfrac {1}{7}$

$Mean = \dfrac{\left (2\dfrac {1}{7}+3\dfrac {1}{7}\right )}{2}$

$= \dfrac{\left (\dfrac {15}{7} + \dfrac {22}{7}\right )}{2}$

$= \left (\dfrac {15 + 22}{7}\right ) \times \dfrac {1}{2}$

$= \dfrac {37}{7}\times \dfrac {1}{2}$

$= \dfrac {37}{14}$

Hence, the mean of the given fractions is

$\dfrac {37}{14}$ .

A handkerchief is divided in four squares. Each part is to be embroidered with a flower. How much part has design of flower?

0%
$\dfrac{3}{4}$
0%
$\dfrac{1}{4}$
0%
$\dfrac{1}{2}$
0%
$\dfrac{1}{3}$

Explanation

Total number of divisions in handkerchief

$= 4$

Divisions with embroidery

$= 3$

$\Rightarrow$ Parts with design

$=$ Embroidered divisions

$\div$ Total divisions

$= \dfrac{3}{4}$

What fraction is represented by all of these figures?

0%
$\dfrac{1}{2}$
0%
$\dfrac{1}{3}$
0%
$\dfrac{2}{3}$
0%
$\dfrac{1}{4}$

Explanation

In the given first object, there are a total of

$2$ rectangles and

$1$ rectangle is shaded amongst them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:

$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 2 }$

Now, consider the second object, there are a total of

$4$ squares and

$2$ squares are shaded amongst them. Therefore, the ratio of shaded squares to the total number of squares is:

$\dfrac {Shaded}{Total}=\dfrac {2 }{ 4 }=\dfrac {1}{2}$

Now, in the third object, there are a total of

$6$ rectangles and

$3$ rectangles are shaded amongst them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:

$\dfrac {Shaded}{Total}=\dfrac { 3 }{ 6 }=\dfrac {1}{2}$

Since the fraction of all of the three given objects is same that is

$\dfrac {1}{2}$ .

Hence, the fraction

$\dfrac {1}{2}$ represented by all of the given figures.

What part of the rectangle is coloured?

0%
$\dfrac{4}{16}$
0%
$\dfrac{1}{6}$
0%
$\dfrac{1}{4}$
0%
Both A and C

Write the equivalent fractions represented by the shaded portions of these figures.

0%
$\cfrac { 2 }{ 10 } =\cfrac { 3 }{ 5 }$
0%
$\cfrac { 6 }{ 15 } =\cfrac { 2 }{ 5 }$
0%
$\cfrac { 6 }{ 10 } =\cfrac { 2 }{ 5 }$
0%
$\cfrac { 3 }{ 15 } =\cfrac { 1 }{ 5 }$

Explanation

Given: The shaded portion of the figures

Total boxes in the figure

$1=15$

Shaded boxes in the figure

$1=6$

Equivalent fraction

$=\dfrac{6}{15}$ (figure 1)

Total boxes in the figure

$2=5$

Shaded boxes in the figure

$2=2$

Equivalent fraction

$=\dfrac{2}{5}$ (figure 2)

$\therefore$ option B is correct.

2108050_723117_ans_3ad331b0d19c4d1f93098c6ea2ac1f20.png

What fraction of the figure is shaded?

0%
$\displaystyle\frac{7}{16}$
0%
$\displaystyle\frac{1}{2}$
0%
$\displaystyle\frac{9}{16}$
0%
$\displaystyle\frac{17}{32}$

Explanation

If we rearrange the figure then we can conclude that half of the square is shaded

$\therefore$ The total fraction of figure shaded is

$\dfrac{1}{2}$

Hence the correct answer is option B.

Identify the figure which represent equal parts?

0%
2 and 3
0%
1 and 2
0%
1 and 3
0%
2 and 4

Explanation

In the given first circular object, there are a total of

$4$ parts and

$1$ part is shaded amongst them. Therefore, the ratio of shaded part to the total number of parts is:

$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 4 }$

Now, consider the second circular object, there are a total of

$4$ parts and

$2$ parts are shaded amongst them. Therefore, the ratio of shaded parts to the total number of parts is:

$\dfrac {Shaded}{Total}=\dfrac {2 }{ 4 }=\dfrac {1}{2}$

Now, in the third object, there are a total of

$4$ squares and

$3$ squares are shaded amongst them. Therefore, the ratio of shaded squares to the total number of squares is:

$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 4 }$

Finally, in the last object, there are a total of

$4$ squares and none of the squares are shaded amongst them. Therefore, the ratio of shaded squares to the total number of squares is:

$\dfrac {Shaded}{Total}=\dfrac { 0 }{ 4 }=0$

Since the fraction of all of first and third objects is same that is

$\dfrac {1}{4}$ .

Hence, the figure 1 and 3 represents the equal parts.

Which figure shows greater fraction?

0%
Fig. a shows greater fraction.
0%
Fig. b shows greater fraction.
0%
None
0%
we cannot say.

Explanation

In the given first circular object, there are a total of

$4$ parts and

$1$ part is shaded amongst them. Therefore, the ratio of shaded part to the total number of parts is:

$\dfrac {Shaded}{Total}=\dfrac {1 }{ 4 }$

Now, consider the second circular object, there are a total of

$8$ parts and

$1$ part is shaded amongst them. Therefore, the ratio of shaded part to the total number of parts is:

$\dfrac {Shaded}{Total}=\dfrac {1 }{ 8 }$

Since the fraction

$\dfrac {1}{4}=0.25$ and

$\dfrac {1}{8}=0.125$ , that means the fraction

$\dfrac {1}{4}$ is greater than

$\dfrac {1}{8}$ .

Hence, figure a is greater than figure b.

Is the simplified fraction form:

$6\times \cfrac { 1 }{ 5 }$

$=1\cfrac { 2 }{ 5 }$

0%
True
0%
False

Explanation

We have,

$6\times\dfrac{1}{5}=\cfrac{6}{5}=\cfrac{1\times5+1}{5}=1\cfrac{1}{5}\quad[\because a\cfrac{b}{c}=\cfrac{a\times c+b}{c}]$

So, above statement is false.

Hence,

$\text{B}$ is the correct option.

How many of the shape of the given figure must be shaded so that

$\dfrac {2}{5}$ of the figure is unshaded?

0%
$5$
0%
$10$
0%
$15$
0%
$20$

Explanation

Total number of shapes

$= 25$
Unshaded fraction

$= \dfrac {2}{5}$

$\therefore$ Shaded fraction

$= 1 - \dfrac {2}{5}$

$= \dfrac {3}{5}$

Now, number of shape to be shaded

$= \dfrac {3}{5}\times 25$

$= 15$

Hence, option

$C$ is correct.

State true/false:

For the given ,

$\dfrac{6}{7} \times 2$

the answer as a mixed fraction is

$1\dfrac{5}{7}$

0%
True
0%
False

Explanation

$\dfrac{6}{7} \times 2$

Can be written as

$=\dfrac{12}{7}$

$=1\dfrac{5}{7}$

In which figure does the shaded part represents

$0.3$ ?

What fraction of the figure is shaded.

0%
$\displaystyle\frac{1}{4}$
0%
$\displaystyle\frac{3}{8}$
0%
$\displaystyle\frac{5}{8}$
0%
$\displaystyle\frac{8}{11}$

Explanation

$\Rightarrow$ Total number of equal parts =

$8$

$\Rightarrow$ Number of shaded parts =

$3$

$\therefore$ Shaded fraction =

$\dfrac{Shaded\,\,parts}{Total\,number\,of\,equal\,parts}$

$\therefore$ Shaded fraction =

$\dfrac{3}{8}$

Pictorial representation of

$3\times \displaystyle \frac{2}{3}$ is?

Explanation

We have given Pictorial representation of

$3\times \dfrac{2}{3}$

$\Rightarrow$

$3\times \dfrac{2}{3}=\dfrac{2}{3}+\dfrac{2}{3}+\dfrac{2}{3}$

$\therefore$ Option

$B$ is correct answer.

What is the sum of shaded parts of the given figures?

0%
1 $\dfrac{2}{3}$
0%
1 $\dfrac{1}{4}$
0%
1 $\dfrac{3}{4}$
0%
2 $\dfrac{1}{4}$

Explanation

In figure I,
Total number of equal parts

$=4$
Number of shaded parts

$= 3$
Therefore shaded fraction

$=\dfrac{3}{4}$
In figure II,
Total number of equal parts

$= 16$
Number of shaded parts

$=8$
Therefore shaded fraction

$=\dfrac{8}{16}=\dfrac{1}{2}$

So, required sum

$=\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{3+2}{4}=\dfrac{5}{4}= 1\dfrac{1}{4}$

$\dfrac { 2 }{ 5 }$ of 15 is

0%
4
0%
7
0%
6
0%
9

Explanation

$\dfrac{2}{5}$

$\times 15$ = 6

How many

$\frac{1}{8}$ are there in

$\frac{1}{2}$ ?

0%
3
0%
4
0%
6
0%
8

Represent the answer in fraction

0%
$\dfrac{2}{4}$
0%
$\dfrac{1}{4}$
0%
$\dfrac{1}{2}$
0%
Both A and C

Which of the following options represents

$\displaystyle\frac{3}{4}$ of

$8$ parts shaded?

0%
0%
0%
0%
None of these

Explanation

We know,

$\dfrac{3}{4}\,of\,8=\dfrac{3}{4}\times 8=6$

$\Rightarrow$ So, in option

$B$ has 6 parts shaded out of

$8$

$\therefore$ Correct answer is option

$B$ .

CBSE Questions for Class 5 Maths Parts And Whole Quiz 4 - MCQExams.com

0:0:1

Practice Class 5 Maths Quiz Questions and Answers

CBSE Questions for Class 5 Maths Parts And Whole Quiz 4 - MCQExams.com

0:0:1

Practice Class 5 Maths Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.