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CBSE Questions for Class 5 Maths Ways To Multiply And Divide Quiz 1 - MCQExams.com
CBSE
Class 5 Maths
Ways To Multiply And Divide
Quiz 1
64 $$\div$$ 1 is ______
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0%
1
0%
0
0%
46
0%
64
Explanation
$$64\div 1=\dfrac { 64 }{ 1 } =64$$
So correct answer will be option D
$$34\times 56= ?$$
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0%
$$2394$$
0%
$$1194$$
0%
$$1094$$
0%
$$1904$$
Explanation
$$\ \ \ \ \ \ \ \ 34 \\ \times\ \ \ \ 56 \\ ----$$
$$\ \ \ \ \ \ 204 \\ + 170 \times \\ ----- \\ \ \ \ \ 1904$$
Evaluate: $$234\times 0$$
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0%
$$234$$
0%
$$100$$
0%
$$0$$
0%
$$1$$
Explanation
Any number multiplied by $$0$$ gives $$0$$ itself.
$$\Rightarrow 234\times 0 = 0$$
1 $$\div$$ 28 is _______
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0%
$$28$$
0%
$$1$$
0%
$$0$$
0%
$$\cfrac {1}{28}$$
Explanation
$$1\div 28=\dfrac { 1 }{ 28 } $$
So correct answer will be option D
238 $$\div$$ 238 is ________
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0%
$$0$$
0%
$$238$$
0%
$$28$$
0%
$$1$$
Explanation
The number divided by itself and we get $$1$$ as quotient except $$0$$
This is not valid for $$0$$
Now as per the question
the number $$238$$ is divided by itself
$$238 \div 238 = \dfrac{238}{238} =1$$
So , option $$D$$ is correct
$$102 \times 103$$
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0%
10506
0%
10505
0%
1050
0%
10504
Explanation
$$(100 + 2) \times (100 + 3)$$
[Using $$(x +a) (x+b)=x^2+(a+b)x+ ab$$]
$$ = (100)^2 + (2 + 3) \times 100 + 2 \times 3$$
$$ = 10000 + 5 \times 100 + 6 = 10000 + 500 + 6 = 10506$$
14 apples cost Rs.Then, the cost of 1 apple is___
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0%
$$Rs.\ 10$$
0%
$$Rs.\ 8$$
0%
$$Rs.\ 4$$
0%
$$Rs.\ 14$$
Explanation
Cost of 14 apples $$= 140$$
Cost of 1 apple $$=\dfrac { Cost \ of \ 14 \ apples} { \ No. \ of \ apples}$$
$$=\dfrac {140} {14}$$
$$= 10$$
Find the value of $$4132\times27$$.
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0%
$$111564$$
0%
$$121564$$
0%
$$131564$$
0%
$$1331564$$
Explanation
4 1 3 2
x 2 7
--------------
2 8 9 2 4
8 2 6 4 x
---------------
1 1 1 5 6 4
So the correct answer will be option A
$$(98 + 14) \times 0$$ is _____
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0%
$$114$$
0%
$$112$$
0%
$$0$$
0%
$$0 \times 98 + 14$$
Explanation
Any number multiplied by $$0,$$ becomes $$0$$ as well.
Hence, option $$C$$ is correct.
Divide 57,804 byThen
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0%
$$Q=1256, R=27$$
0%
$$Q=1256, R=26$$
0%
$$Q=1257, R=28$$
0%
$$Q=1256, R=28$$
Explanation
$$46)57804(1256$$
$$\underline {46}$$
$$118$$
$$\underline {92}$$
$$260$$
$$\underline {230}$$
$$304$$
$$\underline {276}$$
$$\underline {28}$$
$$\displaystyle 178\times \quad ....... = 0 $$
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0%
1
0%
178
0%
0
0%
None of these
Explanation
178*0=0
remember
any number multiplied by zero then result is zero..
Farmer Gopal packed an equal number of oranges into each of the $$15$$ baskets.
If each basket contained $$85$$ oranges, how many oranges did he pack ?
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0%
$$1000$$
0%
$$1527$$
0%
$$1275$$
0%
$$1725$$
Explanation
Each basket contained $$85$$ oranges
Therefore, the number of oranges in $$15$$ baskets
$$=15\times 85$$
$$=1275$$
$$12\times 4356= ?$$
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0%
$$52,272$$
0%
$$52,256$$
0%
$$52,562$$
0%
$$52,632$$
Explanation
By law of commutation,
$$12 \times 4356 = 4356 \times 12$$
By calculation,
$$\ \ \ \ \ \ \ \ 4356 \\ \times\ \ \ \ \ \ \ 12 \\ ----$$
$$\ \ \ \ \ \ 8712 \\ + 43560 \\ ----- \\ \ \ \ \ 52272$$
Evaluate: $$625\div 5=$$
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0%
$$125$$
0%
$$25$$
0%
$$234$$
0%
$$35$$
Explanation
The natural number $$625$$ can be divided by another natural number $$5$$ as follows:
$$625\div 5=\dfrac { 625 }{ 5 } =125$$
Hence, $$625\div 5=125$$
If a cellphone costs Rs.$$999$$. What is the cost of $$12$$ such cellphones?
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0%
Rs.$$26,356$$
0%
Rs.$$56,235$$
0%
Rs.$$13,568$$
0%
Rs.$$11,988$$
Explanation
By unitary method,
$$1$$ cellphone $$=$$ Rs. $$999$$
$$12$$ cellphones $$=$$ Rs. $$999\times 12 =$$ Rs.$$11,988$$
Divide : $$84497\div 7$$.
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0%
$$7$$
0%
$$12071$$
0%
$$84497$$
0%
$$12061$$
Repeated addition of same number is called _________.
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0%
Addition
0%
Subtraction
0%
Multiplication
0%
Division
Explanation
If the same number is repeated then in short we can write that in the form of multiplication.
For example : $$3+3+3+3+3$$
Here $$3$$ is repeated $$5$$ times so, in short, we can write this addition as $$3\times 5$$
$$\therefore$$ Repeated addition is also known as multiplication.
If a child's $$weight = 35 kg$$, then weight of $$12$$ similar children is?
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0%
$$350 kg$$
0%
$$340kg$$
0%
$$420kg$$
0%
$$400kg$$
Explanation
Weight of 12 Children = No. of children $$\times$$ weight of one child
= 12 $$\times$$ 35 kg
= 420 kg
Multiply : $$44\times 567\times 1$$
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0%
$$44$$
0%
$$567$$
0%
$$24948$$
0%
$$1$$
Explanation
We know that any number multiplied by $$1$$ will always result in that number itself. Therefore, we only multiply $$44$$ and $$567$$ as follows:
$$44\times 567=24948$$
Hence,
$$44\times 567\times 1=24948$$
Simplified value of $$769\times 43$$ is
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0%
$$33,058$$
0%
$$23,067$$
0%
$$33,067$$
0%
$$33,207$$
Explanation
By calculations,
$$\ \ \ \ \ \ \ \ 769 \\ \times\ \ \ \ \ \ 43 \\ ----$$
$$\ \ \ \ \ \ 2307 \\ +30760 \\ ----- \\ \ \ \ \ 33067$$
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