MCQ Questions for Class 5 Maths Ways To Multiply And Divide Quiz 1

$\div$ 1 is ______

0%
1
0%
0
0%
46
0%
64

Explanation

$64\div 1=\dfrac { 64 }{ 1 } =64$

So correct answer will be option D

$34\times 56= ?$

0%
$2394$
0%
$1194$
0%
$1094$
0%
$1904$

Explanation

$\ \ \ \ \ \ \ \ 34 \\ \times\ \ \ \ 56 \\ ----$

$\ \ \ \ \ \ 204 \\ + 170 \times \\ ----- \\ \ \ \ \ 1904$

Evaluate:

$234\times 0$

0%
$234$
0%
$100$
0%
$0$
0%
$1$

Explanation

Any number multiplied by

$0$ gives

$0$ itself.

$\Rightarrow 234\times 0 = 0$

$\div$ 28 is _______

0%
$28$
0%
$1$
0%
$0$
0%
$\cfrac {1}{28}$

Explanation

$1\div 28=\dfrac { 1 }{ 28 }$

So correct answer will be option D

238

$\div$ 238 is ________

0%
$0$
0%
$238$
0%
$28$
0%
$1$

Explanation

The number divided by itself and we get

$1$ as quotient except

$0$

This is not valid for

$0$

Now as per the question

the number

$238$ is divided by itself

$238 \div 238 = \dfrac{238}{238} =1$

So , option

$D$ is correct

$102 \times 103$

0%
10506
0%
10505
0%
1050
0%
10504

Explanation

$(100 + 2) \times (100 + 3)$
[Using

$(x +a) (x+b)=x^2+(a+b)x+ ab$ ]

$= (100)^2 + (2 + 3) \times 100 + 2 \times 3$

$= 10000 + 5 \times 100 + 6 = 10000 + 500 + 6 = 10506$

14 apples cost Rs.Then, the cost of 1 apple is___

0%
$Rs.\ 10$
0%
$Rs.\ 8$
0%
$Rs.\ 4$
0%
$Rs.\ 14$

Explanation

Cost of 14 apples

$= 140$

Cost of 1 apple

$=\dfrac { Cost \ of \ 14 \ apples} { \ No. \ of \ apples}$

$=\dfrac {140} {14}$

$= 10$

Find the value of

$4132\times27$ .

0%
$111564$
0%
$121564$
0%
$131564$
0%
$1331564$

$(98 + 14) \times 0$ is _____

0%
$114$
0%
$112$
0%
$0$
0%
$0 \times 98 + 14$

Explanation

Any number multiplied by

$0,$ becomes

$0$ as well.

Hence, option

$C$ is correct.

Divide 57,804 byThen

0%
$Q=1256, R=27$
0%
$Q=1256, R=26$
0%
$Q=1257, R=28$
0%
$Q=1256, R=28$

Explanation

$46)57804(1256$

$\underline {46}$

$118$

$\underline {92}$

$260$

$\underline {230}$

$304$

$\underline {276}$

$\underline {28}$

$\displaystyle 178\times \quad ....... = 0$

0%
1
0%
178
0%
0
0%
None of these

Farmer Gopal packed an equal number of oranges into each of the

$15$ baskets. If each basket contained

$85$ oranges, how many oranges did he pack ?

0%
$1000$
0%
$1527$
0%
$1275$
0%
$1725$

Explanation

Each basket contained

$85$ oranges

Therefore, the number of oranges in

$15$ baskets

$=15\times 85$

$=1275$

$12\times 4356= ?$

0%
$52,272$
0%
$52,256$
0%
$52,562$
0%
$52,632$

Explanation

By law of commutation,

$12 \times 4356 = 4356 \times 12$

By calculation,

$\ \ \ \ \ \ \ \ 4356 \\ \times\ \ \ \ \ \ \ 12 \\ ----$

$\ \ \ \ \ \ 8712 \\ + 43560 \\ ----- \\ \ \ \ \ 52272$

Evaluate:

$625\div 5=$

0%
$125$
0%
$25$
0%
$234$
0%
$35$

Explanation

The natural number

$625$ can be divided by another natural number

$5$ as follows:

$625\div 5=\dfrac { 625 }{ 5 } =125$

Hence,

$625\div 5=125$

If a cellphone costs Rs.

$999$ . What is the cost of

$12$ such cellphones?

0%
Rs. $26,356$
0%
Rs. $56,235$
0%
Rs. $13,568$
0%
Rs. $11,988$

Explanation

By unitary method,

$1$ cellphone

$=$ Rs.

$999$

$12$ cellphones

$=$ Rs.

$999\times 12 =$ Rs.

$11,988$

Divide :

$84497\div 7$ .

0%
$7$
0%
$12071$
0%
$84497$
0%
$12061$

Repeated addition of same number is called _________.

0%
Addition
0%
Subtraction
0%
Multiplication
0%
Division

Explanation

If the same number is repeated then in short we can write that in the form of multiplication.

For example :

$3+3+3+3+3$

Here

$3$ is repeated

$5$ times so, in short, we can write this addition as

$3\times 5$

$\therefore$ Repeated addition is also known as multiplication.

If a child's

$weight = 35 kg$ , then weight of

$12$ similar children is?

0%
$350 kg$
0%
$340kg$
0%
$420kg$
0%
$400kg$

Explanation

Weight of 12 Children = No. of children

$\times$ weight of one child

= 12

$\times$ 35 kg

= 420 kg

Multiply :

$44\times 567\times 1$

0%
$44$
0%
$567$
0%
$24948$
0%
$1$

Explanation

We know that any number multiplied by

$1$ will always result in that number itself. Therefore, we only multiply

$44$ and

$567$ as follows:

$44\times 567=24948$

Hence,

$44\times 567\times 1=24948$

Simplified value of

$769\times 43$ is

0%
$33,058$
0%
$23,067$
0%
$33,067$
0%
$33,207$

Explanation

By calculations,

$\ \ \ \ \ \ \ \ 769 \\ \times\ \ \ \ \ \ 43 \\ ----$

$\ \ \ \ \ \ 2307 \\ +30760 \\ ----- \\ \ \ \ \ 33067$

CBSE Questions for Class 5 Maths Ways To Multiply And Divide Quiz 1 - MCQExams.com

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Practice Class 5 Maths Quiz Questions and Answers

CBSE Questions for Class 5 Maths Ways To Multiply And Divide Quiz 1 - MCQExams.com

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Practice Class 5 Maths Quiz Questions and Answers

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