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CBSE Questions for Class 9 Chemistry Atoms And Molecules Quiz 13 - MCQExams.com

The ratio of molecular mass to empirical formula weight in case of glucose is :

Explanation

Molecular mass of glucose (

$C_6H_{12}O_6) = (6\times 12) + (12\times 1) + (6\times 16) =180\ g$

Empirical formula of glucose will be

$CH_2O$ .

So, empirical formula weight of glucose is,

$12 + 2\times 1 + 16 = 30 g$

$\therefore$ Ratio of molecular mass to empirical formula weight is,

$\dfrac{180 g}{30g}$

$= 6$

Hence, option

$C$ is correct.

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