CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 1 - MCQExams.com

Let the required point be $$P$$.

Given, the point lies on $$y$$-axis.

Then, its abscissa is $$0$$ or $$x = 0$$.

Also, given the point is at a distance of $$2$$ units in the negative direction of $$y$$-axis,

So, its ordinate will be $$-2$$.
Hence, the co-ordinates of the required point are $$(0,-2)$$. 

Therefore, option $$C$$ is correct.

We know, in the $$xy$$ - plane, any point on the $$x$$ - axis will have its ordinate equal to zero.

Hence, any point on the $$x$$ - axis will be of the form $$(x,0)$$, where $$x$$ can be any number. 

Here, the point $$(6,0)$$ is of the form $$(x,0)$$.

The required point is $$Q$$.

Here, the point lies on $$y$$-axis.

Then, its abscissa is $$0$$ or $$x = 0$$.

Also, the point is at a distance of $$3$$ units above the $$x$$-axis

So, its ordinate will be $$+3$$.

Hence, the co-ordinates of the required point are $$Q(0,3)$$.

The required point is $$R$$.

Here, the point lies on the $$II$$nd quadrant.

The point is at a distance of $$2$$ units left of the $$y$$-axis.

So, its abscissa will be $$-2$$.

Also, the point is at a distance of $$1$$ unit above the $$x$$-axis.

So, its ordinate will be $$1$$.
Hence, the co-ordinates of the required point are $$R(-2,1)$$.

The point $$S$$ lies on the $$III^{rd}$$ quadrant.

The point is at a distance of $$3$$ units left of the $$y-$$axis.

So, its abscissa will be $$-3$$.

Also, the point is at a distance of $$2$$ unit below the $$x-$$axis.

So, its ordinate will be $$-2$$.

Hence, the co-ordinates of the required point are $$S(-3,-2)$$.

Consider point is $$P$$.

Here, the ordinate is $$0$$ or $$y = 0$$.

Also, the point is at a distance of $$2$$ units right of the $$y$$-axis.

So, its abscissa will be $$+2$$.

Therefore, the point lies on the $$x$$-axis.

Hence, the co-ordinates of the required point are $$P(2,0)$$.

Consider point is $$Q$$.

Here, the abscissa is $$0$$ or $$x = 0$$.

Also, the point is at a distance of $$3$$ units above the $$x$$-axis

So, its ordinate will be $$+3$$.

Therefore, the point lies on the $$y$$-axis.

Hence, the co-ordinates of the required point are $$Q(0,3)$$.

Consider point is $$R$$.

Here, the point is at a distance of $$2$$ units left of the $$y$$-axis.

So, its abscissa will be $$-2$$.

Also, the point is at a distance of $$1$$ unit above the $$x$$-axis.

So, its ordinate will be $$1$$.

Therefore, the point lies on the $$II$$nd quadrant.

Hence, the co-ordinates of the required point are $$R(-2,1)$$.

Consider point is $$S$$.

Here, the point is at a distance of $$3$$ units left of the $$y$$-axis.

So, its abscissa will be $$-3$$.

Also, the point is at a distance of $$2$$ unit below the $$x$$-axis.

So, its ordinate will be $$-2$$.

Therefore, the point lies on the $$III$$rd quadrant.

Hence, the co-ordinates of the required point are $$S(-3,-2)$$.

Therefore, the only point that lies on the $$y$$-axis is $$Q(0,3)$$.

Hence, option $$B$$ is correct.