MCQ Questions for Class 9 Maths Coordinate Geometry Quiz 1

Which of the following points lies in

$III$ quadrant?

0%
$(1, 3)$
0%
$(-1, 3)$
0%
$(+1, -3)$
0%
$(-1, -3)$

Explanation

In the

$III$ quadrant, both abscissa and ordinate are negative.

So, option

$D$ is correct

The point which lies on

$y$ -axis and at a distance of

$2$ units in negative direction of

$y$ -axis is _____

0%
$(0, 0)$
0%
$(0, 2)$
0%
$(0, -2)$
0%
$(-2, 0)$

Explanation

Let the required point be $P$ .

Given, the point lies on $y$ -axis.

Then, its abscissa is $0$ or $x = 0$ .

Also, given the point is at a distance of $2$ units in the negative direction of $y$ -axis,

So, its ordinate will be $-2$ .
Hence, the co-ordinates of the required point are $(0,-2)$ .

Therefore, option $C$ is correct.

The sign of abscissa and ordinate of point in

$II$ quadrant is

0%
$(+, +)$
0%
$(-, -)$
0%
$(+, -)$
0%
$(-, +)$

Explanation

$II$ quadrant, abscissa is

$-$ ve but ordinate is positive.

So, option

$D$ is correct.

In the graph, which point represents co-ordinates

$(-2, 0)$ .

0%
$P$
0%
$Q$
0%
$R$
0%
$S$

Explanation

Distance from

$y$ -axis

$= 0$ (i.e. the point lies on the

$x$ -axis)
Distance from

$x$ -axis

$= -2$ , being negative lies in the negative

$x$ -axis.

Therefore,

$R$ is the required point.

Hence, option

$C$ is correct.

Which of the following points lie on

$x$ -axis?

0%
$(1, 3)$
0%
$(0, 6)$
0%
$(-2, -3)$
0%
$(6, 0)$

Explanation

We know, in the $xy$ - plane, any point on the $x$ - axis will have its ordinate equal to zero.

Hence, any point on the $x$ - axis will be of the form $(x,0)$ , where $x$ can be any number.

Here, the point $(6,0)$ is of the form $(x,0)$ .

Therefore, option

$D$ is correct.

In which quadrant will point

$(2, -1)$ lie?

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

For the given point Abscissa 2 is positive, but ordinate -1 is negative. So, it will lie in

$IV$ quadrant.

So, option

$D$ is correct.

If the perpendicular distance of a point

$P$ in a plane from

$x$ -axis is

$2$ units and from

$y$ -axis is

$7$ units, then its abscissa is:

0%
$0$
0%
$2$
0%
$7$
0%
None of the above

Explanation

We know, in the

$xy$ -plane, any point is of the form

$(x,y)$ , where

$x,y$ can be any non-zero number.

Here, the

$x$ -coordinate or the abscissa is the perpendicular distance of the point from the

$y$ -axis.

Also, the

$y$ -coordinate or the ordinate is the perpendicular distance of the point from the

$x$ -axis.

Here, the perpendicular distance of the point from

$x$ -axis is

$2$ units and from

$y$ -axis is

$7$ units.

Hence, the abscissa is

$7$ .

Therefore, option

$C$ is correct.

What are the coordinates of

$Q$ ?

0%
$(0,3)$
0%
$(3,0)$
0%
$(-3,0)$
0%
$(0,-3)$

Explanation

The required point is $Q$ .

Here, the point lies on $y$ -axis.

Then, its abscissa is $0$ or $x = 0$ .

Also, the point is at a distance of $3$ units above the $x$ -axis

So, its ordinate will be $+3$ .

Hence, the co-ordinates of the required point are $Q(0,3)$ .

Therefore, option

$A$ is correct.

What are the coordinates of

$R$ ?

0%
$(1,2)$
0%
$(-1,2)$
0%
$(1,-2)$
0%
$(-2, 1)$

Explanation

The required point is $R$ .

Here, the point lies on the $II$ nd quadrant.

The point is at a distance of $2$ units left of the $y$ -axis.

So, its abscissa will be $-2$ .

Also, the point is at a distance of $1$ unit above the $x$ -axis.

So, its ordinate will be $1$ .
Hence, the co-ordinates of the required point are $R(-2,1)$ .

Therefore, option

$D$ is correct.

What are the coordinates of

$S$ ?

0%
$(3,2)$
0%
$(3,-2)$
0%
$(-2,3)$
0%
$(-3,-2)$

Explanation

The point $S$ lies on the $III^{rd}$ quadrant.

The point is at a distance of $3$ units left of the $y-$ axis.

So, its abscissa will be $-3$ .

Also, the point is at a distance of $2$ unit below the $x-$ axis.

So, its ordinate will be $-2$ .

Hence, the co-ordinates of the required point are $S(-3,-2)$ .

The coordinates of a point, if its distance from

$x$ -axis is

$10$ and from negative

$y$ -axis is

$2$ are:

0%
$(10, 2)$
0%
$(10, -2)$
0%
$(-2, 10)$
0%
$(2, 10)$

Explanation

Here,

Abscissa

$= 2$

$(\because$ Distance from

$y$ -axis).
Ordinate

$= 10$

$(\because$ Distance from

$x$ -axis).

Therefore, the coordinates of the required point are

$(2,-10)$ , which is shown in the figure.

Hence, option

$D$ is correct.

Which of the following point lies on

$Y$ -axis?

0%
$P$
0%
$Q$
0%
$R$
0%
$S$

Explanation

Consider point is $P$ .

Here, the ordinate is $0$ or $y = 0$ .

Also, the point is at a distance of $2$ units right of the $y$ -axis.

So, its abscissa will be $+2$ .

Therefore, the point lies on the $x$ -axis.

Hence, the co-ordinates of the required point are $P(2,0)$ .

Consider point is $Q$ .

Here, the abscissa is $0$ or $x = 0$ .

Also, the point is at a distance of $3$ units above the $x$ -axis

So, its ordinate will be $+3$ .

Therefore, the point lies on the $y$ -axis.

Hence, the co-ordinates of the required point are $Q(0,3)$ .

Consider point is $R$ .

Here, the point is at a distance of $2$ units left of the $y$ -axis.

So, its abscissa will be $-2$ .

Also, the point is at a distance of $1$ unit above the $x$ -axis.

So, its ordinate will be $1$ .

Therefore, the point lies on the $II$ nd quadrant.

Hence, the co-ordinates of the required point are $R(-2,1)$ .

Consider point is $S$ .

Here, the point is at a distance of $3$ units left of the $y$ -axis.

So, its abscissa will be $-3$ .

Also, the point is at a distance of $2$ unit below the $x$ -axis.

So, its ordinate will be $-2$ .

Therefore, the point lies on the $III$ rd quadrant.

Hence, the co-ordinates of the required point are $S(-3,-2)$ .

Therefore, the only point that lies on the $y$ -axis is $Q(0,3)$ .

Hence, option $B$ is correct.

The abscissa of all the points on the

$x$ -axis is:

0%
$0$
0%
$1$
0%
$2$
0%
Any number

Explanation

The coordinate of any point in the

$x$ -axis is

$(x,0)$ , where

$x$ can take any value.

So, abscissa of any point on the

$x$ -axis is any number.

Hence, we can say that, abscissa of all the points on the

$x$ -axis is any number because

$x$ - axis is a number line which contains infinite real numbers on it.

Therefore,

$\left(D\right)$ is correct.

Points

$(1, 1), (2, 2), (4, 5), ( 3, 4)$ lie

0%
In $II$ quadrant
0%
In $III$ quadrant
0%
In $IV$ quadrant
0%
In $I$ quadrant.

Explanation

Given points are

$(1,1),(2,2),(4,5),(3,4)$

Both the coordinates of given points are positive.

If both the coordinates are positive, then the points lie in

$\text{I}$ quadrant.

Thus, the given points lie in

$\text{I}$ quadrant.

Hence, option D is correct.

The points

$(5, 2)$ and

$(2, 5)$ lie in the

0%
Same quadrant
0%
$II$ and $III$ quadrants respectively
0%
$II$ and $IV$ quadrants respectively
0%
$IV$ and $II$ quadrants respectively

Explanation

The points are

$(5,2)$ and

$(2,5)$ .

The signs of the abscissae are same (positive) and the signs of the ordinates are same (positive).

Therefore, they both lie in the first quadrant (same quadrant).

$y$ coordinate of a point is zero, then this point always lies:

0%
In $I$ quadrant
0%
In $II$ quadrant
0%
On $x$ -axis
0%
On $y$ -axis

Explanation

Given, the

$y$ -coordinate is zero.

$\therefore$ the abscissa can be any number

$x$ and the ordinate is

$0$ .

Then, the point is

$(x,0)$ , when

$x$ may take any value, i.e.

$x$ may take positive or negative value.

$\therefore$ the point

$(x,0)$ lies on the

$x$ axis.

Therefore, option

$C$ is correct.

State whether the given statement is True or False:

A point lies on

$y-$ axis at a distance of

$2$ units from the

$x$ -axis. Its coordinates are

$(2, 0).$

0%
True
0%
False

Explanation

Any point on the

$y$ -axis and at a distance

$a$ from

$x$ -axis, will have the co-ordinates

$P(0,a),$

i.e.

$y$ may take any value

$a$ , but

$x$ remains

$0$ .

Here,

$a=2$ units.

Then, the required point is

$(0,2)$ .

Here, given the point is

$(2,0)$ .

Therefore, the statement is false.

Hence, option

$B$ is correct.

State whether the following statement is True or False.

$(1, 7)$ is a point in the II quadrant.

0%
True
0%
False

Explanation

In the

${ II }^{ nd }$ quadrant the sign of the abscissa of a point

$P$ is

$-$ the sign of the ordinate is

$+.$ So the point is represented by

$P(-x,+y).$ But the given point is

$P(+1,+7).$

Hence, the given statement is false.

The point at which the two coordinate axes meet is called the

0%
Abscissa
0%
Ordinate
0%
Origin
0%
Quadrant

Explanation

The point at which the coordinate axes meet is called the origin. The point is denoted by

$O$ in the above image.

Write the abscissa and ordinate of the point

$(5, 0)$

0%
Abscissa: $5$
Ordinate: $0$
0%
Abscissa: $0$
Ordinate: $5$
0%
Abscissa: $0$
Ordinate: $0$
0%
None of these

Explanation

The given point is

$(5,0)$

The abscissa (x-coordinate) of the given point is

$5$

The ordinate (y-coordinate) of the given point is

$0$

The point

$( 10, 0)$ lies:

0%
To the positive direction and on the $x$ -axis
0%
On the negative direction of the $y$ -axis
0%
In the third quadrant
0%
In the fourth quadrant

Explanation

The coordinates of the given point are

$(10,0)$ , i.e. the ordinate is

$0$ .

We know, the coordinates of a point in the form

$(x,0)$ lies in the

$x$ -axis.

$\therefore (10,0)$ lie on the $x$ -axis.

Here, the abscissa is $10$ , and is positive.

$\therefore$ $(10,0)$ lies on the positive direction of the $x$ -axis.

Therefore, option $A$ is correct.

A point both of whose coordinates are negative will lie in

0%
$I$ quadrant
0%
$II$ quadrant
0%
$III$ quadrant
0%
$IV$ quadrant

Explanation

In the third quadrant the

$(x,y)$ co-ordinates are negative,

So, the given point will lie in the third quadrant.

Ordinate of all points on the

$x$ -axis is:

0%
$0$
0%
$1$
0%
$-1$
0%
Any number

Explanation

We know, the coordinates of

$x$ -axis is

$(x,0)$ .

Then, the coordinates of any point on the

$x$ -axis is

$(x,0)$ ,

where the abscissa is

$x$ and the ordinate is

$0$ .

Therefore, the ordinate of any point on the

$x$ -axis is

$0$ .

Hence, option

$A$ is correct.

In which quadrant the point

$(2,-3)$ will lie?

0%
First
0%
Second
0%
Third
0%
Fourth

Explanation

Given point is

$(2,-3)$

Since

$x-$ coordinate is positive and

$y-$ coordinate is negative, the given point will lie in the fourth quadrant.

Hence, option D is correct.

Without plotting the point, indicate the quadrant in which the given point will lies whose ordinate is

$-5$ and abscissa is

$3$ ?

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

Given: The abscissa is

$+3$ & ordinate is

$-5$

We know that in

$I^{st}$ quadrant, both the abscissa and ordinate are positive.

$II^{nd}$ quadrant, the abscissa is negative and the ordinate is positive.

$III^{rd}$ quadrant, the abscissa is negative and the ordinate is negative.

$IV^{th}$ quadrant, the abscissa is positive and the ordinate is negative.

$\\ \therefore$ The point lies in the

$IV^{th}$ quadrant.

Without plotting the points indicate the quadrant in which the point will lie, if abscissa is

$-5$ and ordinate is

$-3$ ?

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

$\text{I}$ quadrant, abscissa and ordinates are positive.

$\text{II}$ quadrant, abscissa is negative and ordinate is positive.

$\text{III}$ quadrant, both abscissa and ordinate are negative.

$\text{IV}$ quadrant, abscissa is positive and ordinate is negative.

Here, the given abscissa is

$-5$ and ordinate is

$-3$ . Both are negative.

Thus, they lie in

$\text{III}$ quadrant.

Hence, option

$C$ is correct.

Write the name of the quadrant in which the point

$( - 3, 5)$ lies.

0%
First quadrant
0%
Second quadrant
0%
Third quadrant
0%
Fourth quadrant

Explanation

The point

$(-3,5)$ lies at second quadrant

Without plotting the point indicate the quadrant in which the point will lie, if ordinate is

$5$ and abscissa is

$3$ ?

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

Given ordinate or

$y$ -coordinate

$= 5$

and abscissa or

$x$ -coordinate

$=3$

$\therefore$

$(x ,y)$ =

$(3,5)$

Since, both the coordinates are positive

The point will lie in

$Quadrant-I$

In which quadrant does

$(-1,-1)$ lie?

0%
First
0%
Second
0%
Third
0%
Fourth

The coordinates of a point whose abscissa is

$5$ and which lies on the

$x$ -axis is:

0%
$(5,0)$
0%
$(0,5)$
0%
$(0,0)$
0%
$(5,5)$

Explanation

Let the required point be

$P$ .

Given, the point lies on the

$x$ -axis.

$\therefore$ The ordinate of

$P$ is

$0$ .

Also, its abscissa is

$5$ .

$\therefore$ The co-ordinates of point

$P$ are

$P(5,0)$ .

Hence, option

$A$ is correct.

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 1 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 1 - MCQExams.com

0:0:1

Practice Class 9 Maths Quiz Questions and Answers

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