MCQ Questions for Class 9 Maths Coordinate Geometry Quiz 8

The point whose ordinate is

$4$ and which lies on y - axis is

0%
$\left(4,0\right)$
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$\left(0,4\right)$
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$\left(1,4\right)$
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$\left(4,2\right)$

Explanation

${\textbf{Step - 1 : Apply properties of y axis}}{\text{.}}$

${\text{We know that any point, suppose }}\left( {{x,y}} \right){\text{ on Y axis will have }x = 0}{\text{. }}$

${\text{hence, any point on Y axis will be in the form of }}\left( {0,{y}} \right).$

${\textbf{Step - 2 : Determine the point}}{\text{.}}$

${\text{So given that the ordinate is 4}}{\text{.}}$

${\text{To be on Y axis it must be of form }}\left( {0,{y}} \right).$

${\text{So simply the point will be }}\left( {0,4} \right)$

${\textbf{Hence, the point with ordinate 4 and on Y axis is }} \mathbf{ \left({0,4} \right).}$

State whether the following statement is true or false? Justify your answer.
Point

$\left(3,0\right)$ lies in the first quadrant.

0%
True
0%
False

Explanation

The given point is

$(3,0)$ .

To find out: Whether the point lies in the first quadrant or not.

We know that, the

$x-coordinate$ of a point is the perpendicular distance of the point from

$y-axis$ and the

$y-coordinate$ is the perpendicular distance from the

$x-axis$ .

The

$y-coordinate$ of

$(3,0)$ is

$0$ , which means it is at

$0$ distance from the

$x-axis$ .

Hence, the point lies on the

$x-axis$ and not the first quadrant.

Therefore, the given statement is false.

Fill in the blank using correct alternative.
Out of the following, point ......... lies to the right of the origin on X- axis.

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(-2,0)
0%
(0,2)
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(2,3)
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(2,0)

Which among the points P

$(-1 ,1) , Q ( 3, -4) , R ( 1, -1), S ( -2 , -3), T ( 4,4)$ lie in the fourth quadrant ?

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P and T
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Q and R
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only S
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P and R

Choose the correct alternative answer for the following question .
In which quadrant does the point

$( - 4 , - 3 )$ lie ?

0%
First
0%
second
0%
third
0%
fourth

Explanation

The x co - ordinate of

$( -4 , -3 )$ is negative and its y co - ordinate is negative . Therefore , the point

$( -4 , - 3 )$ lies in the third quadrant .

Choose the correct alternative answer for the following question .
What is the form of co - ordinate of a point on the

$X$ - axis ?

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$( b , b )$
0%
$(o , b)$
0%
$(a ,o)$
0%
$(a ,a)$

Explanation

The y co - ordinate of every point on the

$X$ - axis is

$0$ . Thus , the co - ordinates of a point on the

$X$ - axis is

$( a , o )$

In a rectangular coordinates system, the coordinates axes are chosen such that they form pair of perpendicular lines.

0%
True
0%
False

The point

$( -3 , -4)$ lies in the quadrant .

0%
I
0%
II
0%
III
0%
IV

Explanation

Given:

$x=-3$ and

$y=-4$

$\implies$ Both the abscissa and ordinate are negative. So, it will lie in III quadrant.

1834232_1867709_ans_d3f58363f61c4720bcf57a4113bb3938.png

What is the quadrilateral that is formed by joining the points (1, 1); (2, 4); (8, 4) and (10, 1)?

0%
A triangle
0%
A square
0%
A rectangle
0%
A trapezium

Explanation

Given : quadrilateral vertices are (1,1), (2,4), (8,4) and (10,1).

To find : Draw quadrilateral and find type of Quadrilateral

Solution:

quadrilateral whose vertices are (1,1), (2,4), (8,4) and (10,1).

Given Quadrilateral is a trapezium

Slope of line between (2,4) (8,4) & Length = 6

= (4 - 4)/(8 - 2)

= 0/6

= 0

Slope of line between (10,1). & (1,1), & Length = 9

= ( 1 - 1)/(10 - 1)

= 0/9

= 0

Length of line line joining

$\{(2,4), \ (8,4) \}=(8-2)=6$
Length of line line joining

$\{(1,1), \ (10,1) \}=(10-1)=9$

Hence Two unequal Sides are parallel ,

Quadrilateral is a trapezium

In the graph below, no axes or origin is shown. If point B's coordinates are (10,3), which of the following coordinates would most likely be A's?

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(17, -2)
0%
(10, 6)
0%
(6, 8)
0%
(-10, 3)
0%
(-2, -17)

What are the coordinates of point A on the following graph?

0%
(-3, -4)
0%
(-4, 3)
0%
(3, -4)
0%
(-4, -3)
0%
(3, 4)

Explanation

Clearly, from the following graph, it can be induced that:

$3$ lies on x axis, and

$-4$ on y- axis.

Hence, coordinates of A are

$(3, -4)$ , option C.

2106105_537586_ans_aa18c2109ac342829155ead568d3584e.png

The coordinates of the point of intersection of tangents drawn to

$y^{2}=4 a x$ at the points where it is cut by the line

$x \cos \alpha+y \sin \alpha-p=0$ is

0%
$(p \tan \alpha, 2 \operatorname{asec} \alpha)$
0%
$(-p \sec \alpha,-2 a \tan \alpha)$
0%
$(2 a \sec \alpha, p \tan \alpha)$
0%
$(p \sec \alpha, 2 a \tan \alpha)$

If the lines x + y =

$\left | a \right |$ and ax y = 1 intersected in the first quadrant , then

$a$

$\in$ (

$a_0$ ,

$\infty$ ) where

$a_0$ =

0%
0
0%
1
0%
1
0%
2

Write the names of quadrant in which the following co-ordinates point lies, where

$x$ and

$y$ are natural numbers

$(-x, y)$
$(x, y)$
$(-x, -y)$

0%
Second, First and Third quadrant respectively
0%
First, Second and Third quadrant respectively
0%
Third, First and Second quadrant respectively
0%
Third, Second and First quadrant respectively

The point

$(3, -4)$ lies in the quadrant:

0%
first
0%
second
0%
third
0%
fourth

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 8 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 8 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

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