Explanation
We know, two angles are complementary when their sum is equal to $$90^o.$$
Given, measure of one angle is $$63^o.$$
$$\Rightarrow$$ Measure of its complementary angle $$=90^o-63^o$$ $$=27^o.$$
$$\therefore$$ Measure of complementary angle of $$ 63^{o}=27^o$$.
Option $$A$$ is correct.
We know, two angles are complementary when they add up to $$90^o.$$
Given, measure of one complementary angle is $$72\dfrac{1}{2}^o=\dfrac{145}{2}^o.$$
$$\Rightarrow$$ Measure of other complementary angle $$=90^o-\dfrac{145}{2}^o$$ $$=\dfrac{35}{2}^o=17\dfrac{1}{2}^o.$$
$$\therefore$$ Measure of a complementary angle of $$72\dfrac{1}{2}^o=$$ $$17\dfrac{1}{2}^o.$$
Therefore, option $$D$$ is correct.
Given, measure of one complementary angle is $$68^o.$$
$$\Rightarrow$$ Measure of other complementary angle $$=90^o-68^o$$ $$=22^o.$$
$$\therefore$$ Measure of a complementary angle of $$ 68^{o}=22^o$$.
Also given, measure of one complementary angle is $$33^o.$$
$$\Rightarrow$$ Measure of other complementary angle $$=90^o-33^o$$ $$=57^o.$$
$$\therefore$$ Measure of a complementary angle of $$ 33^{o}=57^o$$.
Hence, option $$A$$ is correct.
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