MCQ Questions for Class 9 Maths Statistics Quiz 1

If x is the average(arithmetic mean) of

5

$5$ consecutive odd integers, what is the median of integers?

0%
$0$
0%
$1$
0%
$x-2$
0%
x

If x and y are both prime numbers such that x < y < 50 , then the maximum possible range of the data 4,6,8, x,y,16 is

0%
44
0%
45
0%
48
0%
47

Upper limit of class interval

75 - 85

$75 - 85$ is:

0%
$10$
0%
$-10$
0%
$75$
0%
$85$

Which two class has same frequency ?

0%
$0-10$ & $10-20$
0%
$10-20$ & $40-50$
0%
both
0%
none of this

Which class has lowest frequency ?

0%
$0-10$
0%
$10-20$
0%
$20-30$
0%
$30-40$

Explanation

Class

0−100−10 has lowest frequency i.e.

1

$1$ .

The difference between upper and lower limit is called

0%
group
0%
class marks
0%
class size
0%
class internal

The class mark of

95 - 100

$95-100$ is

0%
$100$
0%
$97.5$
0%
$95$
0%
$95.5$

Explanation

Class mark of a given interval is given by the following formula:

Class-mark

= \frac{L o w e r c l a s s + U p p e r c l a s s}{2}

$=\dfrac{\mathrm{Lower class}+\mathrm{Upper class}}{2}$

= \frac{(95 + 100)}{2} = 97.5

$=\dfrac{(95+100)}{2} = 97.5$

In the class interval

30 - 40

$30-40$ ,

30

$30$ is

0%
Frequency
0%
Range
0%
Upper limit
0%
Lower limit

Explanation

30

$30$ -lower limit,

40

$40$ -upper limit

Data available in unorganized form is called

0%
out comes
0%
raw data
0%
class
0%
frequency

Size of the class

180 - 195

$180 - 195$ is

0%
$180$
0%
$195$
0%
$15$
0%
$-15$

Explanation

Size of class

= 195 - 180 = 15

$= 195 - 180 = 15$

In the class interval

35 - 46

$35-46$ , the lower limit is _____

0%
$35$
0%
$38$
0%
$40$
0%
$43$

Explanation

For the class interval,

35 - 46

$35 - 46$
Lower limit

= 35

$= 35$
Upper limit

= 46

$= 46$

The mid-value of

20 - 30

$20-30$ is _____

0%
$23$
0%
$22$
0%
$25$
0%
$26$

Explanation

Mid value

= \frac{Lower Limit + Upper limit}{2}

$= \dfrac{\text{Lower Limit} + \text{Upper limit}}{2}$
Mid Value

= \frac{20 + 30}{2}

$= \dfrac{20 + 30}{2}$
Mid Value

= 25

$= 25$

The mean of

x, y, z

$x, y, z$ is

y

$y$ , then

x + z =

$x+z =$

0%
$y$
0%
$2y$
0%
$3y$
0%
$zy$

Explanation

The question tells us that the mean of

x, y

$x, y$ and

z

$z$ is

y

$y$ .

i.e.

\frac{x + y + z}{3} = y

$\dfrac {x+y+z}{3} =y$

i.e.

x + z = 3 y - y

$x+z=3y-y$

\to x + z = 2 y

$\rightarrow x+z=2y$

Consider the data :

2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2.

$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2.$ The frequency of

2

$2$ is ..............

0%
$3$
0%
$4$
0%
$5$
0%
$6$

Explanation

In the data series:

2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2

$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2$

2

$2$ occurs

5

$5$ times, hence its frequency is

5

$5$

The mid-point of a class intervals is called:

0%
class interval
0%
class mark
0%
class limit
0%
upper limit

The formula

\frac{U p p e r c l a s s l i m i t + L o w e r c l a s s l i m i t}{2}

$\dfrac{Upper\ class\ limit + Lower\ class\ limit }{2}$ is known as

0%
Class mark
0%
Class interval
0%
Upper limit
0%
Lower limit

Explanation

True. Class Mark is given by

\frac{U p p e r c l a s s l i m i t + L o w e r c l a s s l i m i t}{2}

$\dfrac{Upper class limit + Lower class limit }{2}$

A class interval of a data has

15

$15$ as the lower limit and

25

$25$ as the size then the class mark is :

0%
$26.5$
0%
$27$
0%
$27.5$
0%
None of these

Explanation

Given,
Lower limit

= 15

$= 15$
Size of class interval

= 25

$= 25$
Upper limit

= lower limit + size = 15 + 25

$= \text{lower limit }+ \text{ size} = 15 + 25$ =

40

$40$
Class mark is calculated from mean of lower and upper limit.

Class mark

= \frac{lower limit + upper limit}{2}

$=\dfrac{ \text{lower limit }+ \text{upper limit }}{2}$

= \frac{15 + 40}{2}

$= \dfrac{15 + 40}{2}$

= 27.5

$=27.5$

0 - 10, 10 - 20, 20 - 30 . . .

$0-10, 10-20, 20-30 ...$ so on are the classes, the lower boundary of the class

20 - 30

$20-30$ is _____

0%
$20$
0%
$21$
0%
$18$
0%
$22$

Explanation

Lower boundary means the lower limit of the class interval.
The lower limit of

20 - 30

$20 - 30$ is

20

$20$ .

Which one of the following groups has different class size from others?

0%
$120 - 125$
0%
$243 - 249$
0%
$141.5 - 146.5$
0%
$315.5 - 320.5$

Explanation

Class size

=

$=$ Upper limit

-

$-$ lower limit

All other classes have a class size

= 5

$= 5$ except,

243 - 249

$243-249$ which has a size of

6

$6$

Lower class limit of

15 - 18

$15 -18$ is _____

0%
$15$
0%
$18$
0%
$15$ or $18$
0%
None of these

Explanation

We need to find lower class limit of

15 - 18

$15-18$ .

Thus,

15

$15$ is lesser in

(15 - 18)

$(15-18)$ , so answer is

15

$15$ .

The number of times a particular item occurs in a class interval is called its:

0%
mean
0%
frequency
0%
cumulative frequency
0%
none of these

Explanation

The number of times a particular item is occurs in a class interval is called its frequency.

For, example the data set is

1, 2, 3, 3, 5, 6, 12, 14, 23, 12, 22, 16, 18

$1,2,3,3,5,6,12,14,23,12,22,16,18$ . In the data set the frequency of the class interval

10 - 15

$10-15$ is

3

$3$ i.e., the values in the class interval are

12, 14, 12

$12,14,12$

In the class interval

35 - 46

$35 - 46$ , the lower limit is _____

0%
$35$
0%
$46$
0%
Can't determine
0%
None of these

Explanation

For the class interval

35 - 46

$35 - 46$ , the lower limit is

35

$35$ and upper limit is

46

$46$

In an examination,

10

$10$ students scored the following marks in Mathematics:

35, 19, 28, 32, 63, 02, 47, 31, 13, 98

$35, 19, 28, 32, 63, 02, 47, 31, 13, 98$ . Its range is

0%
$2$
0%
$96$
0%
$98$
0%
$50$

Explanation

Range

=

$=$ Maximum value of the variable

-

$-$ Minimum value of the variable

= 98 - 2 = 96

$= 98 - 2 = 96$

The mean of

x + 3, x + 5, x + 7, x + 9

$x + 3, x + 5, x + 7, x + 9$ and

x + 11

$x + 11$ is

0%
$2x+7$
0%
$x+8$
0%
$x+7$
0%
None of these

Explanation

The observations are :

x + 3, x + 5, x + 7, x + 9, x + 11

$x+3,x+5,x+7,x+9, x+11$
Mean =

\frac{s u m}{n u m b e r o f o b s e r v a t i o n s}

$\dfrac{sum}{number \quad of \quad observations}$ =

\frac{x + 3, x + 5, x + 7, x + 9, x + 11}{5}

$\dfrac{x+3,x+5,x+7,x+9, x+11}{5}$ =

\frac{5 x + 35}{5} = x + 7

$\dfrac{5x + 35}{5} = x + 7$

What is the difference of frequencies of the intervals 30-40 and 40-50 ?

0%
$5$
0%
$20$
0%
$15$
0%
$25$

Explanation

\Rightarrow

$\Rightarrow$ In given histogram we can see, frequencies of the class intervals

30 - 40

$30-40$ and

40 - 50

$40-50$ are

25

$25$ and

10

$10$ .

\Rightarrow

$\Rightarrow$ Difference of frequencies of the intervals

30 - 40

$30-40$ and

40 - 50

$40-50$

= 25 - 10 = 15

$=25-10=15$

The range of the data

7, 13, 6, 25, 18, 20, 16

$7, 13, 6, 25, 18, 20 , 16$ is _____

0%
$13$
0%
$19$
0%
$20$
0%
$25$

Explanation

The data is:

7, 13, 6, 25, 18, 20, 16

$7,13,6,25,18,20,16$
Lowest value

= 6

$= 6$
highest value

= 25

$= 25$
Range

=

$=$ Highest Value

-

$-$ Lowest value

= 25 - 6 = 19

$= 25 - 6 = 19$

Construct a frequency distribution table for the data, taking class-intervals 4-6, 6-8, ............., 14-16.

11.5
4.5
7.4
9.8
4.6
14.2
6.6
15.5

6.3
6
5.3
8.25
6.4
15.3
4.3
14.4

7.8
8.3
8.4
6.5
8.9
11.7
4.7
12.2

9.2
12.5
15.2
5.8
10.8
9.9
9.4
7.7

10.5
15.8
8.9
10.5
12.7
8.8
10.1
5.5

C.I.	Tally Marks.	Frequency
4-6 6-8 8-10 10-12 12-14 14-16	${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: {\|\|\|\|}\! \! \! \! \! \! {\diagdown}$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$ \|\|\| ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$	7 8 10 6 3 6

C.I.	Tally Marks.	Frequency
4-6 6-8 8-10 10-12 12-14 14-16	${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: {\|\|\|\|}\! \! \! \! \! \! {\diagdown}$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$ \|\|\| ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$	7 10 8 6 3 6

C.I.	Tally Marks.	Frequency
4-6 6-8 8-10 10-12 12-14 14-16	${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: {\|\|\|\|}\! \! \! \! \! \! {\diagdown}$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$ \|\|\| ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$	6 8 10 8 3 3

0%
None of these

Explanation

Crete class interval in

$4 - 6$ ,

$6 - 8$ and so on and count the number of terms in between these intervals:

C.I.	Tally Marks.	Frequency
4-6 6-8 8-10 10-12 12-14 14-16	${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|\|\|$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: {\|\|\|\|}\! \! \! \! \! \! {\diagdown}$ ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$ \|\|\| ${\|\|\|\|}\! \! \! \! \! \! {\diagdown}\: \|$	7 8 10 6 3 6

The difference between the greatest and the least value of the observations is known as

0%
M.D.
0%
S.D.
0%
Range
0%
Variance

Explanation

The difference between the greatest and the least value of the observations is defined as

$Range$ .

How many articles have cost Rs.

$50$ ?

Cost (in Rs.) :	$10 - 20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$
Frequency :	$22$	$18$	$35$	$115$	$38$	$22$

0%
$22$
0%
$38$
0%
$35$
0%
$115$

Explanation

The frequency distribution table is -

Cost (in Rs.) Class Interval	No. of articles(freq)
$10$ to $20$	$22$
$20$ to $30$	$18$
$30$ to $40$	$35$
$40$ to $50$	$115$
$50$ to $60$	$38$
$60$ to $70$	$22$

The articles which cost Rs.

$50 = 38$

Class mark of a class is obtained by using

0%
Upper limit
0%
$\dfrac {1}{2}$ [Upper limit - Lower limit]
0%
$\dfrac {1}{2}$ [Upper limit + lower limit]
0%
$\dfrac {1}{2}$ [Upper limit + Lower limit] $-1$

Explanation

Class mark is the mean of the upper limit and lower limit of the class.
i.e. Class Mark

$=\dfrac {1}{2}$ [upper limit + lower limit]

Hence, option C is correct.

CBSE Questions for Class 9 Maths Statistics Quiz 1 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Statistics Quiz 1 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

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