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CBSE Questions for Class 9 Maths Statistics Quiz 3 - MCQExams.com
CBSE
Class 9 Maths
Statistics
Quiz 3
How many students have heights between $$180 - 200$$?
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0%
$$10$$
0%
$$24$$
0%
$$15$$
0%
$$7$$
Explanation
From the histogram, the class width of number of students:
$$120 - 140$$ is $$4$$
$$140 - 160$$ is $$10$$
$$160 - 180$$ is $$24$$
$$180 - 200$$ is $$10$$
$$200 - 220$$ is $$15$$
$$220 - 240$$ is $$7$$.
Therefore, $$10$$ is the number of student's height between the interval $$180-200$$.
Hence, option $$A$$ is correct.
Find the class interval with
lowest frequency
.
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0%
$$318-335$$
0%
$$354-371$$
0%
$$372-389$$
0%
$$426-443$$
Explanation
In the given data, we observe the lowest frequency
$$=1$$
So, the class interval for the lowest frequency $$1$$ is $$426-443.$$
Fill in the blank$$:$$
$$___________$$ frequency is defined as a running total of frequencies.
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0%
Variable
0%
Accelerate
0%
Data
0%
Cumulative
Explanation
Cumulative frequency is defined as a running total of frequencies.
"The frequency is the no. of times an event occurs within a given scenario. Cumulative frequency is defined as the running of frequencies. It is the sum of all the previous frequencies up to the current point.
D) Cumulative
The following frequency distribution gives the monthly consumption of electricity of $$68$$ consumers of a locality. In which class interval, the number of consumers are the highest?
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0%
$$105-125$$
0%
$$125-145$$
0%
$$145-165$$
0%
$$185-205$$
Explanation
The
highest
number of consumers are at the class interval $$125-145.$$
So, the highest frequency is $$20$$ at the interval $$125-145.$$
How many ponds had $$20-39$$ ducks?
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0%
$$25$$
0%
$$30$$
0%
$$20$$
0%
$$15$$
Explanation
From the histogram, the class width of number of ducks:
$$0 - 19 = 30$$ number of ponds.
$$20 - 39 = 20$$ number of ponds.
$$40 - 59 = 25$$ number of ponds.
$$60 - 79 = 10$$ number of ponds.
$$80 - 99 = 20$$ number of ponds.
$$100 - 119 = 15$$ number of ponds.
Therefore, $$20$$ ponds had $$20-39$$ number of ducks.
Hence, option $$C$$ is correct.
12
24
36
48
60
72
24
48
60
72
50
30
50
45
50
75
50
34
The number of students in a quiz competition scores are in the table. How many students scored $$50$$ marks?
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0%
$$4$$
0%
$$5$$
0%
$$8$$
0%
$$3$$
Explanation
Scores
Frequency
12
1
24
2
30
1
34
1
36
1
45
1
48
2
50
4
60
2
72
2
75
1
So, there are $$4$$ students scored $$50$$ marks.
The annual maintenance cost of a machine in a factory over a seven years period is represented in the histogram.
In which year the maintenance is very low?
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0%
$$1995-1996$$
0%
$$1996-1997$$
0%
$$1997-1998$$
0%
$$1998-1999$$
Explanation
From the histogram, the maintenance cost in the year:
$$1995-1996$$ is Rs. $$2000$$
$$1996-1997$$ is Rs. $$3000$$
$$1997-1998$$ is Rs. $$1500$$
$$1998-1999$$ is Rs. $$2500$$
$$1999-2000$$ is Rs. $$4850$$
$$2000-2001$$ is Rs. $$5000$$
$$2001-2002$$ is Rs. $$7200$$.
Then clearly, the maintenance is very low in the year $$1997-1998$$.
Hence, option $$C$$ is correct.
In which hour interval, the children are $$55$$?
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0%
$$0-10$$
0%
$$10-20$$
0%
$$20-30$$
0%
$$30-40$$
Explanation
From the histogram,
The number of children entered during $$0-10$$ hours $$= 45$$
The number of children entered during $$10-20$$ hours $$= 55$$
The number of children entered during $$20-30$$ hours $$= 15$$
The number of children entered during $$30-40$$ hours $$= 25$$
The number of children entered during $$40-50$$ hours $$= 85$$
The number of children entered during $$50-60$$ hours $$= 10$$.
Therefore,
$$55$$ children entered into the library between the interval $$10-20$$.
Hence, option $$B$$ is correct.
Which is the lowest ticket collected by Judah?
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0%
$$5$$
0%
$$11-13$$
0%
$$14-16$$
0%
$$10$$
Explanation
The lowest height of the bar represents the lowest ticket collected by Judah i.e. $$5$$.
Hence, the answer is $$5$$.
Find the total number of tickets.
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0%
$$60$$
0%
$$80$$
0%
$$90$$
0%
$$100$$
Explanation
The total number of tickets $$= 25 + 15 + 10 + 5 + 20 + 25 = 100$$
Rahul made a frequency table of height for his students. In which class interval, the number of students is less?
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0%
$$5-10$$
0%
$$10-15$$
0%
$$15-20$$
0%
$$35-40$$
How many tickets were collected in the interval $$11-13$$?
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0%
$$25$$
0%
$$15$$
0%
$$10$$
0%
$$5$$
Explanation
Since the height of the bar in the interval $$11-13$$ is $$5$$.
So, $$5$$ tickets were collected in the interval $$11-13$$.
Hence, option D is correct.
Find the number of children in the interval $$20-30$$ hours?
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0%
$$10$$
0%
$$15$$
0%
$$25$$
0%
$$45$$
Explanation
From the histogram,
The number of children entered during $$0-10$$ hours $$= 45$$
The number of children entered during $$10-20$$ hours $$= 55$$
The number of children entered during $$20-30$$ hours $$= 15$$
The number of children entered during $$30-40$$ hours $$= 25$$
The number of children entered during $$40-50$$ hours $$= 85$$
The number of children entered during $$50-60$$ hours $$= 10$$.
The number of children entered into the library in $$20-30$$ hours $$= 15$$
.
Hence, option $$B$$ is correct.
The annual maintenance cost of a machine in a factory over a seven years period is represented in the histogram.
In which year the maintenance cost is $$2500$$?
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0%
$$1998-1999$$
0%
$$2000-2001$$
0%
$$2001-2002$$
0%
$$1995-1996$$
Explanation
From the histogram, the maintenance cost in the year:
$$1995-1996$$ is Rs. $$2000$$
$$1996-1997$$ is Rs. $$3000$$
$$1997-1998$$ is Rs. $$1500$$
$$1998-1999$$ is Rs. $$2500$$
$$1999-2000$$ is Rs. $$4850$$
$$2000-2001$$ is Rs. $$5000$$
$$2001-2002$$ is Rs. $$7200$$.
Then, t
he maintenance cost is Rs. $$2500$$ in the year $$1998-1999$$.
Hence, option $$A$$ is correct.
In which frequency the number of tickets were same?
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0%
$$2-4$$ and $$17-19$$
0%
$$5-7$$ and $$8-10$$
0%
$$8-10$$ and $$11-13$$
0%
$$14-16$$ and $$17-19$$
Explanation
The number of tickets are same in the frequency $$2-4$$ and $$17-19$$.
Judah recorded the number of football tickets collected by his friends, on the histogram.
What is the total number of tickets collected by Judah between the interval $$8-10$$?
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0%
$$5$$
0%
$$15$$
0%
$$10$$
0%
$$40$$
Explanation
The total number of tickets collected by Judah between the interval $$8-10 = 10 $$
From the graph, find the number of tickets collected between the interval $$14-16$$.
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0%
$$25$$
0%
$$20$$
0%
$$15$$
0%
$$10$$
Explanation
From the graph, the number of tickets collected between the interval $$14-16 $$ is $$20$$.
How many music directors required to create $$(9-10)$$ song?
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0%
$$8$$
0%
$$5$$
0%
$$4$$
0%
$$6$$
Explanation
By looking the graph, we get $$8$$ music directors required to create $$(9-10)$$ song
In the graph you can find the takings of a chocolate bar for $$8$$ months. Answer the following
question:
In which two months, $$40000$$ chocolate bars are taken out?
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0%
Jan and Feb
0%
Feb and May
0%
May and Apr
0%
Jun and Jul
Explanation
From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$
.
Clearly, we can say Feb and May months shows the same number of chocolates, i.e. $$40000$$ chocolates.
So, in the months of Feb and May, $$40000$$ chocolate bars are taken out.
Hence, option $$B$$ is correct.
Calculate the number of songs made during the interval $$9-10$$.
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0%
$$14$$
0%
$$6$$
0%
$$8$$
0%
$$10$$
Explanation
By looking the graph, we get the number of songs made during the interval $$9-10$$ is $$8$$.
In which interval the number of music directors made more songs?
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0%
$$1-2$$
0%
$$3-4$$
0%
$$5-6$$
0%
$$7-8$$
Explanation
The tallest bar represents the more songs made by the music director between the interval
5
−
6
5−6
.
How many songs were made between the interval $$3-4$$?
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0%
$$20$$
0%
$$18$$
0%
$$6$$
0%
$$14$$
Explanation
By looking the graph, we get the number of songs made between the interval $$3-4$$ is $$18$$.
Upto $$6$$ songs are totally made by how many music directors?
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0%
$$20$$
0%
$$18$$
0%
$$10$$
0%
$$50$$
Explanation
$$6$$ songs made by total number of music directors $$= 20 + 18 + 12 = 50$$
How many students got more than $$70$$ marks?
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0%
$$16$$
0%
$$8$$
0%
$$47$$
0%
$$18$$
Explanation
From the given frequency polygon, we get the students who got more than $$70$$ marks $$= 16 + 18 + 13 = 47$$.
Hence, option $$C$$ is correct.
Mean of $$40$$ observations was given as $$160$$.It was detected that $$125$$ was misread as $$160$$. Find the correct mean.
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0%
$$158$$
0%
$$169$$
0%
$$159$$
0%
$$161$$
Explanation
Formula used:
$$Arithmetic\ mean= \dfrac{Sum\ of\ given\ numbers}{Total\ numbers}$$
Sine, number of observations$$,n=40$$
Mean$$=160$$ (initial wrong mean)
Incorrected sum$$=n \times u=40 \times 160=6400$$
Now $$125$$ was read as $$165$$, so
Corrected sum $$=6400-165+125=6360$$
$$\therefore$$ Corrected mean $$=\dfrac{6360}{40} =159$$
Length of the class $$11-20$$ is ______.
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0%
$$9$$
0%
$$10$$
0%
$$11$$
0%
$$20$$
Explanation
Length of a class is given by $$b-a$$, where $$b$$ and $$a$$ are the upper and lower limits of the class respectively.
$$\therefore$$ length $$=20-11=9$$
Option $$A$$ is correct.
A factory kept track of the number of broken plates per shipment last month. Which range of broken plates per shipment occurred more frequently?
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0%
$$10-19$$
0%
$$40-49$$
0%
$$30-39$$
0%
$$20-29$$
Explanation
From the histogram, the
number of shipment per range of broken plates:
$$0-9$$ is $$8$$
$$10-19$$ is $$7$$
$$20-29$$ is $$1$$
$$30-39$$ is $$6$$
$$40-49$$ is $$10$$
$$50-59$$ is $$6$$
$$60-69$$ is $$7$$
$$70-79$$ is $$7$$.
The range of broken plates per shipment occurred more frequently $$= 40-49$$, i.e. $$10$$ (The longest bar has the most frequency).
Hence, option $$B$$ is correct.
Find the number of songs made during the interval $$5-6$$.
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0%
$$20$$
0%
$$15$$
0%
$$6$$
0%
$$8$$
Explanation
The height of the bar represents the number of songs.
So, $$20$$ songs were made during the interval $$5-6$$.
Find the average of the expressions $$2x+4, 5x-1$$ and $$-x+3$$.
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0%
$$x+2$$
0%
$$x-2$$
0%
$$2x+2$$
0%
$$2x-2$$
Explanation
Average of the expression $$=$$ $$\dfrac{sum \quad of \quad expression }{total \quad no. \quad of \quad expressions}$$
$$\Rightarrow \dfrac{2x+4+5x-1-x+3}{3}$$
$$\Rightarrow \dfrac{6x+6}{3}$$
$$\Rightarrow \dfrac{3(2x+2)}{3}=2x+2$$
$$12-n, 12, 12+n$$
What is the average (arithmetic mean) of the $$3$$ quantities in the list above?
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0%
$$4$$
0%
$$12$$
0%
$$18$$
0%
$$4+\dfrac{n}{3}$$
0%
$$12+\dfrac{n}{3}$$
Explanation
Given $$3$$ Quantities:
$$12$$ $$-$$ $$n$$, $$12$$, $$12$$ $$+$$ $$n$$
Average of the above $$3$$ Quantities $$=$$ $$\dfrac {\text{Sum of the above}\: 3\: \text{Quantities}} {\text{Number of Quantities}} $$
$$=$$ $$\dfrac { 12 \space - \space n \space + \space 12 \space + \space 12 \space + \space n }{3}$$
$$=$$ $$\dfrac {12 \times 3}{3}$$
$$=$$ $$12$$
Therefore, average of the Quantities listed above is $$12$$.
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