Explanation
Hint: Here we should know about Newton’s second law of motion & third equation of motion
Solution:
Step1: Find acceleration of ship ‘a’
According to Newton’s second law,
$$F = ma$$
Where, m=Mass & a=Acceleration
So, $$a = \dfrac{F}{m}$$
$$ \Rightarrow \dfrac{{5 \times {{10}^4}}}{{3 \times {{10}^7}}}$$…..(As force & mass are given)
$$a = \dfrac{5}{3} \times {10^{ - 3}}$$ m/s2
Step2: Find speed of the ship after moving distance of 3m
According Newton’s third law of motion,
$${v^2} = {u^2} + 2as$$
v=Final velocity, u=Initial velocity, a=Acceleration & s=Displacement
$$ \Rightarrow {0^2} + 2 \times \dfrac{5}{3} \times {10^{ - 3}} \times 3$$
$$ \Rightarrow \dfrac{{10}}{3} \times {10^{ - 3}} \times 3$$
$$ \Rightarrow {10^{ - 2}}$$m/s
$$ \Rightarrow 0.1$$m/s
Hence option (C) is correct.
According to newton second law
$$F=ma$$
So
Since there is no acceleration of body , $$a=0$$ hence $$F=0$$ therefore sum of all forces acting on body must be equal to zero. Therefore sum of pushing force, weight of toy and normal reaction by ground and friction by ground must be equal to zero.
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