Explanation
Body $$1$$:
Initial Speed $$ = 0$$
Acceleration $$ = 9.8 \,ms^{-2} $$
Time $$ = 2 $$ seconds
Now, we know that,
$$ s = ut + \dfrac{1}{2} at^2 $$
So, $$ s_1 = \dfrac{1}{2} \times 9.8 \times 4 $$
$$ s_1 = 19.6 \, m $$
Body $$2$$:
Initial Speed $$ = 0 $$
Acceleration $$ = 9.8\, ms^{-2} $$
A black paper absorbs light of all the colours and reflects none.
$$ \therefore 0.04g-(0.03a + 0.03g) = 0.04a$$
$$0.01g=0.07a$$ or $$a=\frac{0.098}{.07}$$ or $$ a = 1.4$$
The acceleration of the system $$ a = 1.4 m/s^2$$
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