Explanation
For balloon, distance traveled by it in 8 sec,
$$s = ut + \dfrac {1}{2} gt^{2} $$ where $$u=0$$
$$s$$$$=$$$$\dfrac{1}{2}\times \dfrac{g}{8} t^2$$$$=4g$$
So, time taken by stone,
$$s = ut + \dfrac {1}{2} gt^2$$
$$4g = \dfrac {1}{2} gt^2$$ at this height the velocity of stone will be zero
$$t^2 = \sqrt 8 \Rightarrow t = 2 \sqrt 2\ s.$$
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