Explanation
3 right angles $$ = 3 \times {90}^{0} = {270}^{0} $$
Area of a sector of a circle of radius 'r' and angle Area of a sector = $$\dfrac { \theta }{ 360 } \pi {r}^{2}$$
Hence, area of the sector of the circle of radius $$ 7 $$ cm and angle $${ 270 }^{ 0 } = \dfrac { 270 }{ 360 } \times \dfrac { 22 }{ 7 } \times 7 \times7\quad = 115.5 {cm}^{2} $$
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